mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
202 lines
24 KiB
JSON
202 lines
24 KiB
JSON
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"questionId": "1771",
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"title": "Sell Diminishing-Valued Colored Balls",
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"content": "<p>You have an <code>inventory</code> of different colored balls, and there is a customer that wants <code>orders</code> balls of <strong>any</strong> color.</p>\n\n<p>The customer weirdly values the colored balls. Each colored ball's value is the number of balls <strong>of that color </strong>you currently have in your <code>inventory</code>. For example, if you own <code>6</code> yellow balls, the customer would pay <code>6</code> for the first yellow ball. After the transaction, there are only <code>5</code> yellow balls left, so the next yellow ball is then valued at <code>5</code> (i.e., the value of the balls decreases as you sell more to the customer).</p>\n\n<p>You are given an integer array, <code>inventory</code>, where <code>inventory[i]</code> represents the number of balls of the <code>i<sup>th</sup></code> color that you initially own. You are also given an integer <code>orders</code>, which represents the total number of balls that the customer wants. You can sell the balls <strong>in any order</strong>.</p>\n\n<p>Return <em>the <strong>maximum</strong> total value that you can attain after selling </em><code>orders</code><em> colored balls</em>. As the answer may be too large, return it <strong>modulo </strong><code>10<sup>9 </sup>+ 7</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2020/11/05/jj.gif\" style=\"width: 480px; height: 270px;\" />\n<pre>\n<strong>Input:</strong> inventory = [2,5], orders = 4\n<strong>Output:</strong> 14\n<strong>Explanation:</strong> Sell the 1st color 1 time (2) and the 2nd color 3 times (5 + 4 + 3).\nThe maximum total value is 2 + 5 + 4 + 3 = 14.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> inventory = [3,5], orders = 6\n<strong>Output:</strong> 19\n<strong>Explanation: </strong>Sell the 1st color 2 times (3 + 2) and the 2nd color 4 times (5 + 4 + 3 + 2).\nThe maximum total value is 3 + 2 + 5 + 4 + 3 + 2 = 19.\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 <= inventory.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= inventory[i] <= 10<sup>9</sup></code></li>\n\t<li><code>1 <= orders <= min(sum(inventory[i]), 10<sup>9</sup>)</code></li>\n</ul>\n",
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"translatedTitle": "销售价值减少的颜色球",
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"translatedContent": "<p>你有一些球的库存 <code>inventory</code> ，里面包含着不同颜色的球。一个顾客想要 <strong>任意颜色</strong> 总数为 <code>orders</code> 的球。</p>\n\n<p>这位顾客有一种特殊的方式衡量球的价值：每个球的价值是目前剩下的 <strong>同色球</strong> 的数目。比方说还剩下 <code>6</code> 个黄球，那么顾客买第一个黄球的时候该黄球的价值为 <code>6</code> 。这笔交易以后，只剩下 <code>5</code> 个黄球了，所以下一个黄球的价值为 <code>5</code> （也就是球的价值随着顾客购买同色球是递减的）</p>\n\n<p>给你整数数组 <code>inventory</code> ，其中 <code>inventory[i]</code> 表示第 <code>i</code> 种颜色球一开始的数目。同时给你整数 <code>orders</code> ，表示顾客总共想买的球数目。你可以按照 <strong>任意顺序</strong> 卖球。</p>\n\n<p>请你返回卖了 <code>orders</code> 个球以后 <strong>最大</strong> 总价值之和。由于答案可能会很大，请你返回答案对 <code>10<sup>9</sup> + 7</code> <strong>取余数</strong> 的结果。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode-cn.com/aliyun-lc-upload/uploads/2020/11/08/jj.gif\" style=\"width: 480px; height: 270px;\" />\n<pre>\n<b>输入：</b>inventory = [2,5], orders = 4\n<b>输出：</b>14\n<b>解释：</b>卖 1 个第一种颜色的球（价值为 2 )，卖 3 个第二种颜色的球（价值为 5 + 4 + 3）。\n最大总和为 2 + 5 + 4 + 3 = 14 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>inventory = [3,5], orders = 6\n<b>输出：</b>19\n<strong>解释：</strong>卖 2 个第一种颜色的球（价值为 3 + 2），卖 4 个第二种颜色的球（价值为 5 + 4 + 3 + 2）。\n最大总和为 3 + 2 + 5 + 4 + 3 + 2 = 19 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>inventory = [2,8,4,10,6], orders = 20\n<b>输出：</b>110\n</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<b>输入：</b>inventory = [1000000000], orders = 1000000000\n<b>输出：</b>21\n<strong>解释：</strong>卖 1000000000 次第一种颜色的球，总价值为 500000000500000000 。 500000000500000000 对 10<sup>9 </sup>+ 7 取余为 21 。\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 <= inventory.length <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= inventory[i] <= 10<sup>9</sup></code></li>\n\t<li><code>1 <= orders <= min(sum(inventory[i]), 10<sup>9</sup>)</code></li>\n</ul>\n",
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"Greedily sell the most expensive ball.",
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"There is some value k where all balls of value > k are sold, and some, (maybe 0) of balls of value k are sold.",
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