leetcode-problemset/leetcode-cn/originData/majority-element-ii.json

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            "categoryTitle": "Algorithms",
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            "title": "Majority Element II",
            "titleSlug": "majority-element-ii",
            "content": "<p>Given an integer array of size <code>n</code>, find all elements that appear more than <code>&lfloor; n/3 &rfloor;</code> times.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,2,3]\n<strong>Output:</strong> [3]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1]\n<strong>Output:</strong> [1]\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2]\n<strong>Output:</strong> [1,2]\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong> Could you solve the problem in linear time and in <code>O(1)</code> space?</p>\n",
            "translatedTitle": "多数元素 II",
            "translatedContent": "<p>给定一个大小为&nbsp;<em>n&nbsp;</em>的整数数组，找出其中所有出现超过&nbsp;<code>⌊ n/3 ⌋</code>&nbsp;次的元素。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [3,2,3]\n<strong>输出：</strong>[3]</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1]\n<strong>输出：</strong>[1]\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2]\n<strong>输出：</strong>[1,2]</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>-10<sup>9</sup> &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong>尝试设计时间复杂度为 O(n)、空间复杂度为 O(1)的算法解决此问题。</p>\n",
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                    "code": "class Solution(object):\n    def majorityElement(self, nums):\n        \"\"\"\n        :type nums: List[int]\n        :rtype: List[int]\n        \"\"\"\n        ",
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            "hints": [
                "Think about the possible number of elements that can appear more than ⌊ n/3 ⌋ times in the array.",
                "It can be at most two. Why?",
                "Consider using Boyer-Moore Voting Algorithm, which is efficient for finding elements that appear more than a certain threshold."
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