leetcode-problemset/leetcode-cn/originData/OrIXps.json

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        "question": {
            "questionId": "1000270",
            "questionFrontendId": "LCR 031",
            "categoryTitle": "Algorithms",
            "boundTopicId": 910268,
            "title": "LRU 缓存",
            "titleSlug": "OrIXps",
            "content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
            "translatedTitle": "LRU 缓存",
            "translatedContent": "<div class=\"title__3Vvk\">\n<p>运用所掌握的数据结构，设计和实现一个&nbsp; <a href=\"https://baike.baidu.com/item/LRU\" target=\"_blank\">LRU (Least Recently Used，最近最少使用) 缓存机制</a> 。</p>\n\n<p>实现 <code>LRUCache</code> 类：</p>\n\n<ul>\n\t<li><code>LRUCache(int capacity)</code> 以正整数作为容量&nbsp;<code>capacity</code> 初始化 LRU 缓存</li>\n\t<li><code>int get(int key)</code> 如果关键字 <code>key</code> 存在于缓存中，则返回关键字的值，否则返回 <code>-1</code> 。</li>\n\t<li><code>void put(int key, int value)</code>&nbsp;如果关键字已经存在，则变更其数据值；如果关键字不存在，则插入该组「关键字-值」。当缓存容量达到上限时，它应该在写入新数据之前删除最久未使用的数据值，从而为新的数据值留出空间。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例：</strong></p>\n\n<pre>\n<strong>输入</strong>\n[&quot;LRUCache&quot;, &quot;put&quot;, &quot;put&quot;, &quot;get&quot;, &quot;put&quot;, &quot;get&quot;, &quot;put&quot;, &quot;get&quot;, &quot;get&quot;, &quot;get&quot;]\n[[2], [1, 1], [2, 2], [1], [3, 3], [2], [4, 4], [1], [3], [4]]\n<strong>输出</strong>\n[null, null, null, 1, null, -1, null, -1, 3, 4]\n\n<strong>解释</strong>\nLRUCache lRUCache = new LRUCache(2);\nlRUCache.put(1, 1); // 缓存是 {1=1}\nlRUCache.put(2, 2); // 缓存是 {1=1, 2=2}\nlRUCache.get(1);    // 返回 1\nlRUCache.put(3, 3); // 该操作会使得关键字 2 作废，缓存是 {1=1, 3=3}\nlRUCache.get(2);    // 返回 -1 (未找到)\nlRUCache.put(4, 4); // 该操作会使得关键字 1 作废，缓存是 {4=4, 3=3}\nlRUCache.get(1);    // 返回 -1 (未找到)\nlRUCache.get(3);    // 返回 3\nlRUCache.get(4);    // 返回 4\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= capacity &lt;= 3000</code></li>\n\t<li><code>0 &lt;= key &lt;= 10000</code></li>\n\t<li><code>0 &lt;= value &lt;= 10<sup>5</sup></code></li>\n\t<li>最多调用 <code>2 * 10<sup>5</sup></code> 次 <code>get</code> 和 <code>put</code></li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶</strong>：是否可以在&nbsp;<code>O(1)</code> 时间复杂度内完成这两种操作？</p>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意：本题与主站 146&nbsp;题相同：<a href=\"https://leetcode-cn.com/problems/lru-cache/\">https://leetcode-cn.com/problems/lru-cache/</a>&nbsp;</p>\n",
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                    "lang": "C++",
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                    "code": "class LRUCache {\npublic:\n    LRUCache(int capacity) {\n\n    }\n    \n    int get(int key) {\n\n    }\n    \n    void put(int key, int value) {\n\n    }\n};\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * LRUCache* obj = new LRUCache(capacity);\n * int param_1 = obj->get(key);\n * obj->put(key,value);\n */",
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                    "lang": "Java",
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                    "code": "class LRUCache {\n\n    public LRUCache(int capacity) {\n\n    }\n    \n    public int get(int key) {\n\n    }\n    \n    public void put(int key, int value) {\n\n    }\n}\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * LRUCache obj = new LRUCache(capacity);\n * int param_1 = obj.get(key);\n * obj.put(key,value);\n */",
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                    "lang": "Python",
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                    "code": "class LRUCache(object):\n\n    def __init__(self, capacity):\n        \"\"\"\n        :type capacity: int\n        \"\"\"\n\n\n    def get(self, key):\n        \"\"\"\n        :type key: int\n        :rtype: int\n        \"\"\"\n\n\n    def put(self, key, value):\n        \"\"\"\n        :type key: int\n        :type value: int\n        :rtype: None\n        \"\"\"\n\n\n\n# Your LRUCache object will be instantiated and called as such:\n# obj = LRUCache(capacity)\n# param_1 = obj.get(key)\n# obj.put(key,value)",
