leetcode-problemset/leetcode-cn/originData/aMhZSa.json

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        "question": {
            "questionId": "1000263",
            "questionFrontendId": "LCR 027",
            "categoryTitle": "Algorithms",
            "boundTopicId": 910264,
            "title": "回文链表",
            "titleSlug": "aMhZSa",
            "content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
            "translatedTitle": "回文链表",
            "translatedContent": "<p>给定一个链表的 <strong>头节点&nbsp;</strong><code>head</code><strong>&nbsp;，</strong>请判断其是否为回文链表。</p>\n\n<p>如果一个链表是回文，那么链表节点序列从前往后看和从后往前看是相同的。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://pic.leetcode-cn.com/1626421737-LjXceN-image.png\" /></strong></p>\n\n<pre>\n<strong>输入:</strong> head = [1,2,3,3,2,1]\n<strong>输出:</strong> true</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><strong><img alt=\"\" src=\"https://pic.leetcode-cn.com/1626422231-wgvnWh-image.png\" style=\"width: 138px; height: 62px;\" /></strong></p>\n\n<pre>\n<strong>输入:</strong> head = [1,2]\n<strong>输出:</strong> false\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>链表 L 的长度范围为 <code>[1, 10<sup><span style=\"font-size: 9.449999809265137px;\">5</span></sup>]</code></li>\n\t<li><code>0&nbsp;&lt;= node.val &lt;= 9</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong>能否用&nbsp;O(n) 时间复杂度和 O(1) 空间复杂度解决此题？</p>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 234&nbsp;题相同：<a href=\"https://leetcode-cn.com/problems/palindrome-linked-list/\">https://leetcode-cn.com/problems/palindrome-linked-list/</a></p>\n",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     ListNode *next;\n *     ListNode() : val(0), next(nullptr) {}\n *     ListNode(int x) : val(x), next(nullptr) {}\n *     ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n    bool isPalindrome(ListNode* head) {\n\n    }\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode() {}\n *     ListNode(int val) { this.val = val; }\n *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n    public boolean isPalindrome(ListNode head) {\n\n    }\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode(object):\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution(object):\n    def isPalindrome(self, head):\n        \"\"\"\n        :type head: ListNode\n        :rtype: bool\n        \"\"\"",
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                    "lang": "Python3",
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                    "code": "# Definition for singly-linked list.\n# class ListNode:\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution:\n    def isPalindrome(self, head: ListNode) -> bool:",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     struct ListNode *next;\n * };\n */\n\n\nbool isPalindrome(struct ListNode* head){\n\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public int val;\n *     public ListNode next;\n *     public ListNode(int val=0, ListNode next=null) {\n *         this.val = val;\n *         this.next = next;\n *     }\n * }\n */\npublic class Solution {\n    public bool IsPalindrome(ListNode head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {boolean}\n */\nvar isPalindrome = function(head) {\n\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *     val: number\n *     next: ListNode | null\n *     constructor(val?: number, next?: ListNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.next = (next===undefined ? null : next)\n *     }\n * }\n */\n\nfunction isPalindrome(head: ListNode | null): boolean {\n\n};",
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                    "code": "/**\n * Definition for a singly-linked list.\n * class ListNode {\n *     public $val = 0;\n *     public $next = null;\n *     function __construct($val = 0, $next = null) {\n *         $this->val = $val;\n *         $this->next = $next;\n *     }\n * }\n */\nclass Solution {\n\n    /**\n     * @param ListNode $head\n     * @return Boolean\n     */\n    function isPalindrome($head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public var val: Int\n *     public var next: ListNode?\n *     public init() { self.val = 0; self.next = nil; }\n *     public init(_ val: Int) { self.val = val; self.next = nil; }\n *     public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n    func isPalindrome(_ head: ListNode?) -> Bool {\n\n    }\n}",
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                    "lang": "Kotlin",
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                    "code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n *     var next: ListNode? = null\n * }\n */\nclass Solution {\n    fun isPalindrome(head: ListNode?): Boolean {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n *     Val int\n *     Next *ListNode\n * }\n */\nfunc isPalindrome(head *ListNode) bool {\n\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode\n#     attr_accessor :val, :next\n#     def initialize(val = 0, _next = nil)\n#         @val = val\n#         @next = _next\n#     end\n# end\n# @param {ListNode} head\n# @return {Boolean}\ndef is_palindrome(head)\n\nend",
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                    "code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n//   pub val: i32,\n//   pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n//   #[inline]\n//   fn new(val: i32) -> Self {\n//     ListNode {\n//       next: None,\n//       val\n//     }\n//   }\n// }\nimpl Solution {\n    pub fn is_palindrome(head: Option<Box<ListNode>>) -> bool {\n\n    }\n}",
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                    "lang": "Racket",
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                    "code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%%                     next = null :: 'null' | #list_node{}}).\n\n-spec is_palindrome(Head :: #list_node{} | null) -> boolean().\nis_palindrome(Head) ->\n  .",
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