leetcode-problemset/leetcode-cn/originData/number-of-equivalent-domino-pairs.json

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        "question": {
            "questionId": "1227",
            "questionFrontendId": "1128",
            "categoryTitle": "Algorithms",
            "boundTopicId": 15233,
            "title": "Number of Equivalent Domino Pairs",
            "titleSlug": "number-of-equivalent-domino-pairs",
            "content": "<p>Given a list of <code>dominoes</code>, <code>dominoes[i] = [a, b]</code> is <strong>equivalent to</strong> <code>dominoes[j] = [c, d]</code> if and only if either (<code>a == c</code> and <code>b == d</code>), or (<code>a == d</code> and <code>b == c</code>) - that is, one domino can be rotated to be equal to another domino.</p>\n\n<p>Return <em>the number of pairs </em><code>(i, j)</code><em> for which </em><code>0 &lt;= i &lt; j &lt; dominoes.length</code><em>, and </em><code>dominoes[i]</code><em> is <strong>equivalent to</strong> </em><code>dominoes[j]</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> dominoes = [[1,2],[2,1],[3,4],[5,6]]\n<strong>Output:</strong> 1\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> dominoes = [[1,2],[1,2],[1,1],[1,2],[2,2]]\n<strong>Output:</strong> 3\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= dominoes.length &lt;= 4 * 10<sup>4</sup></code></li>\n\t<li><code>dominoes[i].length == 2</code></li>\n\t<li><code>1 &lt;= dominoes[i][j] &lt;= 9</code></li>\n</ul>\n",
            "translatedTitle": "等价多米诺骨牌对的数量",
            "translatedContent": "<p>给你一组多米诺骨牌 <code>dominoes</code> 。</p>\n\n<p>形式上，<code>dominoes[i] = [a, b]</code> 与 <code>dominoes[j] = [c, d]</code> <strong>等价</strong> 当且仅当 (<code>a == c</code> 且 <code>b == d</code>) 或者 (<code>a == d</code> 且 <code>b == c</code>) 。即一张骨牌可以通过旋转 <code>0</code>&nbsp;度或 <code>180</code> 度得到另一张多米诺骨牌。</p>\n\n<p>在&nbsp;<code>0 &lt;= i &lt; j &lt; dominoes.length</code>&nbsp;的前提下，找出满足&nbsp;<code>dominoes[i]</code> 和&nbsp;<code>dominoes[j]</code>&nbsp;等价的骨牌对 <code>(i, j)</code> 的数量。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>dominoes = [[1,2],[2,1],[3,4],[5,6]]\n<strong>输出：</strong>1\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>dominoes = [[1,2],[1,2],[1,1],[1,2],[2,2]]\n<strong>输出：</strong>3\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= dominoes.length &lt;= 4 * 10<sup>4</sup></code></li>\n\t<li><code>dominoes[i].length == 2</code></li>\n\t<li><code>1 &lt;= dominoes[i][j] &lt;= 9</code></li>\n</ul>\n",
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                    "code": "public class Solution {\n    public int NumEquivDominoPairs(int[][] dominoes) {\n        \n    }\n}",
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            "hints": [
                "For each domino j, find the number of dominoes you've already seen (dominoes i with i < j) that are equivalent.",
                "You can keep track of what you've seen using a hashmap."
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