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{
"data": {
"question": {
"questionId": "1000299",
"questionFrontendId": "LCR 046",
"categoryTitle": "Algorithms",
"boundTopicId": 910293,
"title": "二叉树的右视图",
"titleSlug": "WNC0Lk",
"content": "<p>English description is not available for the problem. Please switch to Chinese.</p>\n",
"translatedTitle": "二叉树的右视图",
"translatedContent": "<p>给定一个二叉树的 <strong>根节点</strong> <code>root</code>,想象自己站在它的右侧,按照从顶部到底部的顺序,返回从右侧所能看到的节点值。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/02/14/tree.jpg\" style=\"width: 270px; \" /></p>\n\n<pre>\n<strong>输入:</strong>&nbsp;[1,2,3,null,5,null,4]\n<strong>输出:</strong>&nbsp;[1,3,4]\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>&nbsp;[1,null,3]\n<strong>输出:</strong>&nbsp;[1,3]\n</pre>\n\n<p><strong>示例 3</strong></p>\n\n<pre>\n<strong>输入:</strong>&nbsp;[]\n<strong>输出:</strong>&nbsp;[]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>二叉树的节点个数的范围是 <code>[0,100]</code></li>\n\t<li><meta charset=\"UTF-8\" /><code>-100&nbsp;&lt;= Node.val &lt;= 100</code>&nbsp;</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><meta charset=\"UTF-8\" />注意:本题与主站 199&nbsp;题相同:<a href=\"https://leetcode-cn.com/problems/binary-tree-right-side-view/\">https://leetcode-cn.com/problems/binary-tree-right-side-view/</a></p>\n",
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"difficulty": "Medium",
"likes": 51,
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"profileUrl": "/u/leetcode",
"avatarUrl": "https://assets.leetcode.cn/aliyun-lc-upload/uploaded_files/2021/03/73c9f099-abbe-4d94-853f-f8abffd459cd/leetcode.png",
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"translatedName": "树",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n vector<int> rightSideView(TreeNode* root) {\n\n }\n};",
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"langSlug": "java",
"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public List<Integer> rightSideView(TreeNode root) {\n\n }\n}",
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{
"lang": "Python",
"langSlug": "python",
"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def rightSideView(self, root):\n \"\"\"\n :type root: TreeNode\n :rtype: List[int]\n \"\"\"",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution:\n def rightSideView(self, root: TreeNode) -> List[int]:",
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{
"lang": "C",
"langSlug": "c",
"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\n\n\n/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nint* rightSideView(struct TreeNode* root, int* returnSize){\n\n}",
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"lang": "C#",
"langSlug": "csharp",
"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public IList<int> RightSideView(TreeNode root) {\n\n }\n}",
"__typename": "CodeSnippetNode"
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{
"lang": "JavaScript",
"langSlug": "javascript",
"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @return {number[]}\n */\nvar rightSideView = function(root) {\n\n};",
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{
"lang": "TypeScript",
"langSlug": "typescript",
"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction rightSideView(root: TreeNode | null): number[] {\n\n};",
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"lang": "PHP",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Integer[]\n */\n function rightSideView($root) {\n\n }\n}",
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"lang": "Swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func rightSideView(_ root: TreeNode?) -> [Int] {\n\n }\n}",
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{
"lang": "Kotlin",
"langSlug": "kotlin",
"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun rightSideView(root: TreeNode?): List<Int> {\n\n }\n}",
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{
"lang": "Go",
"langSlug": "golang",
"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc rightSideView(root *TreeNode) []int {\n\n}",
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"lang": "Ruby",
"langSlug": "ruby",
"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Integer[]}\ndef right_side_view(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def rightSideView(root: TreeNode): List[Int] = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn right_side_view(root: Option<Rc<RefCell<TreeNode>>>) -> Vec<i32> {\n\n }\n}",
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{
"lang": "Racket",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec right_side_view(Root :: #tree_node{} | null) -> [integer()].\nright_side_view(Root) ->\n .",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec right_side_view(root :: TreeNode.t | nil) :: [integer]\n def right_side_view(root) do\n\n end\nend",
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