leetcode-problemset/leetcode-cn/originData/time-needed-to-buy-tickets.json

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        "question": {
            "questionId": "2195",
            "questionFrontendId": "2073",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1097162,
            "title": "Time Needed to Buy Tickets",
            "titleSlug": "time-needed-to-buy-tickets",
            "content": "<p>There are <code>n</code> people in a line queuing to buy tickets, where the <code>0<sup>th</sup></code> person is at the <strong>front</strong> of the line and the <code>(n - 1)<sup>th</sup></code> person is at the <strong>back</strong> of the line.</p>\n\n<p>You are given a <strong>0-indexed</strong> integer array <code>tickets</code> of length <code>n</code> where the number of tickets that the <code>i<sup>th</sup></code> person would like to buy is <code>tickets[i]</code>.</p>\n\n<p>Each person takes <strong>exactly 1 second</strong> to buy a ticket. A person can only buy <strong>1 ticket at a time</strong> and has to go back to <strong>the end</strong> of the line (which happens <strong>instantaneously</strong>) in order to buy more tickets. If a person does not have any tickets left to buy, the person will <strong>leave </strong>the line.</p>\n\n<p>Return the <strong>time taken</strong> for the person <strong>initially</strong> at position <strong>k</strong><strong> </strong>(0-indexed) to finish buying tickets.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">tickets = [2,3,2], k = 2</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">6</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>The queue starts as [2,3,<u>2</u>], where the kth person is underlined.</li>\n\t<li>After the person at the front has bought a ticket, the queue becomes [3,<u>2</u>,1] at 1 second.</li>\n\t<li>Continuing this process, the queue becomes [<u>2</u>,1,2] at 2 seconds.</li>\n\t<li>Continuing this process, the queue becomes [1,2,<u>1</u>] at 3 seconds.</li>\n\t<li>Continuing this process, the queue becomes [2,<u>1</u>] at 4 seconds. Note: the person at the front left the queue.</li>\n\t<li>Continuing this process, the queue becomes [<u>1</u>,1] at 5 seconds.</li>\n\t<li>Continuing this process, the queue becomes [1] at 6 seconds. The kth person has bought all their tickets, so return 6.</li>\n</ul>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">tickets = [5,1,1,1], k = 0</span></p>\n\n<p><strong>Output:</strong> <span class=\"example-io\">8</span></p>\n\n<p><strong>Explanation:</strong></p>\n\n<ul>\n\t<li>The queue starts as [<u>5</u>,1,1,1], where the kth person is underlined.</li>\n\t<li>After the person at the front has bought a ticket, the queue becomes [1,1,1,<u>4</u>] at 1 second.</li>\n\t<li>Continuing this process for 3 seconds, the queue becomes [<u>4]</u> at 4 seconds.</li>\n\t<li>Continuing this process for 4 seconds, the queue becomes [] at 8 seconds. The kth person has bought all their tickets, so return 8.</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == tickets.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>1 &lt;= tickets[i] &lt;= 100</code></li>\n\t<li><code>0 &lt;= k &lt; n</code></li>\n</ul>\n",
            "translatedTitle": "买票需要的时间",
            "translatedContent": "<p>有 <code>n</code> 个人前来排队买票，其中第 <code>0</code> 人站在队伍 <strong>最前方</strong> ，第 <code>(n - 1)</code> 人站在队伍 <strong>最后方</strong> 。</p>\n\n<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>tickets</code> ，数组长度为 <code>n</code> ，其中第 <code>i</code> 人想要购买的票数为 <code>tickets[i]</code> 。</p>\n\n<p>每个人买票都需要用掉 <strong>恰好 1 秒</strong> 。一个人 <strong>一次只能买一张票</strong> ，如果需要购买更多票，他必须走到&nbsp; <strong>队尾</strong> 重新排队（<strong>瞬间 </strong>发生，不计时间）。如果一个人没有剩下需要买的票，那他将会 <strong>离开</strong> 队伍。</p>\n\n<p>返回位于位置 <code>k</code>（下标从 <strong>0</strong> 开始）的人完成买票需要的时间（以秒为单位）。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong>tickets = [2,3,2], k = 2</p>\n\n<p><strong>输出：</strong>6</p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>队伍一开始为 [2,3,2]，第 k 个人以下划线标识。