leetcode-problemset/leetcode-cn/originData/subdomain-visit-count.json

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        "question": {
            "questionId": "829",
            "questionFrontendId": "811",
            "categoryTitle": "Algorithms",
            "boundTopicId": 1675,
            "title": "Subdomain Visit Count",
            "titleSlug": "subdomain-visit-count",
            "content": "<p>A website domain <code>&quot;discuss.leetcode.com&quot;</code> consists of various subdomains. At the top level, we have <code>&quot;com&quot;</code>, at the next level, we have <code>&quot;leetcode.com&quot;</code>&nbsp;and at the lowest level, <code>&quot;discuss.leetcode.com&quot;</code>. When we visit a domain like <code>&quot;discuss.leetcode.com&quot;</code>, we will also visit the parent domains <code>&quot;leetcode.com&quot;</code> and <code>&quot;com&quot;</code> implicitly.</p>\n\n<p>A <strong>count-paired domain</strong> is a domain that has one of the two formats <code>&quot;rep d1.d2.d3&quot;</code> or <code>&quot;rep d1.d2&quot;</code> where <code>rep</code> is the number of visits to the domain and <code>d1.d2.d3</code> is the domain itself.</p>\n\n<ul>\n\t<li>For example, <code>&quot;9001 discuss.leetcode.com&quot;</code> is a <strong>count-paired domain</strong> that indicates that <code>discuss.leetcode.com</code> was visited <code>9001</code> times.</li>\n</ul>\n\n<p>Given an array of <strong>count-paired domains</strong> <code>cpdomains</code>, return <em>an array of the <strong>count-paired domains</strong> of each subdomain in the input</em>. You may return the answer in <strong>any order</strong>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> cpdomains = [&quot;9001 discuss.leetcode.com&quot;]\n<strong>Output:</strong> [&quot;9001 leetcode.com&quot;,&quot;9001 discuss.leetcode.com&quot;,&quot;9001 com&quot;]\n<strong>Explanation:</strong> We only have one website domain: &quot;discuss.leetcode.com&quot;.\nAs discussed above, the subdomain &quot;leetcode.com&quot; and &quot;com&quot; will also be visited. So they will all be visited 9001 times.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> cpdomains = [&quot;900 google.mail.com&quot;, &quot;50 yahoo.com&quot;, &quot;1 intel.mail.com&quot;, &quot;5 wiki.org&quot;]\n<strong>Output:</strong> [&quot;901 mail.com&quot;,&quot;50 yahoo.com&quot;,&quot;900 google.mail.com&quot;,&quot;5 wiki.org&quot;,&quot;5 org&quot;,&quot;1 intel.mail.com&quot;,&quot;951 com&quot;]\n<strong>Explanation:</strong> We will visit &quot;google.mail.com&quot; 900 times, &quot;yahoo.com&quot; 50 times, &quot;intel.mail.com&quot; once and &quot;wiki.org&quot; 5 times.\nFor the subdomains, we will visit &quot;mail.com&quot; 900 + 1 = 901 times, &quot;com&quot; 900 + 50 + 1 = 951 times, and &quot;org&quot; 5 times.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= cpdomain.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= cpdomain[i].length &lt;= 100</code></li>\n\t<li><code>cpdomain[i]</code> follows either the <code>&quot;rep<sub>i</sub> d1<sub>i</sub>.d2<sub>i</sub>.d3<sub>i</sub>&quot;</code> format or the <code>&quot;rep<sub>i</sub> d1<sub>i</sub>.d2<sub>i</sub>&quot;</code> format.</li>\n\t<li><code>rep<sub>i</sub></code> is an integer in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li><code>d1<sub>i</sub></code>, <code>d2<sub>i</sub></code>, and <code>d3<sub>i</sub></code> consist of lowercase English letters.</li>\n</ul>\n",
