mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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222 lines
35 KiB
JSON
222 lines
35 KiB
JSON
{
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"questionId": "3863",
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"questionFrontendId": "3607",
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"categoryTitle": "Algorithms",
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"boundTopicId": 3714205,
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"title": "Power Grid Maintenance",
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"titleSlug": "power-grid-maintenance",
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"content": "<p data-end=\"401\" data-start=\"120\">You are given an integer <code data-end=\"194\" data-start=\"191\">c</code> representing <code data-end=\"211\" data-start=\"208\">c</code> power stations, each with a unique identifier <code>id</code> from 1 to <code>c</code> (1‑based indexing).</p>\n\n<p data-end=\"401\" data-start=\"120\">These stations are interconnected via <code data-end=\"295\" data-start=\"292\">n</code> <strong>bidirectional</strong> cables, represented by a 2D array <code data-end=\"357\" data-start=\"344\">connections</code>, where each element <code data-end=\"430\" data-start=\"405\">connections[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> indicates a connection between station <code>u<sub>i</sub></code> and station <code>v<sub>i</sub></code>. Stations that are directly or indirectly connected form a <strong>power grid</strong>.</p>\n\n<p data-end=\"626\" data-start=\"586\">Initially, <strong>all</strong> stations are online (operational).</p>\n\n<p data-end=\"720\" data-start=\"628\">You are also given a 2D array <code data-end=\"667\" data-start=\"658\">queries</code>, where each query is one of the following <em>two</em> types:</p>\n\n<ul data-end=\"995\" data-start=\"722\">\n\t<li data-end=\"921\" data-start=\"722\">\n\t<p data-end=\"921\" data-start=\"724\"><code data-end=\"732\" data-start=\"724\">[1, x]</code>: A maintenance check is requested for station <code data-end=\"782\" data-start=\"779\">x</code>. If station <code>x</code> is online, it resolves the check by itself. If station <code>x</code> is offline, the check is resolved by the operational station with the smallest <code>id</code> in the same <strong>power grid</strong> as <code>x</code>. If <strong>no</strong> <strong>operational</strong> station <em>exists</em> in that grid, return -1.</p>\n\t</li>\n\t<li data-end=\"995\" data-start=\"923\">\n\t<p data-end=\"995\" data-start=\"925\"><code data-end=\"933\" data-start=\"925\">[2, x]</code>: Station <code data-end=\"946\" data-start=\"943\">x</code> goes offline (i.e., it becomes non-operational).</p>\n\t</li>\n</ul>\n\n<p data-end=\"1106\" data-start=\"997\">Return an array of integers representing the results of each query of type <code data-end=\"1080\" data-start=\"1072\">[1, x]</code> in the <strong>order</strong> they appear.</p>\n\n<p data-end=\"1106\" data-start=\"997\"><strong>Note:</strong> The power grid preserves its structure; an offline (non‑operational) node remains part of its grid and taking it offline does not alter connectivity.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">c = 5, connections = [[1,2],[2,3],[3,4],[4,5]], queries = [[1,3],[2,1],[1,1],[2,2],[1,2]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[3,2,3]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2025/04/15/powergrid.jpg\" style=\"width: 361px; height: 42px;\" /></p>\n\n<ul>\n\t<li data-end=\"223\" data-start=\"143\">Initially, all stations <code>{1, 2, 3, 4, 5}</code> are online and form a single power grid.</li>\n\t<li data-end=\"322\" data-start=\"226\">Query <code>[1,3]</code>: Station 3 is online, so the maintenance check is resolved by station 3.</li>\n\t<li data-end=\"402\" data-start=\"325\">Query <code>[2,1]</code>: Station 1 goes offline. The remaining online stations are <code>{2, 3, 4, 5}</code>.