leetcode-problemset/leetcode-cn/originData/insert-interval.json

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        "question": {
            "questionId": "57",
            "questionFrontendId": "57",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1525,
            "title": "Insert Interval",
            "titleSlug": "insert-interval",
            "content": "<p>You are given an array of non-overlapping intervals <code>intervals</code> where <code>intervals[i] = [start<sub>i</sub>, end<sub>i</sub>]</code> represent the start and the end of the <code>i<sup>th</sup></code> interval and <code>intervals</code> is sorted in ascending order by <code>start<sub>i</sub></code>. You are also given an interval <code>newInterval = [start, end]</code> that represents the start and end of another interval.</p>\n\n<p>Insert <code>newInterval</code> into <code>intervals</code> such that <code>intervals</code> is still sorted in ascending order by <code>start<sub>i</sub></code> and <code>intervals</code> still does not have any overlapping intervals (merge overlapping intervals if necessary).</p>\n\n<p>Return <code>intervals</code><em> after the insertion</em>.</p>\n\n<p><strong>Note</strong> that you don&#39;t need to modify <code>intervals</code> in-place. You can make a new array and return it.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[1,3],[6,9]], newInterval = [2,5]\n<strong>Output:</strong> [[1,5],[6,9]]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]\n<strong>Output:</strong> [[1,2],[3,10],[12,16]]\n<strong>Explanation:</strong> Because the new interval [4,8] overlaps with [3,5],[6,7],[8,10].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= intervals.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>0 &lt;= start<sub>i</sub> &lt;= end<sub>i</sub> &lt;= 10<sup>5</sup></code></li>\n\t<li><code>intervals</code> is sorted by <code>start<sub>i</sub></code> in <strong>ascending</strong> order.</li>\n\t<li><code>newInterval.length == 2</code></li>\n\t<li><code>0 &lt;= start &lt;= end &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "插入区间",
            "translatedContent": "<p>给你一个<strong> 无重叠的</strong><em> ，</em>按照区间起始端点排序的区间列表 <code>intervals</code>，其中&nbsp;<code>intervals[i] = [start<sub>i</sub>, end<sub>i</sub>]</code>&nbsp;表示第&nbsp;<code>i</code>&nbsp;个区间的开始和结束，并且&nbsp;<code>intervals</code>&nbsp;按照&nbsp;<code>start<sub>i</sub></code>&nbsp;升序排列。同样给定一个区间&nbsp;<code>newInterval = [start, end]</code>&nbsp;表示另一个区间的开始和结束。</p>\n\n<p>在&nbsp;<code>intervals</code> 中插入区间&nbsp;<code>newInterval</code>，使得&nbsp;<code>intervals</code>&nbsp;依然按照&nbsp;<code>start<sub>i</sub></code>&nbsp;升序排列，且区间之间不重叠（如果有必要的话，可以合并区间）。</p>\n\n<p>返回插入之后的&nbsp;<code>intervals</code>。</p>\n\n<p><strong>注意</strong> 你不需要原地修改&nbsp;<code>intervals</code>。你可以创建一个新数组然后返回它。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,3],[6,9]], newInterval = [2,5]\n<strong>输出：</strong>[[1,5],[6,9]]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>intervals = [[1,2],[3,5],[6,7],[8,10],[12,16]], newInterval = [4,8]\n<strong>输出：</strong>[[1,2],[3,10],[12,16]]\n<strong>解释：</strong>这是因为新的区间 <code>[4,8]</code> 与 <code>[3,5],[6,7],[8,10]</code>&nbsp;重叠。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>0 &lt;= intervals.length &lt;= 10<sup>4</sup></code></li>\n\t<li><code>intervals[i].length == 2</code></li>\n\t<li><code>0 &lt;=&nbsp;start<sub>i</sub> &lt;=&nbsp;end<sub>i</sub> &lt;= 10<sup>5</sup></code></li>\n\t<li><code>intervals</code> 根据 <code>start<sub>i</sub></code> 按 <strong>升序</strong> 排列</li>\n\t<li><code>newInterval.length == 2</code></li>\n\t<li><code>0 &lt;=&nbsp;start &lt;=&nbsp;end &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                {
                    "lang": "C++",
                    "langSlug": "cpp",
                    "code": "class Solution {\npublic:\n    vector<vector<int>> insert(vector<vector<int>>& intervals, vector<int>& newInterval) {\n        \n    }\n};",
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                    "code": "class Solution {\n    public int[][] insert(int[][] intervals, int[] newInterval) {\n        \n    }\n}",
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                    "lang": "Python",
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                    "code": "class Solution(object):\n    def insert(self, intervals, newInterval):\n        \"\"\"\n        :type intervals: List[List[int]]\n        :type newInterval: List[int]\n        :rtype: List[List[int]]\n        \"\"\"\n        ",
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                    "code": "class Solution:\n    def insert(self, intervals: List[List[int]], newInterval: List[int]) -> List[List[int]]:\n        ",
