leetcode-problemset/leetcode-cn/originData/maximum-and-minimum-sums-of-at-most-size-k-subsequences.json

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            "title": "Maximum and Minimum Sums of at Most Size K Subsequences",
            "titleSlug": "maximum-and-minimum-sums-of-at-most-size-k-subsequences",
            "content": "<p>You are given an integer array <code>nums</code> and a positive integer <code>k</code>. Return the sum of the <strong>maximum</strong> and <strong>minimum</strong> elements of all <strong><span data-keyword=\"subsequence-sequence-nonempty\">subsequences</span></strong> of <code>nums</code> with <strong>at most</strong> <code>k</code> elements.</p>\n\n<p>Since the answer may be very large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,2,3], k = 2</span></p>\n\n<p><strong>Output:</strong> 24</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The subsequences of <code>nums</code> with at most 2 elements are:</p>\n\n<table style=\"border: 1px solid black;\">\n\t<tbody>\n\t\t<tr>\n\t\t\t<th style=\"border: 1px solid black;\"><b>Subsequence </b></th>\n\t\t\t<th style=\"border: 1px solid black;\">Minimum</th>\n\t\t\t<th style=\"border: 1px solid black;\">Maximum</th>\n\t\t\t<th style=\"border: 1px solid black;\">Sum</th>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[1]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[2]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[3]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t\t<td style=\"border: 1px solid black;\">6</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[1, 2]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[1, 3]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[2, 3]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t\t<td style=\"border: 1px solid black;\">5</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><strong>Final Total</strong></td>\n\t\t\t<td style=\"border: 1px solid black;\">&nbsp;</td>\n\t\t\t<td style=\"border: 1px solid black;\">&nbsp;</td>\n\t\t\t<td style=\"border: 1px solid black;\">24</td>\n\t\t</tr>\n\t</tbody>\n</table>\n\n<p>The output would be 24.</p>\n</div>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [5,0,6], k = 1</span></p>\n\n<p><strong>Output:</strong> 2<span class=\"example-io\">2</span></p>\n\n<p><strong>Explanation: </strong></p>\n\n<p>For subsequences with exactly 1 element, the minimum and maximum values are the element itself. Therefore, the total is <code>5 + 5 + 0 + 0 + 6 + 6 = 22</code>.</p>\n</div>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<div class=\"example-block\">\n<p><strong>Input:</strong> <span class=\"example-io\">nums = [1,1,1], k = 2</span></p>\n\n<p><strong>Output:</strong> 12</p>\n\n<p><strong>Explanation:</strong></p>\n\n<p>The subsequences <code>[1, 1]</code> and <code>[1]</code> each appear 3 times. For all of them, the minimum and maximum are both 1. Thus, the total is 12.</p>\n</div>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code><font face=\"monospace\">1 &lt;= k &lt;= min(70, nums.length)</font></code></li>\n</ul>\n",
