leetcode-problemset/leetcode-cn/originData/word-search-ii.json

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        "question": {
            "questionId": "212",
            "questionFrontendId": "212",
            "categoryTitle": "Algorithms",
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            "title": "Word Search II",
            "titleSlug": "word-search-ii",
            "content": "<p>Given an <code>m x n</code> <code>board</code>&nbsp;of characters and a list of strings <code>words</code>, return <em>all words on the board</em>.</p>\n\n<p>Each word must be constructed from letters of sequentially adjacent cells, where <strong>adjacent cells</strong> are horizontally or vertically neighboring. The same letter cell may not be used more than once in a word.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/07/search1.jpg\" style=\"width: 322px; height: 322px;\" />\n<pre>\n<strong>Input:</strong> board = [[&quot;o&quot;,&quot;a&quot;,&quot;a&quot;,&quot;n&quot;],[&quot;e&quot;,&quot;t&quot;,&quot;a&quot;,&quot;e&quot;],[&quot;i&quot;,&quot;h&quot;,&quot;k&quot;,&quot;r&quot;],[&quot;i&quot;,&quot;f&quot;,&quot;l&quot;,&quot;v&quot;]], words = [&quot;oath&quot;,&quot;pea&quot;,&quot;eat&quot;,&quot;rain&quot;]\n<strong>Output:</strong> [&quot;eat&quot;,&quot;oath&quot;]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/07/search2.jpg\" style=\"width: 162px; height: 162px;\" />\n<pre>\n<strong>Input:</strong> board = [[&quot;a&quot;,&quot;b&quot;],[&quot;c&quot;,&quot;d&quot;]], words = [&quot;abcb&quot;]\n<strong>Output:</strong> []\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>m == board.length</code></li>\n\t<li><code>n == board[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 12</code></li>\n\t<li><code>board[i][j]</code> is a lowercase English letter.</li>\n\t<li><code>1 &lt;= words.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 10</code></li>\n\t<li><code>words[i]</code> consists of lowercase English letters.</li>\n\t<li>All the strings of <code>words</code> are unique.</li>\n</ul>\n",
            "translatedTitle": "单词搜索 II",
            "translatedContent": "<p>给定一个&nbsp;<code>m x n</code> 二维字符网格&nbsp;<code>board</code><strong>&nbsp;</strong>和一个单词（字符串）列表 <code>words</code>，&nbsp;<em>返回所有二维网格上的单词</em>&nbsp;。</p>\n\n<p>单词必须按照字母顺序，通过 <strong>相邻的单元格</strong> 内的字母构成，其中“相邻”单元格是那些水平相邻或垂直相邻的单元格。同一个单元格内的字母在一个单词中不允许被重复使用。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/07/search1.jpg\" />\n<pre>\n<strong>输入：</strong>board = [[\"o\",\"a\",\"a\",\"n\"],[\"e\",\"t\",\"a\",\"e\"],[\"i\",\"h\",\"k\",\"r\"],[\"i\",\"f\",\"l\",\"v\"]], words = [\"oath\",\"pea\",\"eat\",\"rain\"]\n<strong>输出：</strong>[\"eat\",\"oath\"]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/07/search2.jpg\" />\n<pre>\n<strong>输入：</strong>board = [[\"a\",\"b\"],[\"c\",\"d\"]], words = [\"abcb\"]\n<strong>输出：</strong>[]\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>m == board.length</code></li>\n\t<li><code>n == board[i].length</code></li>\n\t<li><code>1 &lt;= m, n &lt;= 12</code></li>\n\t<li><code>board[i][j]</code> 是一个小写英文字母</li>\n\t<li><code>1 &lt;= words.length &lt;= 3 * 10<sup>4</sup></code></li>\n\t<li><code>1 &lt;= words[i].length &lt;= 10</code></li>\n\t<li><code>words[i]</code> 由小写英文字母组成</li>\n\t<li><code>words</code> 中的所有字符串互不相同</li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    vector<string> findWords(vector<vector<char>>& board, vector<string>& words) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def findWords(self, board, words):\n        \"\"\"\n        :type board: List[List[str]]\n        :type words: List[str]\n        :rtype: List[str]\n        \"\"\"",
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                    "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar** findWords(char** board, int boardSize, int* boardColSize, char** words, int wordsSize, int* returnSize) {\n    \n}",
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                    "code": "public class Solution {\n    public IList<string> FindWords(char[][] board, string[] words) {\n\n    }\n}",
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                    "code": "/**\n * @param {character[][]} board\n * @param {string[]} words\n * @return {string[]}\n */\nvar findWords = function(board, words) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param String[][] $board\n     * @param String[] $words\n     * @return String[]\n     */\n    function findWords($board, $words) {\n\n    }\n}",
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                    "code": "class Solution {\n    func findWords(_ board: [[Character]], _ words: [String]) -> [String] {\n\n    }\n}",
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                    "code": "class Solution {\n    fun findWords(board: Array<CharArray>, words: Array<String>): List<String> {\n\n    }\n}",
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                    "code": "class Solution {\n  List<String> findWords(List<List<String>> board, List<String> words) {\n    \n  }\n}",
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                    "code": "func findWords(board [][]byte, words []string) []string {\n\n}",
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                    "code": "# @param {Character[][]} board\n# @param {String[]} words\n# @return {String[]}\ndef find_words(board, words)\n\nend",
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                    "code": "object Solution {\n    def findWords(board: Array[Array[Char]], words: Array[String]): List[String] = {\n\n    }\n}",
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                    "code": "impl Solution {\n    pub fn find_words(board: Vec<Vec<char>>, words: Vec<String>) -> Vec<String> {\n\n    }\n}",
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                    "code": "defmodule Solution do\n  @spec find_words(board :: [[char]], words :: [String.t]) :: [String.t]\n  def find_words(board, words) do\n    \n  end\nend",
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            "hints": [
                "You would need to optimize your backtracking to pass the larger test. Could you stop backtracking earlier?",
                "If the current candidate does not exist in all words&#39; prefix, you could stop backtracking immediately. What kind of data structure could answer such query efficiently? Does a hash table work? Why or why not? How about a Trie? If you would like to learn how to implement a basic trie, please work on this problem: <a href=\"https://leetcode.com/problems/implement-trie-prefix-tree/\">Implement Trie (Prefix Tree)</a> first."
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