</li>\n\t<li>在最前面的人买完票后，队伍在第 1 秒变成 [3,<u>2</u>,1]。</li>\n\t<li>继续这个过程，队伍在第 2 秒变为[<u>2</u>,1,2]。</li>\n\t<li>继续这个过程，队伍在第 3 秒变为[1,2,<u>1</u>]。</li>\n\t<li>继续这个过程，队伍在第 4 秒变为[2,<u>1</u>]。</li>\n\t<li>继续这个过程，队伍在第 5 秒变为[<u>1</u>,1]。</li>\n\t<li>继续这个过程，队伍在第 6 秒变为[1]。第 k 个人完成买票，所以返回 6。</li>\n</ul>\n</div>\n\n<p><strong>示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong>tickets = [5,1,1,1], k = 0</p>\n\n<p><strong>输出：</strong>8</p>\n\n<p><strong>解释：</strong></p>\n\n<ul>\n\t<li>队伍一开始为 [<u>5</u>,1,1,1]，第 k 个人以下划线标识。</li>\n\t<li>在最前面的人买完票后，队伍在第 1 秒变成 [1,1,1,<u>4</u>]。</li>\n\t<li>继续这个过程 3 秒，队伍在第 4&nbsp;秒变为[<u>4</u>]。</li>\n\t<li>继续这个过程 4 秒，队伍在第 8&nbsp;秒变为[]。第 k 个人完成买票，所以返回 8。</li>\n</ul>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == tickets.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 100</code></li>\n\t<li><code>1 &lt;= tickets[i] &lt;= 100</code></li>\n\t<li><code>0 &lt;= k &lt; n</code></li>\n</ul>\n",
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target=\\\"_blank\\\">sortedcontainers<\\/a> \\u5e93\\u3002<\\/p>\"],\"scala\":[\"Scala\",\"<p>\\u7248\\u672c\\uff1a<code>Scala 3.3.1<\\/code><\\/p>\"],\"kotlin\":[\"Kotlin\",\"<p>\\u7248\\u672c\\uff1a<code>Kotlin 1.9.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u6211\\u4eec\\u4f7f\\u7528\\u7684\\u662f JetBrains \\u63d0\\u4f9b\\u7684 experimental compiler\\u3002\\u5982\\u679c\\u60a8\\u8ba4\\u4e3a\\u60a8\\u9047\\u5230\\u4e86\\u7f16\\u8bd1\\u5668\\u76f8\\u5173\\u7684\\u95ee\\u9898\\uff0c\\u8bf7\\u5411\\u6211\\u4eec\\u53cd\\u9988<\\/p>\"],\"rust\":[\"Rust\",\"<p>\\u7248\\u672c\\uff1a<code>rust 1.79.0<\\/code><\\/p>\\r\\n\\r\\n<p>\\u652f\\u6301 crates.io \\u7684 <a href=\\\"https:\\/\\/crates.io\\/crates\\/rand\\\" target=\\\"_blank\\\">rand<\\/a> \\u548c <a href=\\\"https:\\/\\/crates.io\\/crates\\/regex\\\" target=\\\"_blank\\\">regex<\\/a><\\/p>\"],\"php\":[\"PHP\",\"<p><code>PHP 8.2<\\/code>.<\\/p>\\r\\n\\r\\n<p>With bcmath module.<\\/p>\"],\"typescript\":[\"TypeScript\",\"<p>TypeScript 5.1.6<\\/p>\\r\\n\\r\\n<p>Compile Options: --alwaysStrict --strictBindCallApply --strictFunctionTypes --target ES2022<\\/p>\\r\\n\\r\\n<p><a href=\\\"https:\\/\\/lodash.com\\\" target=\\\"_blank\\\">lodash.js<\\/a> \\u5e93\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5305\\u542b\\u3002<\\/p>\\r\\n\\r\\n<p> \\u5982\\u9700\\u4f7f\\u7528\\u961f\\u5217\\/\\u4f18\\u5148\\u961f\\u5217\\uff0c\\u60a8\\u53ef\\u4f7f\\u7528 <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/priority-queue\\/blob\\/v5\\/README.md\\\" target=\\\"_blank\\\"> datastructures-js\\/priority-queue@5.4.0<\\/a>\\uff0c<a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/queue\\/tree\\/v4.2.3\\\" target=\\\"_blank\\\"> datastructures-js\\/queue@4.2.3<\\/a> \\u4ee5\\u53ca <a href=\\\"https:\\/\\/github.com\\/datastructures-js\\/deque\\/tree\\/v1.0.4\\\" target=\\\"_blank\\\"> datastructures-js\\/deque@1.0.4<\\/a>\\u3002<\\/p>\"],\"racket\":[\"Racket\",\"<p><a href=\\\"https:\\/\\/docs.racket-lang.org\\/guide\\/performance.html#%28tech._c%29\\\" target=\\\"_blank\\\">Racket CS<\\/a> v8.15<\\/p>\\r\\n\\r\\n<p>\\u4f7f\\u7528 #lang racket<\\/p>\\r\\n\\r\\n<p>\\u5df2\\u9884\\u5148 (require data\\/gvector data\\/queue data\\/order data\\/heap). \\u82e5\\u9700\\u4f7f\\u7528\\u5176\\u5b83\\u6570\\u636e\\u7ed3\\u6784\\uff0c\\u53ef\\u81ea\\u884c require\\u3002<\\/p>\"],\"erlang\":[\"Erlang\",\"Erlang\\/OTP 26\"],\"elixir\":[\"Elixir\",\"Elixir 1.17 with Erlang\\/OTP 26\"],\"dart\":[\"Dart\",\"<p>Dart 3.2\\u3002\\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/pub.dev\\/packages\\/collection\\/versions\\/1.18.0\\\" target=\\\"_blank\\\">collection<\\/a> \\u5305<\\/p>\\r\\n\\r\\n<p>\\u60a8\\u7684\\u4ee3\\u7801\\u5c06\\u4f1a\\u88ab\\u4e0d\\u7f16\\u8bd1\\u76f4\\u63a5\\u8fd0\\u884c<\\/p>\"],\"cangjie\":[\"Cangjie\",\"<p>\\u7248\\u672c\\uff1a0.53.11 (cjnative)<\\/p>\\r\\n\\r\\n<p>\\u7f16\\u8bd1\\u53c2\\u6570\\uff1a<code>-O2 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