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leetcode-problemset/leetcode-cn/problem (Chinese)/用特殊操作处理字符串 I [process-string-with-special-operations-i].html
2025-07-17 00:14:36 +08:00

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<p>给你一个字符串 <code>s</code>,它由小写英文字母和特殊字符:<code>*</code><code>#</code><code>%</code> 组成。</p>
<p>请根据以下规则从左到右处理 <code>s</code>&nbsp;中的字符,构造一个新的字符串 <code>result</code></p>
<ul>
<li>如果字符是 <strong>小写</strong> 英文字母,则将其添加到 <code>result</code> 中。</li>
<li>字符 <code>'*'</code>&nbsp;<strong>删除</strong> <code>result</code> 中的最后一个字符(如果存在)。</li>
<li>字符 <code>'#'</code>&nbsp;<strong>复制&nbsp;</strong>当前的 <code>result</code>&nbsp;<strong>追加&nbsp;</strong>到其自身后面。</li>
<li>字符 <code>'%'</code>&nbsp;<strong>反转&nbsp;</strong>当前的 <code>result</code></li>
</ul>
<p>在处理完 <code>s</code> 中的所有字符后,返回最终的字符串 <code>result</code></p>
<p>&nbsp;</p>
<p><strong class="example">示例 1</strong></p>
<div class="example-block">
<p><strong>输入:</strong> <span class="example-io">s = "a#b%*"</span></p>
<p><strong>输出:</strong> <span class="example-io">"ba"</span></p>
<p><strong>解释:</strong></p>
<table style="border: 1px solid black;">
<thead>
<tr>
<th style="border: 1px solid black;"><code>i</code></th>
<th style="border: 1px solid black;"><code>s[i]</code></th>
<th style="border: 1px solid black;">操作</th>
<th style="border: 1px solid black;">当前 <code>result</code></th>
</tr>
</thead>
<tbody>
<tr>
<td style="border: 1px solid black;">0</td>
<td style="border: 1px solid black;"><code>'a'</code></td>
<td style="border: 1px solid black;">添加 <code>'a'</code></td>
<td style="border: 1px solid black;"><code>"a"</code></td>
</tr>
<tr>
<td style="border: 1px solid black;">1</td>
<td style="border: 1px solid black;"><code>'#'</code></td>
<td style="border: 1px solid black;">复制 <code>result</code></td>
<td style="border: 1px solid black;"><code>"aa"</code></td>
</tr>
<tr>
<td style="border: 1px solid black;">2</td>
<td style="border: 1px solid black;"><code>'b'</code></td>
<td style="border: 1px solid black;">添加 <code>'b'</code></td>
<td style="border: 1px solid black;"><code>"aab"</code></td>
</tr>
<tr>
<td style="border: 1px solid black;">3</td>
<td style="border: 1px solid black;"><code>'%'</code></td>
<td style="border: 1px solid black;">反转 <code>result</code></td>
<td style="border: 1px solid black;"><code>"baa"</code></td>
</tr>
<tr>
<td style="border: 1px solid black;">4</td>
<td style="border: 1px solid black;"><code>'*'</code></td>
<td style="border: 1px solid black;">删除最后一个字符</td>
<td style="border: 1px solid black;"><code>"ba"</code></td>
</tr>
</tbody>
</table>
<p>因此,最终的 <code>result</code><code>"ba"</code></p>
</div>
<p><strong class="example">示例 2</strong></p>
<div class="example-block">
<p><strong>输入:</strong> <span class="example-io">s = "z*#"</span></p>
<p><strong>输出:</strong> <span class="example-io">""</span></p>
<p><strong>解释:</strong></p>
<table style="border: 1px solid black;">
<thead>
<tr>
<th style="border: 1px solid black;"><code>i</code></th>
<th style="border: 1px solid black;"><code>s[i]</code></th>
<th style="border: 1px solid black;">操作</th>
<th style="border: 1px solid black;">当前 <code>result</code></th>
</tr>
</thead>
<tbody>
<tr>
<td style="border: 1px solid black;">0</td>
<td style="border: 1px solid black;"><code>'z'</code></td>
<td style="border: 1px solid black;">添加 <code>'z'</code></td>
<td style="border: 1px solid black;"><code>"z"</code></td>
</tr>
<tr>
<td style="border: 1px solid black;">1</td>
<td style="border: 1px solid black;"><code>'*'</code></td>
<td style="border: 1px solid black;">删除最后一个字符</td>
<td style="border: 1px solid black;"><code>""</code></td>
</tr>
<tr>
<td style="border: 1px solid black;">2</td>
<td style="border: 1px solid black;"><code>'#'</code></td>
<td style="border: 1px solid black;">复制字符串</td>
<td style="border: 1px solid black;"><code>""</code></td>
</tr>
</tbody>
</table>
<p>因此,最终的 <code>result</code><code>""</code></p>
</div>
<p>&nbsp;</p>
<p><strong>提示:</strong></p>
<ul>
<li><code>1 &lt;= s.length &lt;= 20</code></li>
<li><code>s</code> 只包含小写英文字母和特殊字符 <code>*</code><code>#</code><code>%</code></li>
</ul>