            "translatedTitle": "最多 K 个元素的子序列的最值之和",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code> 和一个正整数 <code>k</code>，返回所有长度最多为 <code>k</code> 的 <strong>子序列</strong> 中&nbsp;<strong>最大值&nbsp;</strong>与&nbsp;<strong>最小值&nbsp;</strong>之和的总和。</p>\n\n<p><strong>非空子序列</strong>&nbsp;是指从另一个数组中删除一些或不删除任何元素（且不改变剩余元素的顺序）得到的数组。</p>\n\n<p>由于答案可能非常大，请返回对 <code>10<sup>9</sup> + 7</code> 取余数的结果。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [1,2,3], k = 2</span></p>\n\n<p><strong>输出：</strong> 24</p>\n\n<p><strong>解释：</strong></p>\n\n<p>数组 <code>nums</code> 中所有长度最多为 2 的子序列如下：</p>\n\n<table style=\"border: 1px solid black; border-collapse: collapse;\">\n\t<thead>\n\t\t<tr>\n\t\t\t<th style=\"border: 1px solid black;\">子序列</th>\n\t\t\t<th style=\"border: 1px solid black;\">最小值</th>\n\t\t\t<th style=\"border: 1px solid black;\">最大值</th>\n\t\t\t<th style=\"border: 1px solid black;\">和</th>\n\t\t</tr>\n\t</thead>\n\t<tbody>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[1]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[2]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[3]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t\t<td style=\"border: 1px solid black;\">6</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[1, 2]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[1, 3]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">1</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t\t<td style=\"border: 1px solid black;\">4</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><code>[2, 3]</code></td>\n\t\t\t<td style=\"border: 1px solid black;\">2</td>\n\t\t\t<td style=\"border: 1px solid black;\">3</td>\n\t\t\t<td style=\"border: 1px solid black;\">5</td>\n\t\t</tr>\n\t\t<tr>\n\t\t\t<td style=\"border: 1px solid black;\"><strong>总和</strong></td>\n\t\t\t<td style=\"border: 1px solid black;\">&nbsp;</td>\n\t\t\t<td style=\"border: 1px solid black;\">&nbsp;</td>\n\t\t\t<td style=\"border: 1px solid black;\">24</td>\n\t\t</tr>\n\t</tbody>\n</table>\n\n<p>因此，输出为 24。</p>\n</div>\n\n<p><strong>示例 2：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [5,0,6], k = 1</span></p>\n\n<p><strong>输出：</strong> 22</p>\n\n<p><strong>解释：</strong></p>\n\n<p>对于长度恰好为 1 的子序列，最小值和最大值均为元素本身。因此，总和为 <code>5 + 5 + 0 + 0 + 6 + 6 = 22</code>。</p>\n</div>\n\n<p><strong>示例 3：</strong></p>\n\n<div class=\"example-block\">\n<p><strong>输入：</strong> <span class=\"example-io\">nums = [1,1,1], k = 2</span></p>\n\n<p><strong>输出：</strong> 12</p>\n\n<p><strong>解释：</strong></p>\n\n<p>子序列 <code>[1, 1]</code> 和 <code>[1]</code> 各出现 3 次。对于所有这些子序列，最小值和最大值均为 1。因此，总和为 12。</p>\n</div>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= k &lt;= min(100, nums.length)</code></li>\n</ul>\n",
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<code>use-after-free<\\/code> \\u9519\\u8bef\\u3002<\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u4f7f\\u7528\\u65b9\\u4fbf\\uff0c\\u5927\\u90e8\\u5206\\u6807\\u51c6\\u5e93\\u7684\\u5934\\u6587\\u4ef6\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u60f3\\u4f7f\\u7528\\u54c8\\u5e0c\\u8868\\u8fd0\\u7b97, \\u60a8\\u53ef\\u4ee5\\u4f7f\\u7528 <a href=\\\"https:\\/\\/troydhanson.github.io\\/uthash\\/\\\" target=\\\"_blank\\\">uthash<\\/a>\\u3002 \\\"uthash.h\\\"\\u5df2\\u7ecf\\u9ed8\\u8ba4\\u88ab\\u5bfc\\u5165\\u3002\\u8bf7\\u770b\\u5982\\u4e0b\\u793a\\u4f8b:<\\/p>\\r\\n\\r\\n<p><b>1. \\u5f80\\u54c8\\u5e0c\\u8868\\u4e2d\\u6dfb\\u52a0\\u4e00\\u4e2a\\u5bf9\\u8c61\\uff1a<\\/b>\\r\\n<pre>\\r\\nstruct hash_entry {\\r\\n    int id;            \\/* we'll use this field as the key *\\/\\r\\n    char name[10];\\r\\n    UT_hash_handle hh; \\/* makes this structure hashable *\\/\\r\\n};\\r\\n\\r\\nstruct hash_entry *users = NULL;\\r\\n\\r\\nvoid add_user(struct hash_entry 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