leetcode-problemset/leetcode-cn/originData/minimum-deletions-for-at-most-k-distinct-characters.json

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            "categoryTitle": "Algorithms",
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            "title": "Minimum Deletions for At Most K Distinct Characters",
            "titleSlug": "minimum-deletions-for-at-most-k-distinct-characters",
            "content": "<p>You are given a string <code>s</code> consisting of lowercase English letters, and an integer <code>k</code>.</p>\n\n<p>Your task is to delete some (possibly none) of the characters in the string so that the number of <strong>distinct</strong> characters in the resulting string is <strong>at most</strong> <code>k</code>.</p>\n\n<p>Return the <strong>minimum</strong> number of deletions required to achieve this.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;abc&quot;, k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li><code>s</code> has three distinct characters: <code>&#39;a&#39;</code>, <code>&#39;b&#39;</code> and <code>&#39;c&#39;</code>, each with a frequency of 1.</li>\n\t<li>Since we can have at most <code>k = 2</code> distinct characters, remove all occurrences of any one character from the string.</li>\n\t<li>For example, removing all occurrences of <code>&#39;c&#39;</code> results in at most <code>k</code> distinct characters. Thus, the answer is 1.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;aabb&quot;, k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li><code>s</code> has two distinct characters (<code>&#39;a&#39;</code> and <code>&#39;b&#39;</code>) with frequencies of 2 and 2, respectively.</li>\n\t<li>Since we can have at most <code>k = 2</code> distinct characters, no deletions are required. Thus, the answer is 0.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;yyyzz&quot;, k = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li><code>s</code> has two distinct characters (<code>&#39;y&#39;</code> and <code>&#39;z&#39;</code>) with frequencies of 3 and 2, respectively.</li>\n\t<li>Since we can have at most <code>k = 1</code> distinct character, remove all occurrences of any one character from the string.</li>\n\t<li>Removing all <code>&#39;z&#39;</code> results in at most <code>k</code> distinct characters. Thus, the answer is 2.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 16</code></li>\n\t<li><code>1 &lt;= k &lt;= 16</code></li>\n\t<li><code>s</code> consists only of lowercase English letters.</li>\n</ul>\n\n<p> </p>\n",
            "translatedTitle": "不同字符数量最多为 K 时的最少删除数",
            "translatedContent": "<p>给你一个字符串 <code>s</code>（由小写英文字母组成）和一个整数 <code>k</code>。</p>\n\n<p>你的任务是删除字符串中的一些字符（可以不删除任何字符），使得结果字符串中的&nbsp;<strong>不同字符数量&nbsp;</strong>最多为 <code>k</code>。</p>\n\n<p>返回为达到上述目标所需删除的&nbsp;<strong>最小&nbsp;</strong>字符数量。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">s = \"abc\", k = 2</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">1</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li><code>s</code> 有三个不同的字符：<code>'a'</code>、<code>'b'</code> 和 <code>'c'</code>，每个字符的出现频率为 1。</li>\n\t<li>由于最多只能有 <code>k = 2</code> 个不同字符，需要删除某一个字符的所有出现。</li>\n\t<li>例如，删除所有 <code>'c'</code> 后，结果字符串中的不同字符数最多为 <code>k</code>。因此，答案是 1。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">s = \"aabb\", k = 2</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li><code>s</code> 有两个不同的字符（<code>'a'</code> 和 <code>'b'</code>），它们的出现频率分别为 2 和 2。</li>\n\t<li>由于最多可以有 <code>k = 2</code> 个不同字符，不需要删除任何字符。因此，答案是 0。</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">s = \"yyyzz\", k = 1</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">2</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li><code>s</code> 有两个不同的字符（<code>'y'</code> 和 <code>'z'</code>），它们的出现频率分别为 3 和 2。</li>\n\t<li>由于最多只能有 <code>k = 1</code> 个不同字符，需要删除某一个字符的所有出现。</li>\n\t<li>删除所有 <code>'z'</code> 后，结果字符串中的不同字符数最多为 <code>k</code>。因此，答案是 2。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 16</code></li>\n\t<li><code>1 &lt;= k &lt;= 16</code></li>\n\t<li><code>s</code> 仅由小写英文字母组成。</li>\n</ul>\n\n<p>&nbsp;</p>\n",
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                "Compute the frequency of each character in <code>s</code> and collect these into a list <code>counts</code>.",
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target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 2.1.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.85.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a>\\u3001<a href=\\\"https:\\/\\/crates.io\\/crates\\/regex\\\" target=\\\"_blank\\\">regex<\\/a> \\u548c <a href=\\\"https:\\/\\/crates.io\\/crates\\/itertools\\\" target=\\\"_blank\\\">itertools<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.7.3<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2024<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" 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target=\\\"_blank\\\">\\u300c\\u4ed3\\u9889\\u7f16\\u7a0b\\u8bed\\u8a00\\u5f00\\u53d1\\u6307\\u5357\\u300d<\\/a><\\/p>\"]}",
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