leetcode-problemset/leetcode-cn/originData/compare-version-numbers.json

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            "categoryTitle": "Algorithms",
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            "title": "Compare Version Numbers",
            "titleSlug": "compare-version-numbers",
            "content": "<p>Given two version numbers,&nbsp;<code>version1</code> and <code>version2</code>, compare them.</p>\n\n<ul>\n</ul>\n\n<p>Version numbers consist of <strong>one or more revisions</strong> joined by a dot&nbsp;<code>&#39;.&#39;</code>. Each revision&nbsp;consists of <strong>digits</strong>&nbsp;and may contain leading <strong>zeros</strong>. Every revision contains <strong>at least one character</strong>. Revisions are <strong>0-indexed from left to right</strong>, with the leftmost revision being revision 0, the next revision being revision 1, and so on. For example&nbsp;<code>2.5.33</code>&nbsp;and&nbsp;<code>0.1</code>&nbsp;are valid version numbers.</p>\n\n<p>To compare version numbers, compare their revisions in <strong>left-to-right order</strong>. Revisions are compared using their&nbsp;<strong>integer value ignoring any leading zeros</strong>. This means that revisions&nbsp;<code>1</code>&nbsp;and&nbsp;<code>001</code>&nbsp;are considered&nbsp;<strong>equal</strong>. If a version number does not specify a revision at an index, then&nbsp;<strong>treat the revision as&nbsp;<code>0</code></strong>. For example, version&nbsp;<code>1.0</code> is less than version&nbsp;<code>1.1</code>&nbsp;because their revision 0s are the same, but their revision 1s are&nbsp;<code>0</code>&nbsp;and&nbsp;<code>1</code>&nbsp;respectively, and&nbsp;<code>0 &lt; 1</code>.</p>\n\n<p><em>Return the following:</em></p>\n\n<ul>\n\t<li>If <code>version1 &lt; version2</code>, return <code>-1</code>.</li>\n\t<li>If <code>version1 &gt; version2</code>, return <code>1</code>.</li>\n\t<li>Otherwise, return <code>0</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> version1 = &quot;1.01&quot;, version2 = &quot;1.001&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> Ignoring leading zeroes, both &quot;01&quot; and &quot;001&quot; represent the same integer &quot;1&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> version1 = &quot;1.0&quot;, version2 = &quot;1.0.0&quot;\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> version1 does not specify revision 2, which means it is treated as &quot;0&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> version1 = &quot;0.1&quot;, version2 = &quot;1.1&quot;\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> version1&#39;s revision 0 is &quot;0&quot;, while version2&#39;s revision 0 is &quot;1&quot;. 0 &lt; 1, so version1 &lt; version2.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= version1.length, version2.length &lt;= 500</code></li>\n\t<li><code>version1</code> and <code>version2</code>&nbsp;only contain digits and <code>&#39;.&#39;</code>.</li>\n\t<li><code>version1</code> and <code>version2</code>&nbsp;<strong>are valid version numbers</strong>.</li>\n\t<li>All the given revisions in&nbsp;<code>version1</code> and <code>version2</code>&nbsp;can be stored in&nbsp;a&nbsp;<strong>32-bit integer</strong>.</li>\n</ul>\n",
            "translatedTitle": "比较版本号",
            "translatedContent": "<p>给你两个版本号 <code>version1</code> 和 <code>version2</code> ，请你比较它们。</p>\n\n<p>版本号由一个或多个修订号组成，各修订号由一个 <code>'.'</code> 连接。每个修订号由 <strong>多位数字</strong> 组成，可能包含 <strong>前导零</strong> 。每个版本号至少包含一个字符。修订号从左到右编号，下标从 0 开始，最左边的修订号下标为 0 ，下一个修订号下标为 1 ，以此类推。例如，<code>2.5.33</code> 和 <code>0.1</code> 都是有效的版本号。</p>\n\n<p>比较版本号时，请按从左到右的顺序依次比较它们的修订号。比较修订号时，只需比较 <strong>忽略任何前导零后的整数值</strong> 。也就是说，修订号 <code>1</code> 和修订号 <code>001</code> <strong>相等 </strong>。如果版本号没有指定某个下标处的修订号，则该修订号视为 <code>0</code> 。例如，版本 <code>1.0</code> 小于版本 <code>1.1</code> ，因为它们下标为 <code>0</code> 的修订号相同，而下标为 <code>1</code> 的修订号分别为 <code>0</code> 和 <code>1</code> ，<code>0 &lt; 1</code> 。</p>\n\n<p>返回规则如下：</p>\n\n<ul>\n\t<li>如果&nbsp;<code><em>version1&nbsp;</em>&gt;&nbsp;<em>version2</em></code>&nbsp;返回&nbsp;<code>1</code>，</li>\n\t<li>如果&nbsp;<code><em>version1&nbsp;</em>&lt;&nbsp;<em>version2</em></code> 返回 <code>-1</code>，</li>\n\t<li>除此之外返回 <code>0</code>。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>version1 = \"1.01\", version2 = \"1.001\"\n<strong>输出：</strong>0\n<strong>解释：</strong>忽略前导零，\"01\" 和 \"001\" 都表示相同的整数 \"1\"\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>version1 = \"1.0\", version2 = \"1.0.0\"\n<strong>输出：</strong>0\n<strong>解释：</strong>version1 没有指定下标为 2 的修订号，即视为 \"0\"\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>version1 = \"0.1\", version2 = \"1.1\"\n<strong>输出：</strong>-1\n<strong>解释：</strong>version1 中下标为 0 的修订号是 \"0\"，version2 中下标为 0 的修订号是 \"1\" 。0 &lt; 1，所以 version1 &lt; version2\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= version1.length, version2.length &lt;= 500</code></li>\n\t<li><code>version1</code> 和 <code>version2</code> 仅包含数字和 <code>'.'</code></li>\n\t<li><code>version1</code> 和 <code>version2</code> 都是 <strong>有效版本号</strong></li>\n\t<li><code>version1</code> 和 <code>version2</code> 的所有修订号都可以存储在 <strong>32 位整数</strong> 中</li>\n</ul>\n",
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