mirror of
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189 lines
27 KiB
JSON
189 lines
27 KiB
JSON
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"title": "Unit Conversion I",
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"content": "<p>There are <code>n</code> types of units indexed from <code>0</code> to <code>n - 1</code>. You are given a 2D integer array <code>conversions</code> of length <code>n - 1</code>, where <code>conversions[i] = [sourceUnit<sub>i</sub>, targetUnit<sub>i</sub>, conversionFactor<sub>i</sub>]</code>. This indicates that a single unit of type <code>sourceUnit<sub>i</sub></code> is equivalent to <code>conversionFactor<sub>i</sub></code> units of type <code>targetUnit<sub>i</sub></code>.</p>\n\n<p>Return an array <code>baseUnitConversion</code> of length <code>n</code>, where <code>baseUnitConversion[i]</code> is the number of units of type <code>i</code> equivalent to a single unit of type 0. Since the answer may be large, return each <code>baseUnitConversion[i]</code> <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">conversions = [[0,1,2],[1,2,3]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[1,2,6]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Convert a single unit of type 0 into 2 units of type 1 using <code>conversions[0]</code>.</li>\n\t<li>Convert a single unit of type 0 into 6 units of type 2 using <code>conversions[0]</code>, then <code>conversions[1]</code>.</li>\n</ul>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2025/03/12/example1.png\" style=\"width: 545px; height: 118px;\" /></div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">conversions = [[0,1,2],[0,2,3],[1,3,4],[1,4,5],[2,5,2],[4,6,3],[5,7,4]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[1,2,3,8,10,6,30,24]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Convert a single unit of type 0 into 2 units of type 1 using <code>conversions[0]</code>.</li>\n\t<li>Convert a single unit of type 0 into 3 units of type 2 using <code>conversions[1]</code>.</li>\n\t<li>Convert a single unit of type 0 into 8 units of type 3 using <code>conversions[0]</code>, then <code>conversions[2]</code>.</li>\n\t<li>Convert a single unit of type 0 into 10 units of type 4 using <code>conversions[0]</code>, then <code>conversions[3]</code>.</li>\n\t<li>Convert a single unit of type 0 into 6 units of type 5 using <code>conversions[1]</code>, then <code>conversions[4]</code>.</li>\n\t<li>Convert a single unit of type 0 into 30 units of type 6 using <code>conversions[0]</code>, <code>conversions[3]</code>, then <code>conversions[5]</code>.</li>\n\t<li>Convert a single unit of type 0 into 24 units of type 7 using <code>conversions[1]</code>, <code>conversions[4]</code>, then <code>conversions[6]</code>.</li>\n</ul>\n</div>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>conversions.length == n - 1</code></li>\n\t<li><code>0 <= sourceUnit<sub>i</sub>, targetUnit<sub>i</sub> < n</code></li>\n\t<li><code>1 <= conversionFactor<sub>i</sub> <= 10<sup>9</sup></code></li>\n\t<li>It is guaranteed that unit 0 can be converted into any other unit through a <strong>unique</strong> combination of conversions without using any conversions in the opposite direction.</li>\n</ul>\n",
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"translatedTitle": "单位转换 I",
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"translatedContent": "<p>有 <code>n</code> 种单位,编号从 <code>0</code> 到 <code>n - 1</code>。给你一个二维整数数组 <code>conversions</code>,长度为 <code>n - 1</code>,其中 <code>conversions[i] = [sourceUnit<sub>i</sub>, targetUnit<sub>i</sub>, conversionFactor<sub>i</sub>]</code> ,表示一个 <code>sourceUnit<sub>i</sub></code> 类型的单位等于 <code>conversionFactor<sub>i</sub></code> 个 <code>targetUnit<sub>i</sub></code> 类型的单位。</p>\n\n<p>请你返回一个长度为 <code>n</code> 的数组 <code>baseUnitConversion</code>,其中 <code>baseUnitConversion[i]</code> 表示 <strong>一个</strong> 0 类型单位等于多少个 i 类型单位。由于结果可能很大,请返回每个 <code>baseUnitConversion[i]</code> 对 <code>10<sup>9</sup> + 7</code> 取模后的值。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">conversions = [[0,1,2],[1,2,3]]</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">[1,2,6]</span></p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li>使用 <code>conversions[0]</code>:将一个 0 类型单位转换为 2 个 1 类型单位。</li>\n\t<li>使用 <code>conversions[0]</code> 和 <code>conversions[1]</code> 将一个 0 类型单位转换为 6 个 2 类型单位。</li>\n</ul>\n<img alt=\"\" src=\"https://pic.leetcode.cn/1745660099-FZhVTM-example1.png\" style=\"width: 545px; height: 119px;\" /></div>\n\n<p><strong class=\"example\">示例 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">conversions = [[0,1,2],[0,2,3],[1,3,4],[1,4,5],[2,5,2],[4,6,3],[5,7,4]]</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">[1,2,3,8,10,6,30,24]</span></p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li>使用 <code>conversions[0]</code> 将一个 0 类型单位转换为 2 个 1 类型单位。</li>\n\t<li>使用 <code>conversions[1]</code> 将一个 0 类型单位转换为 3 个 2 类型单位。</li>\n\t<li>使用 <code>conversions[0]</code> 和 <code>conversions[2]</code> 将一个 0 类型单位转换为 8 个 3 类型单位。</li>\n\t<li>使用 <code>conversions[0]</code> 和 <code>conversions[3]</code> 将一个 0 类型单位转换为 10 个 4 类型单位。</li>\n\t<li>使用 <code>conversions[1]</code> 和 <code>conversions[4]</code> 将一个 0 类型单位转换为 6 个 5 类型单位。</li>\n\t<li>使用 <code>conversions[0]</code>、<code>conversions[3]</code> 和 <code>conversions[5]</code> 将一个 0 类型单位转换为 30 个 6 类型单位。</li>\n\t<li>使用 <code>conversions[1]</code>、<code>conversions[4]</code> 和 <code>conversions[6]</code> 将一个 0 类型单位转换为 24 个 7 类型单位。</li>\n</ul>\n</div>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>2 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>conversions.length == n - 1</code></li>\n\t<li><code>0 <= sourceUnit<sub>i</sub>, targetUnit<sub>i</sub> < n</code></li>\n\t<li><code>1 <= conversionFactor<sub>i</sub> <= 10<sup>9</sup></code></li>\n\t<li>保证单位 0 可以通过 <strong>唯一 </strong>的转换路径(不需要反向转换)转换为任何其他单位。</li>\n</ul>\n",
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<code>use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n int id; \\/* we'll use this field as the key *\\/\\r\\n char name[10];\\r\\n UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry *s) {\\r\\n 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