leetcode-problemset/leetcode-cn/originData/longest-common-prefix-between-adjacent-strings-after-removals.json

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        "question": {
            "questionId": "3800",
            "questionFrontendId": "3598",
            "categoryTitle": "Algorithms",
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            "title": "Longest Common Prefix Between Adjacent Strings After Removals",
            "titleSlug": "longest-common-prefix-between-adjacent-strings-after-removals",
            "content": "<p>You are given an array of strings <code>words</code>. For each index <code>i</code> in the range <code>[0, words.length - 1]</code>, perform the following steps:</p>\n\n<ul>\n\t<li>Remove the element at index <code>i</code> from the <code>words</code> array.</li>\n\t<li>Compute the <strong>length</strong> of the <strong>longest common <span data-keyword=\"string-prefix\">prefix</span></strong> among all <strong>adjacent</strong> pairs in the modified array.</li>\n</ul>\n\n<p>Return an array <code>answer</code>, where <code>answer[i]</code> is the length of the longest common prefix between the adjacent pairs after removing the element at index <code>i</code>. If <strong>no</strong> adjacent pairs remain or if <strong>none</strong> share a common prefix, then <code>answer[i]</code> should be 0.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">words = [&quot;jump&quot;,&quot;run&quot;,&quot;run&quot;,&quot;jump&quot;,&quot;run&quot;]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[3,0,0,3,3]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Removing index 0:\n\t<ul>\n\t\t<li><code>words</code> becomes <code>[&quot;run&quot;, &quot;run&quot;, &quot;jump&quot;, &quot;run&quot;]</code></li>\n\t\t<li>Longest adjacent pair is <code>[&quot;run&quot;, &quot;run&quot;]</code> having a common prefix <code>&quot;run&quot;</code> (length 3)</li>\n\t</ul>\n\t</li>\n\t<li>Removing index 1:\n\t<ul>\n\t\t<li><code>words</code> becomes <code>[&quot;jump&quot;, &quot;run&quot;, &quot;jump&quot;, &quot;run&quot;]</code></li>\n\t\t<li>No adjacent pairs share a common prefix (length 0)</li>\n\t</ul>\n\t</li>\n\t<li>Removing index 2:\n\t<ul>\n\t\t<li><code>words</code> becomes <code>[&quot;jump&quot;, &quot;run&quot;, &quot;jump&quot;, &quot;run&quot;]</code></li>\n\t\t<li>No adjacent pairs share a common prefix (length 0)</li>\n\t</ul>\n\t</li>\n\t<li>Removing index 3:\n\t<ul>\n\t\t<li><code>words</code> becomes <code>[&quot;jump&quot;, &quot;run&quot;, &quot;run&quot;, &quot;run&quot;]</code></li>\n\t\t<li>Longest adjacent pair is <code>[&quot;run&quot;, &quot;run&quot;]</code> having a common prefix <code>&quot;run&quot;</code> (length 3)</li>\n\t</ul>\n\t</li>\n\t<li>Removing index 4:\n\t<ul>\n\t\t<li>words becomes <code>[&quot;jump&quot;, &quot;run&quot;, &quot;run&quot;, &quot;jump&quot;]</code></li>\n\t\t<li>Longest adjacent pair is <code>[&quot;run&quot;, &quot;run&quot;]</code> having a common prefix <code>&quot;run&quot;</code> (length 3)</li>\n\t</ul>\n\t</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">words = [&quot;dog&quot;,&quot;racer&quot;,&quot;car&quot;]</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">[0,0,0]</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>Removing any index results in an answer of 0.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>words[i]</code> consists of lowercase English letters.</li>\n\t<li>The sum of <code>words[i].length</code> is smaller than or equal <code>10<sup>5</sup></code>.</li>\n</ul>\n",