            "translatedTitle": "子域名访问计数",
            "translatedContent": "<p>网站域名 <code>\"discuss.leetcode.com\"</code> 由多个子域名组成。顶级域名为 <code>\"com\"</code> ，二级域名为 <code>\"leetcode.com\"</code> ，最低一级为 <code>\"discuss.leetcode.com\"</code> 。当访问域名 <code>\"discuss.leetcode.com\"</code> 时，同时也会隐式访问其父域名 <code>\"leetcode.com\" </code>以及 <code>\"com\"</code> 。</p>\n\n<p><strong>计数配对域名</strong> 是遵循 <code>\"rep d1.d2.d3\"</code> 或 <code>\"rep d1.d2\"</code> 格式的一个域名表示，其中 <code>rep</code> 表示访问域名的次数，<code>d1.d2.d3</code> 为域名本身。</p>\n\n<ul>\n\t<li>例如，<code>\"9001 discuss.leetcode.com\"</code> 就是一个 <strong>计数配对域名</strong> ，表示 <code>discuss.leetcode.com</code> 被访问了 <code>9001</code> 次。</li>\n</ul>\n\n<p>给你一个<strong> 计数配对域名 </strong>组成的数组 <code>cpdomains</code> ，解析得到输入中每个子域名对应的&nbsp;<strong>计数配对域名</strong> ，并以数组形式返回。可以按 <strong>任意顺序</strong> 返回答案。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>cpdomains = [\"9001 discuss.leetcode.com\"]\n<strong>输出：</strong>[\"9001 leetcode.com\",\"9001 discuss.leetcode.com\",\"9001 com\"]\n<strong>解释：</strong>例子中仅包含一个网站域名：\"discuss.leetcode.com\"。\n按照前文描述，子域名 \"leetcode.com\" 和 \"com\" 都会被访问，所以它们都被访问了 9001 次。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>cpdomains = [\"900 google.mail.com\", \"50 yahoo.com\", \"1 intel.mail.com\", \"5 wiki.org\"]\n<strong>输出：</strong>[\"901 mail.com\",\"50 yahoo.com\",\"900 google.mail.com\",\"5 wiki.org\",\"5 org\",\"1 intel.mail.com\",\"951 com\"]\n<strong>解释：</strong>按照前文描述，会访问 \"google.mail.com\" 900 次，\"yahoo.com\" 50 次，\"intel.mail.com\" 1 次，\"wiki.org\" 5 次。\n而对于父域名，会访问 \"mail.com\" 900 + 1 = 901 次，\"com\" 900 + 50 + 1 = 951 次，和 \"org\" 5 次。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= cpdomain.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= cpdomain[i].length &lt;= 100</code></li>\n\t<li><code>cpdomain[i]</code> 会遵循 <code>\"rep<sub>i</sub> d1<sub>i</sub>.d2<sub>i</sub>.d3<sub>i</sub>\"</code> 或 <code>\"rep<sub>i</sub> d1<sub>i</sub>.d2<sub>i</sub>\"</code> 格式</li>\n\t<li><code>rep<sub>i</sub></code> 是范围 <code>[1, 10<sup>4</sup>]</code> 内的一个整数</li>\n\t<li><code>d1<sub>i</sub></code>、<code>d2<sub>i</sub></code> 和 <code>d3<sub>i</sub></code> 由小写英文字母组成</li>\n</ul>\n",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<string> subdomainVisits(vector<string>& cpdomains) {\n\n    }\n};",
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                    "code": "class Solution(object):\n    def subdomainVisits(self, cpdomains):\n        \"\"\"\n        :type cpdomains: List[str]\n        :rtype: List[str]\n        \"\"\"",
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                    "code": "/**\n * Note: The returned array must be malloced, assume caller calls free().\n */\nchar** subdomainVisits(char** cpdomains, int cpdomainsSize, int* returnSize) {\n    \n}",
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                    "code": "public class Solution {\n    public IList<string> SubdomainVisits(string[] cpdomains) {\n\n    }\n}",
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                    "code": "/**\n * @param {string[]} cpdomains\n * @return {string[]}\n */\nvar subdomainVisits = function(cpdomains) {\n\n};",
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