leetcode-problemset/leetcode-cn/originData/the-kth-factor-of-n.json

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            "title": "The kth Factor of n",
            "titleSlug": "the-kth-factor-of-n",
            "content": "<p>You are given two positive integers <code>n</code> and <code>k</code>. A factor of an integer <code>n</code> is defined as an integer <code>i</code> where <code>n % i == 0</code>.</p>\n\n<p>Consider a list of all factors of <code>n</code> sorted in <strong>ascending order</strong>, return <em>the </em><code>k<sup>th</sup></code><em> factor</em> in this list or return <code>-1</code> if <code>n</code> has less than <code>k</code> factors.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 12, k = 3\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> Factors list is [1, 2, 3, 4, 6, 12], the 3<sup>rd</sup> factor is 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 7, k = 2\n<strong>Output:</strong> 7\n<strong>Explanation:</strong> Factors list is [1, 7], the 2<sup>nd</sup> factor is 7.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> n = 4, k = 4\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> Factors list is [1, 2, 4], there is only 3 factors. We should return -1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= n &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong>Follow up:</strong></p>\n\n<p>Could you solve this problem in less than O(n) complexity?</p>\n",
            "translatedTitle": "n 的第 k 个因子",
            "translatedContent": "<p>给你两个正整数&nbsp;<code>n</code> 和&nbsp;<code>k</code>&nbsp;。</p>\n\n<p>如果正整数 <code>i</code> 满足 <code>n % i == 0</code> ，那么我们就说正整数 <code>i</code> 是整数 <code>n</code>&nbsp;的因子。</p>\n\n<p>考虑整数 <code>n</code>&nbsp;的所有因子，将它们 <strong>升序排列</strong>&nbsp;。请你返回第 <code>k</code>&nbsp;个因子。如果 <code>n</code>&nbsp;的因子数少于 <code>k</code>&nbsp;，请你返回 <code>-1</code>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 12, k = 3\n<strong>输出：</strong>3\n<strong>解释：</strong>因子列表包括 [1, 2, 3, 4, 6, 12]，第 3 个因子是 3 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 7, k = 2\n<strong>输出：</strong>7\n<strong>解释：</strong>因子列表包括 [1, 7] ，第 2 个因子是 7 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>n = 4, k = 4\n<strong>输出：</strong>-1\n<strong>解释：</strong>因子列表包括 [1, 2, 4] ，只有 3 个因子，所以我们应该返回 -1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= k &lt;= n &lt;= 1000</code></li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>进阶：</strong></p>\n\n<p>你可以设计时间复杂度小于 O(n) 的算法来解决此问题吗？</p>\n",
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