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                    "lang": "Python3",
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                    "code": "class LRUCache:\n\n    def __init__(self, capacity: int):\n\n\n    def get(self, key: int) -> int:\n\n\n    def put(self, key: int, value: int) -> None:\n\n\n\n# Your LRUCache object will be instantiated and called as such:\n# obj = LRUCache(capacity)\n# param_1 = obj.get(key)\n# obj.put(key,value)",
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                    "lang": "C",
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                    "code": "\n\n\ntypedef struct {\n\n} LRUCache;\n\n\nLRUCache* lRUCacheCreate(int capacity) {\n\n}\n\nint lRUCacheGet(LRUCache* obj, int key) {\n\n}\n\nvoid lRUCachePut(LRUCache* obj, int key, int value) {\n\n}\n\nvoid lRUCacheFree(LRUCache* obj) {\n\n}\n\n/**\n * Your LRUCache struct will be instantiated and called as such:\n * LRUCache* obj = lRUCacheCreate(capacity);\n * int param_1 = lRUCacheGet(obj, key);\n \n * lRUCachePut(obj, key, value);\n \n * lRUCacheFree(obj);\n*/",
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                    "lang": "C#",
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                    "code": "public class LRUCache {\n\n    public LRUCache(int capacity) {\n\n    }\n    \n    public int Get(int key) {\n\n    }\n    \n    public void Put(int key, int value) {\n\n    }\n}\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * LRUCache obj = new LRUCache(capacity);\n * int param_1 = obj.Get(key);\n * obj.Put(key,value);\n */",
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                    "lang": "JavaScript",
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                    "code": "/**\n * @param {number} capacity\n */\nvar LRUCache = function(capacity) {\n\n};\n\n/** \n * @param {number} key\n * @return {number}\n */\nLRUCache.prototype.get = function(key) {\n\n};\n\n/** \n * @param {number} key \n * @param {number} value\n * @return {void}\n */\nLRUCache.prototype.put = function(key, value) {\n\n};\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * var obj = new LRUCache(capacity)\n * var param_1 = obj.get(key)\n * obj.put(key,value)\n */",
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                    "lang": "TypeScript",
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                    "code": "class LRUCache {\n    constructor(capacity: number) {\n\n    }\n\n    get(key: number): number {\n\n    }\n\n    put(key: number, value: number): void {\n\n    }\n}\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * var obj = new LRUCache(capacity)\n * var param_1 = obj.get(key)\n * obj.put(key,value)\n */",
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                    "code": "class LRUCache {\n    /**\n     * @param Integer $capacity\n     */\n    function __construct($capacity) {\n\n    }\n\n    /**\n     * @param Integer $key\n     * @return Integer\n     */\n    function get($key) {\n\n    }\n\n    /**\n     * @param Integer $key\n     * @param Integer $value\n     * @return NULL\n     */\n    function put($key, $value) {\n\n    }\n}\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * $obj = LRUCache($capacity);\n * $ret_1 = $obj->get($key);\n * $obj->put($key, $value);\n */",
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                    "lang": "Swift",
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                    "code": "\nclass LRUCache {\n\n    init(_ capacity: Int) {\n\n    }\n    \n    func get(_ key: Int) -> Int {\n\n    }\n    \n    func put(_ key: Int, _ value: Int) {\n\n    }\n}\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * let obj = LRUCache(capacity)\n * let ret_1: Int = obj.get(key)\n * obj.put(key, value)\n */",
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                    "lang": "Kotlin",
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                    "code": "class LRUCache(capacity: Int) {\n\n    fun get(key: Int): Int {\n\n    }\n\n    fun put(key: Int, value: Int) {\n\n    }\n\n}\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * var obj = LRUCache(capacity)\n * var param_1 = obj.get(key)\n * obj.put(key,value)\n */",