            "translatedTitle": "相邻字符串之间的最长公共前缀",
            "translatedContent": "<p>给你一个字符串数组 <code>words</code>，对于范围 <code>[0, words.length - 1]</code> 内的每个下标&nbsp;<code>i</code>，执行以下步骤：</p>\n\n<ul>\n\t<li>从 <code>words</code> 数组中移除下标&nbsp;<code>i</code> 处的元素。</li>\n\t<li>计算修改后的数组中所有&nbsp;<strong>相邻对&nbsp;</strong>之间的&nbsp;<strong>最长公共前缀&nbsp;</strong>的长度。</li>\n</ul>\n\n<p>返回一个数组 <code>answer</code>，其中 <code>answer[i]</code> 是移除下标&nbsp;<code>i</code> 后，相邻对之间最长公共前缀的长度。如果 <strong>不存在&nbsp;</strong>相邻对，或者&nbsp;<strong>不存在&nbsp;</strong>公共前缀，则 <code>answer[i]</code> 应为 0。</p>\n\n<p>字符串的前缀是从字符串的开头开始延伸到任意位置的子字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">words = [\"jump\",\"run\",\"run\",\"jump\",\"run\"]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">[3,0,0,3,3]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>移除下标&nbsp;0：\n\t<ul>\n\t\t<li><code>words</code> 变为 <code>[\"run\", \"run\", \"jump\", \"run\"]</code></li>\n\t\t<li>最长的相邻对是 <code>[\"run\", \"run\"]</code>，其公共前缀为 <code>\"run\"</code>（长度为 3）</li>\n\t</ul>\n\t</li>\n\t<li>移除下标&nbsp;1：\n\t<ul>\n\t\t<li><code>words</code> 变为 <code>[\"jump\", \"run\", \"jump\", \"run\"]</code></li>\n\t\t<li>没有相邻对有公共前缀（长度为 0）</li>\n\t</ul>\n\t</li>\n\t<li>移除下标&nbsp;2：\n\t<ul>\n\t\t<li><code>words</code> 变为 <code>[\"jump\", \"run\", \"jump\", \"run\"]</code></li>\n\t\t<li>没有相邻对有公共前缀（长度为 0）</li>\n\t</ul>\n\t</li>\n\t<li>移除下标&nbsp;3：\n\t<ul>\n\t\t<li><code>words</code> 变为 <code>[\"jump\", \"run\", \"run\", \"run\"]</code></li>\n\t\t<li>最长的相邻对是 <code>[\"run\", \"run\"]</code>，其公共前缀为 <code>\"run\"</code>（长度为 3）</li>\n\t</ul>\n\t</li>\n\t<li>移除下标&nbsp;4：\n\t<ul>\n\t\t<li><code>words</code> 变为 <code>[\"jump\", \"run\", \"run\", \"jump\"]</code></li>\n\t\t<li>最长的相邻对是 <code>[\"run\", \"run\"]</code>，其公共前缀为 <code>\"run\"</code>（长度为 3）</li>\n\t</ul>\n\t</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">words = [\"dog\",\"racer\",\"car\"]</span></p>\n\n<p><strong>输出：</strong> <span class=\"example-io\">[0,0,0]</span></p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>移除任意下标都会导致答案为 0。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= words.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>words[i]</code> 仅由小写英文字母组成。</li>\n\t<li><code>words[i]</code> 的长度总和不超过 <code>10<sup>5</sup></code>。</li>\n</ul>\n",
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target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 2.1.10<\\/code><\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.85.0<\\/code>\\uff0c\\u4f7f\\u7528 edition 2021\\u3002<\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a>\\u3001<a href=\\\"https:\\/\\/crates.io\\/crates\\/regex\\\" target=\\\"_blank\\\">regex<\\/a> \\u548c <a href=\\\"https:\\/\\/crates.io\\/crates\\/itertools\\\" target=\\\"_blank\\\">itertools<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.7.3<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2024<\\/p>\\r\\n\\r\\n<p><a 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target=\\\"_blank\\\">\\u300c\\u4ed3\\u9889\\u7f16\\u7a0b\\u8bed\\u8a00\\u5f00\\u53d1\\u6307\\u5357\\u300d<\\/a><\\/p>\"]}",
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