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leetcode-problemset/leetcode-cn/originData/Ju9Xwi.json
2023-12-09 19:57:46 +08:00

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{
"data": {
"question": {
"questionId": "1000225",
"questionFrontendId": "LCS 01",
"categoryTitle": "Algorithms",
"boundTopicId": 835230,
"title": "下载插件",
"titleSlug": "Ju9Xwi",
"content": "English description is not available for the problem. Please switch to Chinese.",
"translatedTitle": "下载插件",
"translatedContent": "小扣打算给自己的 **VS code** 安装使用插件,初始状态下带宽每分钟可以完成 `1` 个插件的下载。假定每分钟选择以下两种策略之一:\r\n- 使用当前带宽下载插件\r\n- 将带宽加倍(下载插件数量随之加倍)\r\n\r\n请返回小扣完成下载 `n` 个插件最少需要多少分钟。\r\n\r\n注意实际的下载的插件数量可以超过 `n` 个\r\n\r\n\r\n**示例 1**\r\n>输入:`n = 2`\r\n>\r\n>输出:`2`\r\n>\r\n>解释:\r\n> 以下两个方案,都能实现 2 分钟内下载 2 个插件\r\n>- 方案一:第一分钟带宽加倍,带宽可每分钟下载 2 个插件;第二分钟下载 2 个插件\r\n>- 方案二:第一分钟下载 1 个插件,第二分钟下载 1 个插件\r\n\r\n**示例 2**\r\n>输入:`n = 4`\r\n>\r\n>输出:`3`\r\n>\r\n>解释:\r\n> 最少需要 3 分钟可完成 4 个插件的下载,以下是其中一种方案:\r\n> 第一分钟带宽加倍,带宽可每分钟下载 2 个插件;\r\n> 第二分钟下载 2 个插件;\r\n> 第三分钟下载 2 个插件。\r\n\r\n\r\n\r\n**提示:**\r\n- `1 <= n <= 10^5`\r\n",
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"difficulty": "Easy",
"likes": 44,
"dislikes": 0,
"isLiked": null,
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{
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"code": "class Solution {\npublic:\n int leastMinutes(int n) {\n\n }\n};",
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{
"lang": "Python",
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"code": "class Solution(object):\n def leastMinutes(self, n):\n \"\"\"\n :type n: int\n :rtype: int\n \"\"\"",
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{
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