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leetcode-problemset/leetcode-cn/originData/Uh984O.json

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{
"data": {
"question": {
"questionId": "1000138",
"questionFrontendId": "LCP 25",
"categoryTitle": "Algorithms",
"boundTopicId": 393241,
"title": "古董键盘",
"titleSlug": "Uh984O",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "古董键盘",
"translatedContent": "小扣在秋日市集购买了一个古董键盘。由于古董键盘年久失修,键盘上只有 26 个字母 **a~z** 可以按下,且每个字母最多仅能被按 `k` 次。\n\n小扣随机按了 `n` 次按键,请返回小扣总共有可能按出多少种内容。由于数字较大,最终答案需要对 1000000007 (1e9 + 7) 取模。\n\n\n**示例 1**\n>输入:`k = 1, n = 1`\n> \n>输出:`26`\n> \n>解释:由于只能按一次按键,所有可能的字符串为 \"a\", \"b\", ... \"z\" \n\n**示例 2**\n>输入:`k = 1, n = 2`\n> \n>输出:`650`\n> \n>解释:由于只能按两次按键,且每个键最多只能按一次,所有可能的字符串(按字典序排序)为 \"ab\", \"ac\", ... \"zy\" \n\n**提示:**\n- `1 <= k <= 5`\n- `1 <= n <= 26*k`\n \n\n",
"isPaidOnly": false,
"difficulty": "Hard",
"likes": 36,
"dislikes": 0,
"isLiked": null,
"similarQuestions": "[]",
"contributors": [
{
"username": "LeetCode",
"profileUrl": "/u/leetcode",
"avatarUrl": "https://assets.leetcode.cn/aliyun-lc-upload/uploaded_files/2021/03/73c9f099-abbe-4d94-853f-f8abffd459cd/leetcode.png",
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"translatedName": "数学",
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{
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"translatedName": "动态规划",
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{
"name": "Combinatorics",
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"translatedName": "组合数学",
"__typename": "TopicTagNode"
}
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"lang": "C++",
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"code": "class Solution {\npublic:\n int keyboard(int k, int n) {\n\n }\n};",
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{
"lang": "Java",
"langSlug": "java",
"code": "class Solution {\n public int keyboard(int k, int n) {\n\n }\n}",
"__typename": "CodeSnippetNode"
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{
"lang": "Python",
"langSlug": "python",
"code": "class Solution(object):\n def keyboard(self, k, n):\n \"\"\"\n :type k: int\n :type n: int\n :rtype: int\n \"\"\"",
"__typename": "CodeSnippetNode"
},
{
"lang": "Python3",
"langSlug": "python3",
"code": "class Solution:\n def keyboard(self, k: int, n: int) -> int:",
"__typename": "CodeSnippetNode"
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{
"lang": "C",
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"code": "\n\nint keyboard(int k, int n){\n\n}",
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{
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"code": "public class Solution {\n public int Keyboard(int k, int n) {\n\n }\n}",
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{
"lang": "JavaScript",
"langSlug": "javascript",
"code": "/**\n * @param {number} k\n * @param {number} n\n * @return {number}\n */\nvar keyboard = function(k, n) {\n\n};",
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{
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"lang": "Rust",
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"code": "impl Solution {\n pub fn keyboard(k: i32, n: i32) -> i32 {\n\n }\n}",
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{
"lang": "Racket",
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"sampleTestCase": "1\n1",
"metaData": "{\"name\": \"keyboard\", \"params\": [{\"name\": \"k\", \"type\": \"integer\"}, {\"name\": \"n\", \"type\": \"integer\"}], \"return\": {\"type\": \"integer\"}}",
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