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leetcode-problemset/leetcode-cn/originData/count-asterisks.json
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"question": {
"questionId": "2401",
"questionFrontendId": "2315",
"categoryTitle": "Algorithms",
"boundTopicId": 1621162,
"title": "Count Asterisks",
"titleSlug": "count-asterisks",
"content": "<p>You are given a string <code>s</code>, where every <strong>two</strong> consecutive vertical bars <code>&#39;|&#39;</code> are grouped into a <strong>pair</strong>. In other words, the 1<sup>st</sup> and 2<sup>nd</sup> <code>&#39;|&#39;</code> make a pair, the 3<sup>rd</sup> and 4<sup>th</sup> <code>&#39;|&#39;</code> make a pair, and so forth.</p>\n\n<p>Return <em>the number of </em><code>&#39;*&#39;</code><em> in </em><code>s</code><em>, <strong>excluding</strong> the </em><code>&#39;*&#39;</code><em> between each pair of </em><code>&#39;|&#39;</code>.</p>\n\n<p><strong>Note</strong> that each <code>&#39;|&#39;</code> will belong to <strong>exactly</strong> one pair.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;l|*e*et|c**o|*de|&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The considered characters are underlined: &quot;<u>l</u>|*e*et|<u>c**o</u>|*de|&quot;.\nThe characters between the first and second &#39;|&#39; are excluded from the answer.\nAlso, the characters between the third and fourth &#39;|&#39; are excluded from the answer.\nThere are 2 asterisks considered. Therefore, we return 2.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;iamprogrammer&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> In this example, there are no asterisks in s. Therefore, we return 0.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;yo|uar|e**|b|e***au|tifu|l&quot;\n<strong>Output:</strong> 5\n<strong>Explanation:</strong> The considered characters are underlined: &quot;<u>yo</u>|uar|<u>e**</u>|b|<u>e***au</u>|tifu|<u>l</u>&quot;. There are 5 asterisks considered. Therefore, we return 5.</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code> consists of lowercase English letters, vertical bars <code>&#39;|&#39;</code>, and asterisks <code>&#39;*&#39;</code>.</li>\n\t<li><code>s</code> contains an <strong>even</strong> number of vertical bars <code>&#39;|&#39;</code>.</li>\n</ul>\n",
"translatedTitle": "统计星号",
"translatedContent": "<p>给你一个字符串&nbsp;<code>s</code>&nbsp;,每&nbsp;<strong>两个</strong>&nbsp;连续竖线&nbsp;<code>'|'</code>&nbsp;为 <strong>一对</strong>&nbsp;。换言之,第一个和第二个&nbsp;<code>'|'</code>&nbsp;为一对,第三个和第四个&nbsp;<code>'|'</code>&nbsp;为一对,以此类推。</p>\n\n<p>请你返回 <strong>不在</strong> 竖线对之间,<code>s</code>&nbsp;中&nbsp;<code>'*'</code>&nbsp;的数目。</p>\n\n<p><strong>注意</strong>,每个竖线&nbsp;<code>'|'</code>&nbsp;都会 <strong>恰好</strong>&nbsp;属于一个对。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre><b>输入:</b>s = \"l|*e*et|c**o|*de|\"\n<b>输出:</b>2\n<b>解释:</b>不在竖线对之间的字符加粗加斜体后,得到字符串:\"<strong><em>l</em></strong>|*e*et|<strong><em>c**o</em></strong>|*de|\" 。\n第一和第二条竖线 '|' 之间的字符不计入答案。\n同时第三条和第四条竖线 '|' 之间的字符也不计入答案。\n不在竖线对之间总共有 2 个星号,所以我们返回 2 。</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre><b>输入:</b>s = \"iamprogrammer\"\n<b>输出:</b>0\n<b>解释:</b>在这个例子中s 中没有星号。所以返回 0 。\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre><b>输入:</b>s = \"yo|uar|e**|b|e***au|tifu|l\"\n<b>输出:</b>5\n<b>解释:</b>需要考虑的字符加粗加斜体后:\"<strong><em>yo</em></strong>|uar|<strong><em>e**</em></strong>|b|<strong><em>e***au</em></strong>|tifu|<strong><em>l</em></strong>\" 。不在竖线对之间总共有 5 个星号。所以我们返回 5 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 1000</code></li>\n\t<li><code>s</code>&nbsp;只包含小写英文字母,竖线&nbsp;<code>'|'</code>&nbsp;和星号&nbsp;<code>'*'</code>&nbsp;。</li>\n\t<li><code>s</code>&nbsp;包含 <strong>偶数</strong>&nbsp;个竖线&nbsp;<code>'|'</code> 。</li>\n</ul>\n",
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"If we are not in between a pair of | and there is a *, increment the answer by 1."
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