leetcode-problemset/leetcode-cn/originData/coin-change.json

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            "title": "Coin Change",
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            "content": "<p>You are given an integer array <code>coins</code> representing coins of different denominations and an integer <code>amount</code> representing a total amount of money.</p>\n\n<p>Return <em>the fewest number of coins that you need to make up that amount</em>. If that amount of money cannot be made up by any combination of the coins, return <code>-1</code>.</p>\n\n<p>You may assume that you have an infinite number of each kind of coin.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> coins = [1,2,5], amount = 11\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> 11 = 5 + 5 + 1\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> coins = [2], amount = 3\n<strong>Output:</strong> -1\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> coins = [1], amount = 0\n<strong>Output:</strong> 0\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= coins.length &lt;= 12</code></li>\n\t<li><code>1 &lt;= coins[i] &lt;= 2<sup>31</sup> - 1</code></li>\n\t<li><code>0 &lt;= amount &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "零钱兑换",
            "translatedContent": "<p>给你一个整数数组 <code>coins</code> ，表示不同面额的硬币；以及一个整数 <code>amount</code> ，表示总金额。</p>\n\n<p>计算并返回可以凑成总金额所需的 <strong>最少的硬币个数</strong> 。如果没有任何一种硬币组合能组成总金额，返回&nbsp;<code>-1</code> 。</p>\n\n<p>你可以认为每种硬币的数量是无限的。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例&nbsp;1：</strong></p>\n\n<pre>\n<strong>输入：</strong>coins = <code>[1, 2, 5]</code>, amount = <code>11</code>\n<strong>输出：</strong><code>3</code> \n<strong>解释：</strong>11 = 5 + 5 + 1</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>coins = <code>[2]</code>, amount = <code>3</code>\n<strong>输出：</strong>-1</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>coins = [1], amount = 0\n<strong>输出：</strong>0\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= coins.length &lt;= 12</code></li>\n\t<li><code>1 &lt;= coins[i] &lt;= 2<sup>31</sup> - 1</code></li>\n\t<li><code>0 &lt;= amount &lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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