leetcode-problemset/leetcode-cn/originData/maximum-manhattan-distance-after-k-changes.json

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        "question": {
            "questionId": "3754",
            "questionFrontendId": "3443",
            "categoryTitle": "Algorithms",
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            "title": "Maximum Manhattan Distance After K Changes",
            "titleSlug": "maximum-manhattan-distance-after-k-changes",
            "content": "<p>You are given a string <code>s</code> consisting of the characters <code>&#39;N&#39;</code>, <code>&#39;S&#39;</code>, <code>&#39;E&#39;</code>, and <code>&#39;W&#39;</code>, where <code>s[i]</code> indicates movements in an infinite grid:</p>\n\n<ul>\n\t<li><code>&#39;N&#39;</code> : Move north by 1 unit.</li>\n\t<li><code>&#39;S&#39;</code> : Move south by 1 unit.</li>\n\t<li><code>&#39;E&#39;</code> : Move east by 1 unit.</li>\n\t<li><code>&#39;W&#39;</code> : Move west by 1 unit.</li>\n</ul>\n\n<p>Initially, you are at the origin <code>(0, 0)</code>. You can change <strong>at most</strong> <code>k</code> characters to any of the four directions.</p>\n\n<p>Find the <strong>maximum</strong> <strong>Manhattan distance</strong> from the origin that can be achieved <strong>at any time</strong> while performing the movements <strong>in order</strong>.</p>\nThe <strong>Manhattan Distance</strong> between two cells <code>(x<sub>i</sub>, y<sub>i</sub>)</code> and <code>(x<sub>j</sub>, y<sub>j</sub>)</code> is <code>|x<sub>i</sub> - x<sub>j</sub>| + |y<sub>i</sub> - y<sub>j</sub>|</code>.\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;NWSE&quot;, k = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">3</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Change <code>s[2]</code> from <code>&#39;S&#39;</code> to <code>&#39;N&#39;</code>. The string <code>s</code> becomes <code>&quot;NWNE&quot;</code>.</p>\n\n<table style=\"border: 1px solid black;\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th style=\"border: 1px solid black;\">Movement</th>\n\t\t\t<th style=\"border: 1px solid black;\">Position (x, y)</th>\n\t\t\t<th style=\"border: 1px solid black;\">Manhattan Distance</th>\n\t\t\t<th style=\"border: 1px solid black;\">Maximum</th>\n\t\t</tr>\n\t</thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">s[0] == &#39;N&#39;</td>\n\t\t\t<td style=\"border: 1px solid black;\">(0, 1)</td>\n\t\t\t<td style=\"border: 1px solid black;\">0 + 1 = 1</td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">s[1] == &#39;W&#39;</td>\n\t\t\t<td style=\"border: 1px solid black;\">(-1, 1)</td>\n\t\t\t<td style=\"border: 1px solid black;\">1 + 1 = 2</td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">s[2] == &#39;N&#39;</td>\n\t\t\t<td style=\"border: 1px solid black;\">(-1, 2)</td>\n\t\t\t<td style=\"border: 1px solid black;\">1 + 2 = 3</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">s[3] == &#39;E&#39;</td>\n\t\t\t<td style=\"border: 1px solid black;\">(0, 2)</td>\n\t\t\t<td style=\"border: 1px solid black;\">0 + 2 = 2</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t</tr>\n\t</tbody>\n</table>\n\n<p>The maximum Manhattan distance from the origin that can be achieved is 3. Hence, 3 is the output.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">s = &quot;NSWWEW&quot;, k = 3</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">6</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>Change <code>s[1]</code> from <code>&#39;S&#39;</code> to <code>&#39;N&#39;</code>, and <code>s[4]</code> from <code>&#39;E&#39;</code> to <code>&#39;W&#39;</code>. The string <code>s</code> becomes <code>&quot;NNWWWW&quot;</code>.</p>\n\n<p>The maximum Manhattan distance from the origin that can be achieved is 6. Hence, 6 is the output.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= s.length</code></li>\n\t<li><code>s</code> consists of only <code>&#39;N&#39;</code>, <code>&#39;S&#39;</code>, <code>&#39;E&#39;</code>, and <code>&#39;W&#39;</code>.</li>\n</ul>\n",
            "translatedTitle": "K 次修改后的最大曼哈顿距离",