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                    "code": "/**\n * Return an array of arrays of size *returnSize.\n * The sizes of the arrays are returned as *returnColumnSizes array.\n * Note: Both returned array and *columnSizes array must be malloced, assume caller calls free().\n */\nint** insert(int** intervals, int intervalsSize, int* intervalsColSize, int* newInterval, int newIntervalSize, int* returnSize, int** returnColumnSizes) {\n    \n}",
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                    "code": "public class Solution {\n    public int[][] Insert(int[][] intervals, int[] newInterval) {\n        \n    }\n}",
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                    "lang": "JavaScript",
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                    "code": "/**\n * @param {number[][]} intervals\n * @param {number[]} newInterval\n * @return {number[][]}\n */\nvar insert = function(intervals, newInterval) {\n    \n};",
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                    "code": "function insert(intervals: number[][], newInterval: number[]): number[][] {\n    \n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[][] $intervals\n     * @param Integer[] $newInterval\n     * @return Integer[][]\n     */\n    function insert($intervals, $newInterval) {\n        \n    }\n}",
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                    "code": "class Solution {\n    func insert(_ intervals: [[Int]], _ newInterval: [Int]) -> [[Int]] {\n        \n    }\n}",
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                    "lang": "Kotlin",
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                    "code": "class Solution {\n    fun insert(intervals: Array<IntArray>, newInterval: IntArray): Array<IntArray> {\n        \n    }\n}",
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                    "lang": "Dart",
                    "langSlug": "dart",
                    "code": "class Solution {\n  List<List<int>> insert(List<List<int>> intervals, List<int> newInterval) {\n    \n  }\n}",
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                    "lang": "Go",
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                    "code": "func insert(intervals [][]int, newInterval []int) [][]int {\n    \n}",
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                    "lang": "Ruby",
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                    "code": "# @param {Integer[][]} intervals\n# @param {Integer[]} new_interval\n# @return {Integer[][]}\ndef insert(intervals, new_interval)\n    \nend",
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                    "lang": "Scala",
                    "langSlug": "scala",
                    "code": "object Solution {\n    def insert(intervals: Array[Array[Int]], newInterval: Array[Int]): Array[Array[Int]] = {\n        \n    }\n}",
                    "__typename": "CodeSnippetNode"
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                {
                    "lang": "Rust",
                    "langSlug": "rust",
                    "code": "impl Solution {\n    pub fn insert(intervals: Vec<Vec<i32>>, new_interval: Vec<i32>) -> Vec<Vec<i32>> {\n        \n    }\n}",
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                    "code": "(define/contract (insert intervals newInterval)\n  (-> (listof (listof exact-integer?)) (listof exact-integer?) (listof (listof exact-integer?)))\n  )",
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                    "lang": "Erlang",
                    "langSlug": "erlang",
                    "code": "-spec insert(Intervals :: [[integer()]], NewInterval :: [integer()]) -> [[integer()]].\ninsert(Intervals, NewInterval) ->\n  .",
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                {
                    "lang": "Elixir",
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                    "code": "defmodule Solution do\n  @spec insert(intervals :: [[integer]], new_interval :: [integer]) :: [[integer]]\n  def insert(intervals, new_interval) do\n    \n  end\nend",
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                    "code": "class Solution {\n    func insert(intervals: Array<Array<Int64>>, newInterval: Array<Int64>): Array<Array<Int64>> {\n\n    }\n}",
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            "hints": [
                "Intervals Array is sorted. Can you use Binary Search to find the correct position to insert the new Interval.?",
                "Can you try merging the overlapping intervals while inserting the new interval?",
                "This can be done by comparing the end of the last interval with the start of the new interval and vice versa."
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            "sampleTestCase": "[[1,3],[6,9]]\n[2,5]",
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