</li>\n\t<li data-end=\"557\" data-start=\"405\">Query <code>[1,1]</code>: Station 1 is offline, so the check is resolved by the operational station with the smallest <code>id</code> among <code>{2, 3, 4, 5}</code>, which is station 2.</li>\n\t<li data-end=\"641\" data-start=\"560\">Query <code>[2,2]</code>: Station 2 goes offline. The remaining online stations are <code>{3, 4, 5}</code>.</li>\n\t<li data-end=\"800\" data-start=\"644\">Query <code>[1,2]</code>: Station 2 is offline, so the check is resolved by the operational station with the smallest <code>id</code> among <code>{3, 4, 5}</code>, which is station 3.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">c = 3, connections = [], queries = [[1,1],[2,1],[1,1]]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[1,-1]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li data-end=\"976\" data-start=\"909\">There are no connections, so each station is its own isolated grid.</li>\n\t<li data-end=\"1096\" data-start=\"979\">Query <code>[1,1]</code>: Station 1 is online in its isolated grid, so the maintenance check is resolved by station 1.</li>\n\t<li data-end=\"1135\" data-start=\"1099\">Query <code>[2,1]</code>: Station 1 goes offline.</li>\n\t<li data-end=\"1237\" data-start=\"1138\">Query <code>[1,1]</code>: Station 1 is offline and there are no other stations in its grid, so the result is -1.</li>\n</ul>\n</div>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li data-end=\"155\" data-start=\"139\"><code>1 <= c <= 10<sup>5</sup></code></li>\n\t<li data-end=\"213\" data-start=\"158\"><code>0 <= n == connections.length <= min(10<sup>5</sup>, c * (c - 1) / 2)</code></li>\n\t<li data-end=\"244\" data-start=\"216\"><code>connections[i].length == 2</code></li>\n\t<li data-end=\"295\" data-start=\"247\"><code>1 <= u<sub>i</sub>, v<sub>i</sub> <= c</code></li>\n\t<li data-end=\"338\" data-start=\"298\"><code>u<sub>i</sub> != v<sub>i</sub></code></li>\n\t<li data-end=\"374\" data-start=\"341\"><code>1 <= queries.length <= 2 * 10<sup>5</sup></code></li>\n\t<li data-end=\"401\" data-start=\"377\"><code>queries[i].length == 2</code></li>\n\t<li data-end=\"436\" data-start=\"404\"><code>queries[i][0]</code> is either 1 or 2.</li>\n\t<li data-end=\"462\" data-start=\"439\"><code>1 <= queries[i][1] <= c</code></li>\n</ul>\n",
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"translatedTitle": "电网维护",
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"translatedContent": "<p data-end=\"401\" data-start=\"120\">给你一个整数 <code data-end=\"194\" data-start=\"191\">c</code>,表示 <code data-end=\"211\" data-start=\"208\">c</code> 个电站,每个电站有一个唯一标识符 <code>id</code>,从 1 到 <code>c</code> 编号。</p>\n\n<p data-end=\"401\" data-start=\"120\">这些电站通过 <code data-end=\"295\" data-start=\"292\">n</code> 条 <strong>双向 </strong>电缆互相连接,表示为一个二维数组 <code data-end=\"357\" data-start=\"344\">connections</code>,其中每个元素 <code data-end=\"430\" data-start=\"405\">connections[i] = [u<sub>i</sub>, v<sub>i</sub>]</code> 表示电站 <code>u<sub>i</sub></code> 和电站 <code>v<sub>i</sub></code> 之间的连接。直接或间接连接的电站组成了一个 <strong>电网 </strong>。</p>\n\n<p data-end=\"626\" data-start=\"586\">最初,<strong>所有 </strong>电站均处于在线(正常运行)状态。</p>\n\n<p data-end=\"720\" data-start=\"628\">另给你一个二维数组 <code data-end=\"667\" data-start=\"658\">queries</code>,其中每个查询属于以下 <strong>两种类型之一 </strong>:</p>\n\n<ul data-end=\"995\" data-start=\"722\">\n\t<li data-end=\"921\" data-start=\"722\">\n\t<p data-end=\"921\" data-start=\"724\"><code data-end=\"732\" data-start=\"724\">[1, x]</code>:请求对电站 <code data-end=\"782\" data-start=\"779\">x</code> 进行维护检查。如果电站 <code>x</code> 在线,则它自行解决检查。如果电站 <code>x</code> 已离线,则检查由与 <code>x</code> 同一 <strong>电网 </strong>中 <strong>编号最小 </strong>的在线电站解决。如果该电网中 <strong>不存在 </strong>任何 <strong>在线 </strong>电站,则返回 -1。</p>\n\t</li>\n\t<li data-end=\"995\" data-start=\"923\">\n\t<p data-end=\"995\" data-start=\"925\"><code data-end=\"933\" data-start=\"925\">[2, x]</code>:电站 <code data-end=\"946\" data-start=\"943\">x</code> 离线(即变为非运行状态)。</p>\n\t</li>\n</ul>\n\n<p data-end=\"1106\" data-start=\"997\">返回一个整数数组,表示按照查询中出现的顺序,所有类型为 <code data-end=\"1080\" data-start=\"1072\">[1, x]</code> 的查询结果。