            "translatedContent": "<p>给你一个由字符 <code>'N'</code>、<code>'S'</code>、<code>'E'</code> 和 <code>'W'</code> 组成的字符串 <code>s</code>，其中 <code>s[i]</code> 表示在无限网格中的移动操作：</p>\n\n<ul>\n\t<li><code>'N'</code>：向北移动 1 个单位。</li>\n\t<li><code>'S'</code>：向南移动 1 个单位。</li>\n\t<li><code>'E'</code>：向东移动 1 个单位。</li>\n\t<li><code>'W'</code>：向西移动 1 个单位。</li>\n</ul>\n\n<p>初始时，你位于原点 <code>(0, 0)</code>。你 <strong>最多</strong> 可以修改 <code>k</code> 个字符为任意四个方向之一。</p>\n\n<p>请找出在 <strong>按顺序</strong> 执行所有移动操作过程中的 <strong>任意时刻</strong> ，所能达到的离原点的&nbsp;<strong>最大曼哈顿距离&nbsp;</strong>。</p>\n\n<p><strong>曼哈顿距离&nbsp;</strong>定义为两个坐标点 <code>(x<sub>i</sub>, y<sub>i</sub>)</code> 和 <code>(x<sub>j</sub>, y<sub>j</sub>)</code> 的横向距离绝对值与纵向距离绝对值之和，即 <code>|x<sub>i</sub> - x<sub>j</sub>| + |y<sub>i</sub> - y<sub>j</sub>|</code>。</p>\n\n<p>&nbsp;</p>\n\n<p><b>示例 1：</b></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>s = \"NWSE\", k = 1</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>3</span></p>\n\n<p><b>解释：</b></p>\n\n<p>将&nbsp;<code>s[2]</code>&nbsp;从&nbsp;<code>'S'</code>&nbsp;改为&nbsp;<code>'N'</code> ，字符串&nbsp;<code>s</code>&nbsp;变为&nbsp;<code>\"NWNE\"</code> 。</p>\n\n<table style=\"border: 1px solid black;\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th style=\"border: 1px solid black;\">移动操作</th>\n\t\t\t<th style=\"border: 1px solid black;\">位置 (x, y)</th>\n\t\t\t<th style=\"border: 1px solid black;\">曼哈顿距离</th>\n\t\t\t<th style=\"border: 1px solid black;\">最大值</th>\n\t\t</tr>\n\t</thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">s[0] == 'N'</td>\n\t\t\t<td style=\"border: 1px solid black;\">(0, 1)</td>\n\t\t\t<td style=\"border: 1px solid black;\">0 + 1 = 1</td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">s[1] == 'W'</td>\n\t\t\t<td style=\"border: 1px solid black;\">(-1, 1)</td>\n\t\t\t<td style=\"border: 1px solid black;\">1 + 1 = 2</td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">s[2] == 'N'</td>\n\t\t\t<td style=\"border: 1px solid black;\">(-1, 2)</td>\n\t\t\t<td style=\"border: 1px solid black;\">1 + 2 = 3</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\">s[3] == 'E'</td>\n\t\t\t<td style=\"border: 1px solid black;\">(0, 2)</td>\n\t\t\t<td style=\"border: 1px solid black;\">0 + 2 = 2</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t</tr>\n\t</tbody>\n</table>\n\n<p>执行移动操作过程中，距离原点的最大曼哈顿距离是 3 。</p>\n</div>\n\n<p><b>示例 2：</b></p>\n\n<div class=\"example-block\">\n<p><span class=\"example-io\"><b>输入：</b>s = \"NSWWEW\", k = 3</span></p>\n\n<p><span class=\"example-io\"><b>输出：</b>6</span></p>\n\n<p><b>解释：</b></p>\n\n<p>将&nbsp;<code>s[1]</code>&nbsp;从&nbsp;<code>'S'</code>&nbsp;改为&nbsp;<code>'N'</code> ，将&nbsp;<code>s[4]</code>&nbsp;从&nbsp;<code>'E'</code>&nbsp;改为&nbsp;<code>'W'</code> 。字符串&nbsp;<code>s</code>&nbsp;变为&nbsp;<code>\"NNWWWW\"</code>&nbsp;。</p>\n\n<p>执行移动操作过程中，距离原点的最大曼哈顿距离是 6&nbsp;。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><b>提示：</b></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= s.length</code></li>\n\t<li><code>s</code>&nbsp;仅由&nbsp;<code>'N'</code>、<code>'S'</code>、<code>'E'</code>&nbsp;和&nbsp;<code>'W'</code> 。</li>\n</ul>\n",
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<code>use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n    int id;            \\/* we'll use this field as the key *\\/\\r\\n    char name[10];\\r\\n    UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry 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target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u4f7f\\u7528\\u7684\\u662f JetBrains \\u63d0\\u4f9b\\u7684 experimental compiler\\u3002\\u5982\\u679c\\u60a8\\u8ba4\\u4e3a\\u60a8\\u9047\\u5230\\u4e86\\u7f16\\u8bd1\\u5668\\u76f8\\u5173\\u7684\\u95ee\\u9898\\uff0c\\u8bf7\\u5411\\u6211\\u4eec\\u53cd\\u9988<\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.79.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a> \\u548c <a href=\\\"https:\\/\\/crates.io\\/crates\\/regex\\\" target=\\\"_blank\\\">regex<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.1.6<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2022<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/blob\\/v5\\/README.md\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@5.4.0<\\/a>\\uff0c<a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/v4.2.3\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.3<\\/a> \\u4ee5\\u53ca <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/deque\\/tree\\/v1.0.4\\\" target=\\\"_blank\\\"> datastructures-js\\/deque@1.0.4<\\/a>\\u3002<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.15<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 26\"],\"elixir\":[\"Elixir\",\"Elixir 1.17 with Erlang\\/OTP 26\"],\"dart\":[\"Dart\",\"<p>Dart 3.2\\u3002\\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/pub.dev\\/packages\\/collection\\/versions\\/1.18.0\\\" target=\\\"_blank\\\">collection<\\/a> \\u5305<\\/p>\\r\\n\\r\\n<p>\\u60a8\\u7684\\u4ee3\\u7801\\u5c06\\u4f1a\\u88ab\\u4e0d\\u7f16\\u8bd1\\u76f4\\u63a5\\u8fd0\\u884c<\\/p>\"],\"cangjie\":[\"Cangjie\",\"<p>\\u7248\\u672c\\uff1a0.53.11 (cjnative)<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u53c2\\u6570\\uff1a<code>-O2 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