leetcode-problemset/leetcode/originData/add-minimum-number-of-rungs.json

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            "title": "Add Minimum Number of Rungs",
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            "content": "<p>You are given a <strong>strictly increasing</strong> integer array <code>rungs</code> that represents the <strong>height</strong> of rungs on a ladder. You are currently on the <strong>floor</strong> at height <code>0</code>, and you want to reach the last rung.</p>\n\n<p>You are also given an integer <code>dist</code>. You can only climb to the next highest rung if the distance between where you are currently at (the floor or on a rung) and the next rung is <strong>at most</strong> <code>dist</code>. You are able to insert rungs at any positive <strong>integer</strong> height if a rung is not already there.</p>\n\n<p>Return <em>the <strong>minimum</strong> number of rungs that must be added to the ladder in order for you to climb to the last rung.</em></p>\n\n<p>&nbsp;</p>\n<p><strong>Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> rungs = [1,3,5,10], dist = 2\n<strong>Output:</strong> 2\n<strong>Explanation:\n</strong>You currently cannot reach the last rung.\nAdd rungs at heights 7 and 8 to climb this ladder. \nThe ladder will now have rungs at [1,3,5,<u>7</u>,<u>8</u>,10].\n</pre>\n\n<p><strong>Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> rungs = [3,6,8,10], dist = 3\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\nThis ladder can be climbed without adding additional rungs.\n</pre>\n\n<p><strong>Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> rungs = [3,4,6,7], dist = 2\n<strong>Output:</strong> 1\n<strong>Explanation:</strong>\nYou currently cannot reach the first rung from the ground.\nAdd a rung at height 1 to climb this ladder.\nThe ladder will now have rungs at [<u>1</u>,3,4,6,7].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= rungs.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= rungs[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= dist &lt;= 10<sup>9</sup></code></li>\n\t<li><code>rungs</code> is <strong>strictly increasing</strong>.</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int addRungs(vector<int>& rungs, int dist) {\n        \n    }\n};",
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                    "code": "class Solution(object):\n    def addRungs(self, rungs, dist):\n        \"\"\"\n        :type rungs: List[int]\n        :type dist: int\n        :rtype: int\n        \"\"\"\n        ",
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                    "code": "public class Solution {\n    public int AddRungs(int[] rungs, int dist) {\n        \n    }\n}",
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                    "code": "/**\n * @param {number[]} rungs\n * @param {number} dist\n * @return {number}\n */\nvar addRungs = function(rungs, dist) {\n    \n};",
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                    "code": "# @param {Integer[]} rungs\n# @param {Integer} dist\n# @return {Integer}\ndef add_rungs(rungs, dist)\n    \nend",
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                    "code": "impl Solution {\n    pub fn add_rungs(rungs: Vec<i32>, dist: i32) -> i32 {\n        \n    }\n}",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $rungs\n     * @param Integer $dist\n     * @return Integer\n     */\n    function addRungs($rungs, $dist) {\n        \n    }\n}",
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            "hints": [
                "Go as far as you can on the available rungs before adding new rungs.",
                "If you have to add a new rung, add it as high up as possible.",
                "Try using division to decrease the number of computations."
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