</p>\n\n<p data-end=\"1106\" data-start=\"997\"><strong>注意:</strong>电网的结构是固定的;离线(非运行)的节点仍然属于其所在的电网,且离线操作不会改变电网的连接性。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">c = 5, connections = [[1,2],[2,3],[3,4],[4,5]], queries = [[1,3],[2,1],[1,1],[2,2],[1,2]]</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">[3,2,3]</span></p>\n\n<p><strong>解释:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2025/04/15/powergrid.jpg\" style=\"width: 361px; height: 42px;\" /></p>\n\n<ul>\n\t<li data-end=\"223\" data-start=\"143\">最初,所有电站 <code>{1, 2, 3, 4, 5}</code> 都在线,并组成一个电网。</li>\n\t<li data-end=\"322\" data-start=\"226\">查询 <code>[1,3]</code>:电站 3 在线,因此维护检查由电站 3 自行解决。</li>\n\t<li data-end=\"402\" data-start=\"325\">查询 <code>[2,1]</code>:电站 1 离线。剩余在线电站为 <code>{2, 3, 4, 5}</code>。</li>\n\t<li data-end=\"557\" data-start=\"405\">查询 <code>[1,1]</code>:电站 1 离线,因此检查由电网中编号最小的在线电站解决,即电站 2。</li>\n\t<li data-end=\"641\" data-start=\"560\">查询 <code>[2,2]</code>:电站 2 离线。剩余在线电站为 <code>{3, 4, 5}</code>。</li>\n\t<li data-end=\"800\" data-start=\"644\">查询 <code>[1,2]</code>:电站 2 离线,因此检查由电网中编号最小的在线电站解决,即电站 3。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入:</strong> <span class=\"example-io\">c = 3, connections = [], queries = [[1,1],[2,1],[1,1]]</span></p>\n\n<p><strong>输出:</strong> <span class=\"example-io\">[1,-1]</span></p>\n\n<p><strong>解释:</strong></p>\n\n<ul>\n\t<li data-end=\"976\" data-start=\"909\">没有连接,因此每个电站是一个独立的电网。</li>\n\t<li data-end=\"1096\" data-start=\"979\">查询 <code>[1,1]</code>:电站 1 在线,且属于其独立电网,因此维护检查由电站 1 自行解决。</li>\n\t<li data-end=\"1135\" data-start=\"1099\">查询 <code>[2,1]</code>:电站 1 离线。</li>\n\t<li data-end=\"1237\" data-start=\"1138\">查询 <code>[1,1]</code>:电站 1 离线,且其电网中没有其他电站,因此结果为 -1。</li>\n</ul>\n</div>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li data-end=\"155\" data-start=\"139\"><code>1 <= c <= 10<sup>5</sup></code></li>\n\t<li data-end=\"213\" data-start=\"158\"><code>0 <= n == connections.length <= min(10<sup>5</sup>, c * (c - 1) / 2)</code></li>\n\t<li data-end=\"244\" data-start=\"216\"><code>connections[i].length == 2</code></li>\n\t<li data-end=\"295\" data-start=\"247\"><code>1 <= u<sub>i</sub>, v<sub>i</sub> <= c</code></li>\n\t<li data-end=\"338\" data-start=\"298\"><code>u<sub>i</sub> != v<sub>i</sub></code></li>\n\t<li data-end=\"374\" data-start=\"341\"><code>1 <= queries.length <= 2 * 10<sup>5</sup></code></li>\n\t<li data-end=\"401\" data-start=\"377\"><code>queries[i].length == 2</code></li>\n\t<li data-end=\"436\" data-start=\"404\"><code>queries[i][0]</code> 为 1 或 2。</li>\n\t<li data-end=\"462\" data-start=\"439\"><code>1 <= queries[i][1] <= c</code></li>\n</ul>\n",
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"code": "defmodule Solution do\n @spec process_queries(c :: integer, connections :: [[integer]], queries :: [[integer]]) :: [integer]\n def process_queries(c, connections, queries) do\n \n end\nend",
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{
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"lang": "Cangjie",
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"code": "class Solution {\n func processQueries(c: Int64, connections: Array<Array<Int64>>, queries: Array<Array<Int64>>): Array<Int64> {\n\n }\n}",
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"hints": [
|
||
"Use DFS or BFS to assign each station a component ID",
|
||
"For each component, maintain a sorted set of online station IDs",
|
||
"For query <code>[2, x]</code>, remove <code>x</code> from the set of its component",
|
||
"For query <code>[1, x]</code>, if <code>x</code> is in its component’s set return <code>x</code>; otherwise if the set is non-empty return its smallest element; else return <code>-1</code>",
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"Precompute all components and then handle each query in O(log n) time using the sorted sets"
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],
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"sampleTestCase": "5\n[[1,2],[2,3],[3,4],[4,5]]\n[[1,3],[2,1],[1,1],[2,2],[1,2]]",
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