leetcode-problemset/leetcode-cn/originData/largest-values-from-labels.json

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        "question": {
            "questionId": "1169",
            "questionFrontendId": "1090",
            "categoryTitle": "Algorithms",
            "boundTopicId": 8957,
            "title": "Largest Values From Labels",
            "titleSlug": "largest-values-from-labels",
            "content": "<p>You are given <code>n</code> item&#39;s value and label as two integer arrays <code>values</code> and <code>labels</code>. You are also given two integers <code>numWanted</code> and <code>useLimit</code>.</p>\n\n<p>Your task is to find a subset of items with the <strong>maximum sum</strong> of their values such that:</p>\n\n<ul>\n\t<li>The number of items is <strong>at most</strong> <code>numWanted</code>.</li>\n\t<li>The number of items with the same label is <strong>at most</strong> <code>useLimit</code>.</li>\n</ul>\n\n<p>Return the maximum sum.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">values = [5,4,3,2,1], labels = [1,1,2,2,3], numWanted = 3, useLimit = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">9</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The subset chosen is the first, third, and fifth items with the sum of values 5 + 3 + 1.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">values = [5,4,3,2,1], labels = [1,3,3,3,2], numWanted = 3, useLimit = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">12</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The subset chosen is the first, second, and third items with the sum of values 5 + 4 + 3.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">values = [9,8,8,7,6], labels = [0,0,0,1,1], numWanted = 3, useLimit = 1</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">16</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The subset chosen is the first and fourth items with the sum of values 9 + 7.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == values.length == labels.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= values[i], labels[i] &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= numWanted, useLimit &lt;= n</code></li>\n</ul>\n",
            "translatedTitle": "受标签影响的最大值",
            "translatedContent": "<p>以两个整数数组 &nbsp;<code>values</code>&nbsp;和 <code>labels</code>&nbsp;给定&nbsp;<code>n</code>&nbsp;个项的值和标签，并且给出两个整数&nbsp;<code>numWanted</code>&nbsp;和 <code>useLimit</code> 。</p>\n\n<p>你的任务是从这些项中找到一个值的和 <strong>最大</strong> 的子集使得：</p>\n\n<ul>\n\t<li>项的数量 <strong>最多</strong> 为&nbsp;<code>numWanted</code>。</li>\n\t<li>相同标签的项的数量&nbsp;<strong>最多 </strong>为&nbsp;<code>useLimit</code>。</li>\n</ul>\n\n<p>返回最大的和。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">values = [5,4,3,2,1], labels = [1,1,2,2,3], numWanted = 3, useLimit = 1</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">9</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>选择的子集是第一个、第三个和第五个项，其值之和为 5 + 3 + 1。</p>\n</div>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">values = [5,4,3,2,1], labels = [1,3,3,3,2], numWanted = 3, useLimit = 2</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">12</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>选择的子集是第一个、第二个和第三个项，其值之和为 5 + 4 + 3。</p>\n</div>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong><span class=\"example-io\">values = [9,8,8,7,6], labels = [0,0,0,1,1], numWanted = 3, useLimit = 1</span></p>\n\n<p><strong>输出：</strong><span class=\"example-io\">16</span></p>\n\n<p><strong>解释：</strong></p>\n\n<p>选择的子集是第一个和第四个项，其值之和为 9 + 7。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == values.length == labels.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>0 &lt;= values[i], labels[i] &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= numWanted, useLimit &lt;= n</code></li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    int largestValsFromLabels(vector<int>& values, vector<int>& labels, int numWanted, int useLimit) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def largestValsFromLabels(self, values, labels, numWanted, useLimit):\n        \"\"\"\n        :type values: List[int]\n        :type labels: List[int]\n        :type numWanted: int\n        :type useLimit: int\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "int largestValsFromLabels(int* values, int valuesSize, int* labels, int labelsSize, int numWanted, int useLimit) {\n    \n}",
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                    "code": "public class Solution {\n    public int LargestValsFromLabels(int[] values, int[] labels, int numWanted, int useLimit) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number[]} values\n * @param {number[]} labels\n * @param {number} numWanted\n * @param {number} useLimit\n * @return {number}\n */\nvar largestValsFromLabels = function(values, labels, numWanted, useLimit) {\n    \n};",
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                    "code": "class Solution {\n    func largestValsFromLabels(_ values: [Int], _ labels: [Int], _ numWanted: Int, _ useLimit: Int) -> Int {\n        \n    }\n}",
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                    "code": "class Solution {\n    fun largestValsFromLabels(values: IntArray, labels: IntArray, numWanted: Int, useLimit: Int): Int {\n        \n    }\n}",
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                    "code": "# @param {Integer[]} values\n# @param {Integer[]} labels\n# @param {Integer} num_wanted\n# @param {Integer} use_limit\n# @return {Integer}\ndef largest_vals_from_labels(values, labels, num_wanted, use_limit)\n    \nend",
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                    "code": "impl Solution {\n    pub fn largest_vals_from_labels(values: Vec<i32>, labels: Vec<i32>, num_wanted: i32, use_limit: i32) -> i32 {\n        \n    }\n}",
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                    "code": "-spec largest_vals_from_labels(Values :: [integer()], Labels :: [integer()], NumWanted :: integer(), UseLimit :: integer()) -> integer().\nlargest_vals_from_labels(Values, Labels, NumWanted, UseLimit) ->\n  .",
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                    "code": "defmodule Solution do\n  @spec largest_vals_from_labels(values :: [integer], labels :: [integer], num_wanted :: integer, use_limit :: integer) :: integer\n  def largest_vals_from_labels(values, labels, num_wanted, use_limit) do\n    \n  end\nend",
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                    "code": "class Solution {\n    func largestValsFromLabels(values: Array<Int64>, labels: Array<Int64>, numWanted: Int64, useLimit: Int64): Int64 {\n\n    }\n}",
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                "Consider the items in order from largest to smallest value, and greedily take the items if they fall under the use_limit.  We can keep track of how many items of each label are used by using a hash table."
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