leetcode-problemset/leetcode-cn/originData/watering-plants.json

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        "question": {
            "questionId": "1310",
            "questionFrontendId": "2079",
            "categoryTitle": "Algorithms",
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            "title": "Watering Plants",
            "titleSlug": "watering-plants",
            "content": "<p>You want to water <code>n</code> plants in your garden with a watering can. The plants are arranged in a row and are labeled from <code>0</code> to <code>n - 1</code> from left to right where the <code>i<sup>th</sup></code> plant is located at <code>x = i</code>. There is a river at <code>x = -1</code> that you can refill your watering can at.</p>\n\n<p>Each plant needs a specific amount of water. You will water the plants in the following way:</p>\n\n<ul>\n\t<li>Water the plants in order from left to right.</li>\n\t<li>After watering the current plant, if you do not have enough water to <strong>completely</strong> water the next plant, return to the river to fully refill the watering can.</li>\n\t<li>You <strong>cannot</strong> refill the watering can early.</li>\n</ul>\n\n<p>You are initially at the river (i.e., <code>x = -1</code>). It takes <strong>one step</strong> to move <strong>one unit</strong> on the x-axis.</p>\n\n<p>Given a <strong>0-indexed</strong> integer array <code>plants</code> of <code>n</code> integers, where <code>plants[i]</code> is the amount of water the <code>i<sup>th</sup></code> plant needs, and an integer <code>capacity</code> representing the watering can capacity, return <em>the <strong>number of steps</strong> needed to water all the plants</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> plants = [2,2,3,3], capacity = 5\n<strong>Output:</strong> 14\n<strong>Explanation:</strong> Start at the river with a full watering can:\n- Walk to plant 0 (1 step) and water it. Watering can has 3 units of water.\n- Walk to plant 1 (1 step) and water it. Watering can has 1 unit of water.\n- Since you cannot completely water plant 2, walk back to the river to refill (2 steps).\n- Walk to plant 2 (3 steps) and water it. Watering can has 2 units of water.\n- Since you cannot completely water plant 3, walk back to the river to refill (3 steps).\n- Walk to plant 3 (4 steps) and water it.\nSteps needed = 1 + 1 + 2 + 3 + 3 + 4 = 14.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> plants = [1,1,1,4,2,3], capacity = 4\n<strong>Output:</strong> 30\n<strong>Explanation:</strong> Start at the river with a full watering can:\n- Water plants 0, 1, and 2 (3 steps). Return to river (3 steps).\n- Water plant 3 (4 steps). Return to river (4 steps).\n- Water plant 4 (5 steps). Return to river (5 steps).\n- Water plant 5 (6 steps).\nSteps needed = 3 + 3 + 4 + 4 + 5 + 5 + 6 = 30.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> plants = [7,7,7,7,7,7,7], capacity = 8\n<strong>Output:</strong> 49\n<strong>Explanation:</strong> You have to refill before watering each plant.\nSteps needed = 1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + 5 + 5 + 6 + 6 + 7 = 49.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == plants.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n\t<li><code>1 &lt;= plants[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>max(plants[i]) &lt;= capacity &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "给植物浇水",
            "translatedContent": "<p>你打算用一个水罐给花园里的 <code>n</code> 株植物浇水。植物排成一行，从左到右进行标记，编号从 <code>0</code> 到 <code>n - 1</code> 。其中，第 <code>i</code> 株植物的位置是 <code>x = i</code> 。<code>x = -1</code>&nbsp;处有一条河，你可以在那里重新灌满你的水罐。</p>\n\n<p>每一株植物都需要浇特定量的水。你将会按下面描述的方式完成浇水：</p>\n\n<ul>\n\t<li>按从左到右的顺序给植物浇水。</li>\n\t<li>在给当前植物浇完水之后，如果你没有足够的水 <strong>完全</strong> 浇灌下一株植物，那么你就需要返回河边重新装满水罐。</li>\n\t<li>你 <strong>不能</strong> 提前重新灌满水罐。</li>\n</ul>\n\n<p>最初，你在河边（也就是，<code>x = -1</code>），在 x 轴上每移动 <strong>一个单位</strong>&nbsp;都需要 <strong>一步</strong> 。</p>\n\n<p>给你一个下标从 <strong>0</strong> 开始的整数数组 <code>plants</code> ，数组由 <code>n</code> 个整数组成。其中，<code>plants[i]</code> 为第 <code>i</code> 株植物需要的水量。另有一个整数 <code>capacity</code> 表示水罐的容量，返回浇灌所有植物需要的 <strong>步数</strong> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>plants = [2,2,3,3], capacity = 5\n<strong>输出：</strong>14\n<strong>解释：</strong>从河边开始，此时水罐是装满的：\n- 走到植物 0 (1 步) ，浇水。水罐中还有 3 单位的水。\n- 走到植物 1 (1 步) ，浇水。水罐中还有 1 单位的水。\n- 由于不能完全浇灌植物 2 ，回到河边取水 (2 步)。\n- 走到植物 2 (3 步) ，浇水。水罐中还有 2 单位的水。\n- 由于不能完全浇灌植物 3 ，回到河边取水 (3 步)。\n- 走到植物 3 (4 步) ，浇水。\n需要的步数是 = 1 + 1 + 2 + 3 + 3 + 4 = 14 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>plants = [1,1,1,4,2,3], capacity = 4\n<strong>输出：</strong>30\n<strong>解释：</strong>从河边开始，此时水罐是装满的：\n- 走到植物 0，1，2 (3 步) ，浇水。回到河边取水 (3 步)。\n- 走到植物 3 (4 步) ，浇水。回到河边取水 (4 步)。\n- 走到植物 4 (5 步) ，浇水。回到河边取水 (5 步)。\n- 走到植物 5 (6 步) ，浇水。\n需要的步数是 = 3 + 3 + 4 + 4 + 5 + 5 + 6 = 30 。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>plants = [7,7,7,7,7,7,7], capacity = 8\n<strong>输出：</strong>49\n<strong>解释：</strong>每次浇水都需要重新灌满水罐。\n需要的步数是 = 1 + 1 + 2 + 2 + 3 + 3 + 4 + 4 + 5 + 5 + 6 + 6 + 7 = 49 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == plants.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 1000</code></li>\n\t<li><code>1 &lt;= plants[i] &lt;= 10<sup>6</sup></code></li>\n\t<li><code>max(plants[i]) &lt;= capacity &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                    "code": "class Solution {\npublic:\n    int wateringPlants(vector<int>& plants, int capacity) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def wateringPlants(self, plants, capacity):\n        \"\"\"\n        :type plants: List[int]\n        :type capacity: int\n        :rtype: int\n        \"\"\"",
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