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leetcode-problemset/leetcode/originData/rearrange-characters-to-make-target-string.json
2022-06-10 23:34:17 +08:00

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{
"data": {
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"title": "Rearrange Characters to Make Target String",
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"content": "<p>You are given two <strong>0-indexed</strong> strings <code>s</code> and <code>target</code>. You can take some letters from <code>s</code> and rearrange them to form new strings.</p>\n\n<p>Return<em> the <strong>maximum</strong> number of copies of </em><code>target</code><em> that can be formed by taking letters from </em><code>s</code><em> and rearranging them.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;ilovecodingonleetcode&quot;, target = &quot;code&quot;\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nFor the first copy of &quot;code&quot;, take the letters at indices 4, 5, 6, and 7.\nFor the second copy of &quot;code&quot;, take the letters at indices 17, 18, 19, and 20.\nThe strings that are formed are &quot;ecod&quot; and &quot;code&quot; which can both be rearranged into &quot;code&quot;.\nWe can make at most two copies of &quot;code&quot;, so we return 2.\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abcba&quot;, target = &quot;abc&quot;\n<strong>Output:</strong> 1\n<strong>Explanation:</strong>\nWe can make one copy of &quot;abc&quot; by taking the letters at indices 0, 1, and 2.\nWe can make at most one copy of &quot;abc&quot;, so we return 1.\nNote that while there is an extra &#39;a&#39; and &#39;b&#39; at indices 3 and 4, we cannot reuse the letter &#39;c&#39; at index 2, so we cannot make a second copy of &quot;abc&quot;.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;abbaccaddaeea&quot;, target = &quot;aaaaa&quot;\n<strong>Output:</strong> 1\n<strong>Explanation:</strong>\nWe can make one copy of &quot;aaaaa&quot; by taking the letters at indices 0, 3, 6, 9, and 12.\nWe can make at most one copy of &quot;aaaaa&quot;, so we return 1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= target.length &lt;= 10</code></li>\n\t<li><code>s</code> and <code>target</code> consist of lowercase English letters.</li>\n</ul>\n",
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"code": "class Solution {\npublic:\n int rearrangeCharacters(string s, string target) {\n \n }\n};",
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"code": "class Solution(object):\n def rearrangeCharacters(self, s, target):\n \"\"\"\n :type s: str\n :type target: str\n :rtype: int\n \"\"\"\n ",
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"code": "# @param {String} s\n# @param {String} target\n# @return {Integer}\ndef rearrange_characters(s, target)\n \nend",
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"code": "defmodule Solution do\n @spec rearrange_characters(s :: String.t, target :: String.t) :: integer\n def rearrange_characters(s, target) do\n\n end\nend",
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"hints": [
"Count the frequency of each character in s and target.",
"Consider each letter one at a time. If there are x occurrences of a letter in s and y occurrences of the same letter in target, how many copies of this letter can we make?",
"We can make floor(x / y) copies of the letter."
],
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