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                    "lang": "Go",
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                    "code": "type LRUCache struct {\n\n}\n\n\nfunc Constructor(capacity int) LRUCache {\n\n}\n\n\nfunc (this *LRUCache) Get(key int) int {\n\n}\n\n\nfunc (this *LRUCache) Put(key int, value int)  {\n\n}\n\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * obj := Constructor(capacity);\n * param_1 := obj.Get(key);\n * obj.Put(key,value);\n */",
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                    "code": "class LRUCache\n\n=begin\n    :type capacity: Integer\n=end\n    def initialize(capacity)\n\n    end\n\n\n=begin\n    :type key: Integer\n    :rtype: Integer\n=end\n    def get(key)\n\n    end\n\n\n=begin\n    :type key: Integer\n    :type value: Integer\n    :rtype: Void\n=end\n    def put(key, value)\n\n    end\n\n\nend\n\n# Your LRUCache object will be instantiated and called as such:\n# obj = LRUCache.new(capacity)\n# param_1 = obj.get(key)\n# obj.put(key, value)",
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                    "lang": "Scala",
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                    "code": "class LRUCache(_capacity: Int) {\n\n    def get(key: Int): Int = {\n\n    }\n\n    def put(key: Int, value: Int) {\n\n    }\n\n}\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * var obj = new LRUCache(capacity)\n * var param_1 = obj.get(key)\n * obj.put(key,value)\n */",
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                    "code": "struct LRUCache {\n\n}\n\n\n/**\n * `&self` means the method takes an immutable reference.\n * If you need a mutable reference, change it to `&mut self` instead.\n */\nimpl LRUCache {\n\n    fn new(capacity: i32) -> Self {\n\n    }\n    \n    fn get(&self, key: i32) -> i32 {\n\n    }\n    \n    fn put(&self, key: i32, value: i32) {\n\n    }\n}\n\n/**\n * Your LRUCache object will be instantiated and called as such:\n * let obj = LRUCache::new(capacity);\n * let ret_1: i32 = obj.get(key);\n * obj.put(key, value);\n */",
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                    "lang": "Racket",
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                    "code": "(define lru-cache%\n  (class object%\n    (super-new)\n\n    ; capacity : exact-integer?\n    (init-field\n      capacity)\n    \n    ; get : exact-integer? -> exact-integer?\n    (define/public (get key)\n\n      )\n    ; put : exact-integer? exact-integer? -> void?\n    (define/public (put key value)\n\n      )))\n\n;; Your lru-cache% object will be instantiated and called as such:\n;; (define obj (new lru-cache% [capacity capacity]))\n;; (define param_1 (send obj get key))\n;; (send obj put key value)",
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                    "code": "-spec lru_cache_init_(Capacity :: integer()) -> any().\nlru_cache_init_(Capacity) ->\n  .\n\n-spec lru_cache_get(Key :: integer()) -> integer().\nlru_cache_get(Key) ->\n  .\n\n-spec lru_cache_put(Key :: integer(), Value :: integer()) -> any().\nlru_cache_put(Key, Value) ->\n  .\n\n\n%% Your functions will be called as such:\n%% lru_cache_init_(Capacity),\n%% Param_1 = lru_cache_get(Key),\n%% lru_cache_put(Key, Value),\n\n%% lru_cache_init_ will be called before every test case, in which you can do some necessary initializations.",
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                    "code": "defmodule LRUCache do\n  @spec init_(capacity :: integer) :: any\n  def init_(capacity) do\n\n  end\n\n  @spec get(key :: integer) :: integer\n  def get(key) do\n\n  end\n\n  @spec put(key :: integer, value :: integer) :: any\n  def put(key, value) do\n\n  end\nend\n\n# Your functions will be called as such:\n# LRUCache.init_(capacity)\n# param_1 = LRUCache.get(key)\n# LRUCache.put(key, value)\n\n# LRUCache.init_ will be called before every test case, in which you can do some necessary initializations.",
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