leetcode-problemset/leetcode-cn/originData/subsets-ii.json

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            "questionId": "90",
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            "categoryTitle": "Algorithms",
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            "title": "Subsets II",
            "titleSlug": "subsets-ii",
            "content": "<p>Given an integer array <code>nums</code> that may contain duplicates, return <em>all possible</em> <span data-keyword=\"subset\"><em>subsets</em></span><em> (the power set)</em>.</p>\n\n<p>The solution set <strong>must not</strong> contain duplicate subsets. Return the solution in <strong>any order</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<pre><strong>Input:</strong> nums = [1,2,2]\n<strong>Output:</strong> [[],[1],[1,2],[1,2,2],[2],[2,2]]\n</pre><p><strong class=\"example\">Example 2:</strong></p>\n<pre><strong>Input:</strong> nums = [0]\n<strong>Output:</strong> [[],[0]]\n</pre>\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10</code></li>\n\t<li><code>-10 &lt;= nums[i] &lt;= 10</code></li>\n</ul>\n",
            "translatedTitle": "子集 II",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code> ，其中可能包含重复元素，请你返回该数组所有可能的 <span data-keyword=\"subset\">子集</span>（幂集）。</p>\n\n<p>解集 <strong>不能</strong> 包含重复的子集。返回的解集中，子集可以按 <strong>任意顺序</strong> 排列。</p>\n\n<div class=\"original__bRMd\">\n<div>\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,2]\n<strong>输出：</strong>[[],[1],[1,2],[1,2,2],[2],[2,2]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [0]\n<strong>输出：</strong>[[],[0]]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10</code></li>\n\t<li><code>-10 &lt;= nums[i] &lt;= 10</code></li>\n</ul>\n</div>\n</div>\n",
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                    "code": "class Solution {\npublic:\n    vector<vector<int>> subsetsWithDup(vector<int>& nums) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def subsetsWithDup(self, nums):\n        \"\"\"\n        :type nums: List[int]\n        :rtype: List[List[int]]\n        \"\"\"\n        ",
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                    "lang": "C",
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                    "code": "/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** subsetsWithDup(int* nums, int numsSize, int* returnSize, int** returnColumnSizes) {\n    \n}",
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                    "code": "public class Solution {\n    public IList<IList<int>> SubsetsWithDup(int[] nums) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number[]} nums\n * @return {number[][]}\n */\nvar subsetsWithDup = function(nums) {\n    \n};",
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                    "code": "function subsetsWithDup(nums: number[]): number[][] {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @return Integer[][]\n     */\n    function subsetsWithDup($nums) {\n        \n    }\n}",
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                    "code": "# @param {Integer[]} nums\n# @return {Integer[][]}\ndef subsets_with_dup(nums)\n    \nend",
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                    "code": "object Solution {\n    def subsetsWithDup(nums: Array[Int]): List[List[Int]] = {\n        \n    }\n}",
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                    "code": "impl Solution {\n    pub fn subsets_with_dup(nums: Vec<i32>) -> Vec<Vec<i32>> {\n        \n    }\n}",
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                    "lang": "Erlang",
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                    "code": "-spec subsets_with_dup(Nums :: [integer()]) -> [[integer()]].\nsubsets_with_dup(Nums) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec subsets_with_dup(nums :: [integer]) :: [[integer]]\n  def subsets_with_dup(nums) do\n    \n  end\nend",
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