leetcode-problemset/leetcode-cn/originData/stone-game-ii.json

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            "title": "Stone Game II",
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            "content": "<p>Alice and Bob continue their&nbsp;games with piles of stones.&nbsp; There are a number of&nbsp;piles&nbsp;<strong>arranged in a row</strong>, and each pile has a positive integer number of stones&nbsp;<code>piles[i]</code>.&nbsp; The objective of the game is to end with the most&nbsp;stones.&nbsp;</p>\n\n<p>Alice&nbsp;and Bob take turns, with Alice starting first.&nbsp; Initially, <code>M = 1</code>.</p>\n\n<p>On each player&#39;s turn, that player&nbsp;can take <strong>all the stones</strong> in the <strong>first</strong> <code>X</code> remaining piles, where <code>1 &lt;= X &lt;= 2M</code>.&nbsp; Then, we set&nbsp;<code>M = max(M, X)</code>.</p>\n\n<p>The game continues until all the stones have been taken.</p>\n\n<p>Assuming Alice and Bob play optimally, return the maximum number of stones Alice&nbsp;can get.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> piles = [2,7,9,4,4]\n<strong>Output:</strong> 10\n<strong>Explanation:</strong>  If Alice takes one pile at the beginning, Bob takes two piles, then Alice takes 2 piles again. Alice can get 2 + 4 + 4 = 10 piles in total. If Alice takes two piles at the beginning, then Bob can take all three piles left. In this case, Alice get 2 + 7 = 9 piles in total. So we return 10 since it&#39;s larger. \n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> piles = [1,2,3,4,5,100]\n<strong>Output:</strong> 104\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= piles.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= piles[i]&nbsp;&lt;= 10<sup>4</sup></code></li>\n</ul>\n",
            "translatedTitle": "石子游戏 II",
            "translatedContent": "<p>爱丽丝和鲍勃继续他们的石子游戏。许多堆石子&nbsp;<strong>排成一行</strong>，每堆都有正整数颗石子&nbsp;<code>piles[i]</code>。游戏以谁手中的石子最多来决出胜负。</p>\n\n<p>爱丽丝和鲍勃轮流进行，爱丽丝先开始。最初，<code>M = 1</code>。</p>\n\n<p>在每个玩家的回合中，该玩家可以拿走剩下的&nbsp;<strong>前</strong>&nbsp;<code>X</code>&nbsp;堆的所有石子，其中&nbsp;<code>1 &lt;= X &lt;= 2M</code>。然后，令&nbsp;<code>M = max(M, X)</code>。</p>\n\n<p>游戏一直持续到所有石子都被拿走。</p>\n\n<p>假设爱丽丝和鲍勃都发挥出最佳水平，返回爱丽丝可以得到的最大数量的石头。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>piles = [2,7,9,4,4]\n<strong>输出：</strong>10\n<strong>解释：</strong>如果一开始Alice取了一堆，Bob取了两堆，然后Alice再取两堆。爱丽丝可以得到2 + 4 + 4 = 10堆。如果Alice一开始拿走了两堆，那么Bob可以拿走剩下的三堆。在这种情况下，Alice得到2 + 7 = 9堆。返回10，因为它更大。\n</pre>\n\n<p><strong>示例 2:</strong></p>\n\n<pre>\n<strong>输入：</strong>piles = [1,2,3,4,5,100]\n<strong>输出：</strong>104\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= piles.length &lt;= 100</code></li>\n\t<li><meta charset=\"UTF-8\" /><code>1 &lt;= piles[i]&nbsp;&lt;= 10<sup>4</sup></code></li>\n</ul>\n",
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