mirror of
				https://gitee.com/coder-xiaomo/leetcode-problemset
				synced 2025-11-04 11:43:12 +08:00 
			
		
		
		
	
		
			
				
	
	
		
			41 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
			
		
		
	
	
			41 lines
		
	
	
		
			1.7 KiB
		
	
	
	
		
			HTML
		
	
	
	
	
	
<p>Given an integer array <code>nums</code> and two integers <code>firstLen</code> and <code>secondLen</code>, return <em>the maximum sum of elements in two non-overlapping <strong>subarrays</strong> with lengths </em><code>firstLen</code><em> and </em><code>secondLen</code>.</p>
 | 
						|
 | 
						|
<p>The array with length <code>firstLen</code> could occur before or after the array with length <code>secondLen</code>, but they have to be non-overlapping.</p>
 | 
						|
 | 
						|
<p>A <strong>subarray</strong> is a <strong>contiguous</strong> part of an array.</p>
 | 
						|
 | 
						|
<p> </p>
 | 
						|
<p><strong class="example">Example 1:</strong></p>
 | 
						|
 | 
						|
<pre>
 | 
						|
<strong>Input:</strong> nums = [0,6,5,2,2,5,1,9,4], firstLen = 1, secondLen = 2
 | 
						|
<strong>Output:</strong> 20
 | 
						|
<strong>Explanation:</strong> One choice of subarrays is [9] with length 1, and [6,5] with length 2.
 | 
						|
</pre>
 | 
						|
 | 
						|
<p><strong class="example">Example 2:</strong></p>
 | 
						|
 | 
						|
<pre>
 | 
						|
<strong>Input:</strong> nums = [3,8,1,3,2,1,8,9,0], firstLen = 3, secondLen = 2
 | 
						|
<strong>Output:</strong> 29
 | 
						|
<strong>Explanation:</strong> One choice of subarrays is [3,8,1] with length 3, and [8,9] with length 2.
 | 
						|
</pre>
 | 
						|
 | 
						|
<p><strong class="example">Example 3:</strong></p>
 | 
						|
 | 
						|
<pre>
 | 
						|
<strong>Input:</strong> nums = [2,1,5,6,0,9,5,0,3,8], firstLen = 4, secondLen = 3
 | 
						|
<strong>Output:</strong> 31
 | 
						|
<strong>Explanation:</strong> One choice of subarrays is [5,6,0,9] with length 4, and [0,3,8] with length 3.
 | 
						|
</pre>
 | 
						|
 | 
						|
<p> </p>
 | 
						|
<p><strong>Constraints:</strong></p>
 | 
						|
 | 
						|
<ul>
 | 
						|
	<li><code>1 <= firstLen, secondLen <= 1000</code></li>
 | 
						|
	<li><code>2 <= firstLen + secondLen <= 1000</code></li>
 | 
						|
	<li><code>firstLen + secondLen <= nums.length <= 1000</code></li>
 | 
						|
	<li><code>0 <= nums[i] <= 1000</code></li>
 | 
						|
</ul>
 |