leetcode-problemset/leetcode-cn/originData/count-collisions-on-a-road.json

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        "question": {
            "questionId": "2317",
            "questionFrontendId": "2211",
            "categoryTitle": "Algorithms",
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            "title": "Count Collisions on a Road",
            "titleSlug": "count-collisions-on-a-road",
            "content": "<p>There are <code>n</code> cars on an infinitely long road. The cars are numbered from <code>0</code> to <code>n - 1</code> from left to right and each car is present at a <strong>unique</strong> point.</p>\n\n<p>You are given a <strong>0-indexed</strong> string <code>directions</code> of length <code>n</code>. <code>directions[i]</code> can be either <code>&#39;L&#39;</code>, <code>&#39;R&#39;</code>, or <code>&#39;S&#39;</code> denoting whether the <code>i<sup>th</sup></code> car is moving towards the <strong>left</strong>, towards the <strong>right</strong>, or <strong>staying</strong> at its current point respectively. Each moving car has the <strong>same speed</strong>.</p>\n\n<p>The number of collisions can be calculated as follows:</p>\n\n<ul>\n\t<li>When two cars moving in <strong>opposite</strong> directions collide with each other, the number of collisions increases by <code>2</code>.</li>\n\t<li>When a moving car collides with a stationary car, the number of collisions increases by <code>1</code>.</li>\n</ul>\n\n<p>After a collision, the cars involved can no longer move and will stay at the point where they collided. Other than that, cars cannot change their state or direction of motion.</p>\n\n<p>Return <em>the <strong>total number of collisions</strong> that will happen on the road</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> directions = &quot;RLRSLL&quot;\n<strong>Output:</strong> 5\n<strong>Explanation:</strong>\nThe collisions that will happen on the road are:\n- Cars 0 and 1 will collide with each other. Since they are moving in opposite directions, the number of collisions becomes 0 + 2 = 2.\n- Cars 2 and 3 will collide with each other. Since car 3 is stationary, the number of collisions becomes 2 + 1 = 3.\n- Cars 3 and 4 will collide with each other. Since car 3 is stationary, the number of collisions becomes 3 + 1 = 4.\n- Cars 4 and 5 will collide with each other. After car 4 collides with car 3, it will stay at the point of collision and get hit by car 5. The number of collisions becomes 4 + 1 = 5.\nThus, the total number of collisions that will happen on the road is 5. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> directions = &quot;LLRR&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\nNo cars will collide with each other. Thus, the total number of collisions that will happen on the road is 0.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= directions.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>directions[i]</code> is either <code>&#39;L&#39;</code>, <code>&#39;R&#39;</code>, or <code>&#39;S&#39;</code>.</li>\n</ul>\n",
            "translatedTitle": "统计道路上的碰撞次数",
            "translatedContent": "<p>在一条无限长的公路上有 <code>n</code> 辆汽车正在行驶。汽车按从左到右的顺序按从 <code>0</code> 到 <code>n - 1</code> 编号，每辆车都在一个 <strong>独特的</strong> 位置。</p>\n\n<p>给你一个下标从 <strong>0</strong> 开始的字符串 <code>directions</code> ，长度为 <code>n</code> 。<code>directions[i]</code> 可以是 <code>'L'</code>、<code>'R'</code> 或 <code>'S'</code> 分别表示第 <code>i</code> 辆车是向 <strong>左</strong> 、向 <strong>右</strong> 或者 <strong>停留</strong> 在当前位置。每辆车移动时 <strong>速度相同</strong> 。</p>\n\n<p>碰撞次数可以按下述方式计算：</p>\n\n<ul>\n\t<li>当两辆移动方向&nbsp;<strong>相反</strong>&nbsp;的车相撞时，碰撞次数加 <code>2</code> 。</li>\n\t<li>当一辆移动的车和一辆静止的车相撞时，碰撞次数加 <code>1</code> 。</li>\n</ul>\n\n<p>碰撞发生后，涉及的车辆将无法继续移动并停留在碰撞位置。除此之外，汽车不能改变它们的状态或移动方向。</p>\n\n<p>返回在这条道路上发生的 <strong>碰撞总次数</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>directions = \"RLRSLL\"\n<strong>输出：</strong>5\n<strong>解释：</strong>\n将会在道路上发生的碰撞列出如下：\n- 车 0 和车 1 会互相碰撞。由于它们按相反方向移动，碰撞数量变为 0 + 2 = 2 。\n- 车 2 和车 3 会互相碰撞。由于 3 是静止的，碰撞数量变为 2 + 1 = 3 。\n- 车 3 和车 4 会互相碰撞。由于 3 是静止的，碰撞数量变为 3 + 1 = 4 。\n- 车 4 和车 5 会互相碰撞。在车 4 和车 3 碰撞之后，车 4 会待在碰撞位置，接着和车 5 碰撞。碰撞数量变为 4 + 1 = 5 。\n因此，将会在道路上发生的碰撞总次数是 5 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>directions = \"LLRR\"\n<strong>输出：</strong>0\n<strong>解释：</strong>\n不存在会发生碰撞的车辆。因此，将会在道路上发生的碰撞总次数是 0 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= directions.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>directions[i]</code> 的值为 <code>'L'</code>、<code>'R'</code> 或 <code>'S'</code></li>\n</ul>\n",
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