mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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190 lines
26 KiB
JSON
190 lines
26 KiB
JSON
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"title": "Minimum Cost to Make Arrays Identical",
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"content": "<p>You are given two integer arrays <code>arr</code> and <code>brr</code> of length <code>n</code>, and an integer <code>k</code>. You can perform the following operations on <code>arr</code> <em>any</em> number of times:</p>\n\n<ul>\n\t<li>Split <code>arr</code> into <em>any</em> number of <strong>contiguous</strong> <span data-keyword=\"subarray-nonempty\">subarrays</span> and rearrange these subarrays in <em>any order</em>. This operation has a fixed cost of <code>k</code>.</li>\n\t<li>\n\t<p>Choose any element in <code>arr</code> and add or subtract a positive integer <code>x</code> to it. The cost of this operation is <code>x</code>.</p>\n\t</li>\n</ul>\n\n<p>Return the <strong>minimum </strong>total cost to make <code>arr</code> <strong>equal</strong> to <code>brr</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">arr = [-7,9,5], brr = [7,-2,-5], k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">13</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Split <code>arr</code> into two contiguous subarrays: <code>[-7]</code> and <code>[9, 5]</code> and rearrange them as <code>[9, 5, -7]</code>, with a cost of 2.</li>\n\t<li>Subtract 2 from element <code>arr[0]</code>. The array becomes <code>[7, 5, -7]</code>. The cost of this operation is 2.</li>\n\t<li>Subtract 7 from element <code>arr[1]</code>. The array becomes <code>[7, -2, -7]</code>. The cost of this operation is 7.</li>\n\t<li>Add 2 to element <code>arr[2]</code>. The array becomes <code>[7, -2, -5]</code>. The cost of this operation is 2.</li>\n</ul>\n\n<p>The total cost to make the arrays equal is <code>2 + 2 + 7 + 2 = 13</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">arr = [2,1], brr = [2,1], k = 0</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">0</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Since the arrays are already equal, no operations are needed, and the total cost is 0.</p>\n</div>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= arr.length == brr.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= k <= 2 * 10<sup>10</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= arr[i] <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= brr[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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"translatedTitle": "将数组变相同的最小代价",
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"translatedContent": "<p>给你两个长度都为 <code>n</code> 的整数数组 <code>arr</code> 和 <code>brr</code> 以及一个整数 <code>k</code> 。你可以对 <code>arr</code> 执行以下操作任意次:</p>\n\n<ul>\n\t<li>将 <code>arr</code> 分割成若干个 <strong>连续的</strong> 子数组,并将这些子数组按任意顺序重新排列。这个操作的代价为 <code>k</code> 。</li>\n\t<li>\n\t<p>选择 <code>arr</code> 中的任意一个元素,将它增加或者减少一个正整数 <code>x</code> 。这个操作的代价为 <code>x</code> 。</p>\n\t</li>\n</ul>\n\n<p>请你返回将 <code>arr</code> 变为 <code>brr</code> 的 <strong>最小</strong> 总代价。</p>\n\n<p><strong>子数组</strong> 是一个数组中一段连续 <strong>非空</strong> 的元素序列。</p>\n\n<p> </p>\n\n<p><strong class=\"example\">示例 1:</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入:</b>arr = [-7,9,5], brr = [7,-2,-5], k = 2</span></p>\n\n<p><span class=\"example-io\"><b>输出:</b>13</span></p>\n\n<p><b>解释:</b></p>\n\n<ul>\n\t<li>将 <code>arr</code> 分割成两个连续子数组:<code>[-7]</code> 和 <code>[9, 5]</code> 然后将它们重新排列成 <code>[9, 5, -7]</code> ,代价为 2 。</li>\n\t<li>将 <code>arr[0]</code> 减小 2 ,数组变为 <code>[7, 5, -7]</code> ,操作代价为 2 。</li>\n\t<li>将 <code>arr[1]</code> 减小 7 ,数组变为 <code>[7, -2, -7]</code> ,操作代价为 7 。</li>\n\t<li>将 <code>arr[2]</code> 增加 2 ,数组变为 <code>[7, -2, -5]</code> ,操作代价为 2 。</li>\n</ul>\n\n<p>将两个数组变相等的总代价为 <code>2 + 2 + 7 + 2 = 13</code> 。</p>\n</div>\n\n<p><strong class=\"example\">示例 2:</strong></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入:</b>arr = [2,1], brr = [2,1], k = 0</span></p>\n\n<p><span class=\"example-io\"><b>输出:</b>0</span></p>\n\n<p><b>解释:</b></p>\n\n<p>由于数组已经相等,不需要进行任何操作,所以总代价为 0 。</p>\n</div>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>1 <= arr.length == brr.length <= 10<sup>5</sup></code></li>\n\t<li><code>0 <= k <= 2 * 10<sup>10</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= arr[i] <= 10<sup>5</sup></code></li>\n\t<li><code>-10<sup>5</sup> <= brr[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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"What does Operation 1 (rearranging subarrays) actually accomplish?",
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