leetcode-problemset/leetcode-cn/originData/bulb-switcher-ii.json

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            "categoryTitle": "Algorithms",
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            "title": "Bulb Switcher II",
            "titleSlug": "bulb-switcher-ii",
            "content": "<p>There is a room with <code>n</code> bulbs labeled from <code>1</code> to <code>n</code> that all are turned on initially, and <strong>four buttons</strong> on the wall. Each of the four buttons has a different functionality where:</p>\n\n<ul>\n\t<li><strong>Button 1:</strong> Flips the status of all the bulbs.</li>\n\t<li><strong>Button 2:</strong> Flips the status of all the bulbs with even labels (i.e., <code>2, 4, ...</code>).</li>\n\t<li><strong>Button 3:</strong> Flips the status of all the bulbs with odd labels (i.e., <code>1, 3, ...</code>).</li>\n\t<li><strong>Button 4:</strong> Flips the status of all the bulbs with a label <code>j = 3k + 1</code> where <code>k = 0, 1, 2, ...</code> (i.e., <code>1, 4, 7, 10, ...</code>).</li>\n</ul>\n\n<p>You must make <strong>exactly</strong> <code>presses</code> button presses in total. For each press, you may pick <strong>any</strong> of the four buttons to press.</p>\n\n<p>Given the two integers <code>n</code> and <code>presses</code>, return <em>the number of <strong>different possible statuses</strong> after performing all </em><code>presses</code><em> button presses</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 1, presses = 1\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> Status can be:\n- [off] by pressing button 1\n- [on] by pressing button 2\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 2, presses = 1\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> Status can be:\n- [off, off] by pressing button 1\n- [on, off] by pressing button 2\n- [off, on] by pressing button 3\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 3, presses = 1\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> Status can be:\n- [off, off, off] by pressing button 1\n- [off, on, off] by pressing button 2\n- [on, off, on] by pressing button 3\n- [off, on, on] by pressing button 4\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n\t<li><code>0 &lt;= presses &lt;= 1000</code></li>\n</ul>\n",
            "translatedTitle": "灯泡开关 Ⅱ",
            "translatedContent": "<p>房间中有 <code>n</code>&nbsp;只已经打开的灯泡，编号从 <code>1</code> 到 <code>n</code> 。墙上挂着 <strong>4 个开关</strong> 。</p>\n\n<p>这 4 个开关各自都具有不同的功能，其中：</p>\n\n<ul>\n\t<li><strong>开关 1 ：</strong>反转当前所有灯的状态（即开变为关，关变为开）</li>\n\t<li><strong>开关 2 ：</strong>反转编号为偶数的灯的状态（即 <code>0, 2, 4, ...</code>）</li>\n\t<li><strong>开关 3 ：</strong>反转编号为奇数的灯的状态（即 <code>1, 3, ...</code>）</li>\n\t<li><strong>开关 4 ：</strong>反转编号为 <code>j = 3k + 1</code> 的灯的状态，其中 <code>k = 0, 1, 2, ...</code>（即 <code>1, 4, 7, 10, ...</code>）</li>\n</ul>\n\n<p>你必须 <strong>恰好</strong> 按压开关 <code>presses</code> 次。每次按压，你都需要从 4 个开关中选出一个来执行按压操作。</p>\n\n<p>给你两个整数 <code>n</code> 和 <code>presses</code> ，执行完所有按压之后，返回 <strong>不同可能状态</strong> 的数量。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 1, presses = 1\n<strong>输出：</strong>2\n<strong>解释：</strong>状态可以是：\n- 按压开关 1 ，[关]\n- 按压开关 2 ，[开]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 2, presses = 1\n<strong>输出：</strong>3\n<strong>解释：</strong>状态可以是：\n- 按压开关 1 ，[关, 关]\n- 按压开关 2 ，[开, 关]\n- 按压开关 3 ，[关, 开]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 3, presses = 1\n<strong>输出：</strong>4\n<strong>解释：</strong>状态可以是：\n- 按压开关 1 ，[关, 关, 关]\n- 按压开关 2 ，[关, 开, 关]\n- 按压开关 3 ，[开, 关, 开]\n- 按压开关 4 ，[关, 开, 开]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n\t<li><code>0 &lt;= presses &lt;= 1000</code></li>\n</ul>\n",
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