mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
180 lines
27 KiB
JSON
180 lines
27 KiB
JSON
{
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"data": {
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"question": {
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"questionId": "783",
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"questionFrontendId": "700",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1538,
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"title": "Search in a Binary Search Tree",
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"titleSlug": "search-in-a-binary-search-tree",
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"content": "<p>You are given the <code>root</code> of a binary search tree (BST) and an integer <code>val</code>.</p>\n\n<p>Find the node in the BST that the node's value equals <code>val</code> and return the subtree rooted with that node. If such a node does not exist, return <code>null</code>.</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/12/tree1.jpg\" style=\"width: 422px; height: 302px;\" />\n<pre>\n<strong>Input:</strong> root = [4,2,7,1,3], val = 2\n<strong>Output:</strong> [2,1,3]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/12/tree2.jpg\" style=\"width: 422px; height: 302px;\" />\n<pre>\n<strong>Input:</strong> root = [4,2,7,1,3], val = 5\n<strong>Output:</strong> []\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 5000]</code>.</li>\n\t<li><code>1 <= Node.val <= 10<sup>7</sup></code></li>\n\t<li><code>root</code> is a binary search tree.</li>\n\t<li><code>1 <= val <= 10<sup>7</sup></code></li>\n</ul>\n",
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"translatedTitle": "二叉搜索树中的搜索",
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"translatedContent": "<p>给定二叉搜索树（BST）的根节点<meta charset=\"UTF-8\" /> <code>root</code> 和一个整数值<meta charset=\"UTF-8\" /> <code>val</code>。</p>\n\n<p>你需要在 BST 中找到节点值等于 <code>val</code> 的节点。 返回以该节点为根的子树。 如果节点不存在，则返回<meta charset=\"UTF-8\" /> <code>null</code> 。</p>\n\n<p> </p>\n\n<p><strong>示例 1:</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/12/tree1.jpg\" style=\"height: 179px; width: 250px;\" /><meta charset=\"UTF-8\" /></p>\n\n<pre>\n<b>输入：</b>root = [4,2,7,1,3], val = 2\n<b>输出：</b>[2,1,3]\n</pre>\n\n<p><strong>示例 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/01/12/tree2.jpg\" style=\"height: 179px; width: 250px;\" />\n<pre>\n<b>输入：</b>root = [4,2,7,1,3], val = 5\n<b>输出：</b>[]\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>树中节点数在 <code>[1, 5000]</code> 范围内</li>\n\t<li><code>1 <= Node.val <= 10<sup>7</sup></code></li>\n\t<li><code>root</code> 是二叉搜索树</li>\n\t<li><code>1 <= val <= 10<sup>7</sup></code></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n TreeNode* searchBST(TreeNode* root, int val) {\n\n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * int val;\n * TreeNode left;\n * TreeNode right;\n * TreeNode() {}\n * TreeNode(int val) { this.val = val; }\n * TreeNode(int val, TreeNode left, TreeNode right) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\nclass Solution {\n public TreeNode searchBST(TreeNode root, int val) {\n\n }\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode(object):\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution(object):\n def searchBST(self, root, val):\n \"\"\"\n :type root: TreeNode\n :type val: int\n :rtype: TreeNode\n \"\"\"\n ",
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"code": "# Definition for a binary tree node.\n# class TreeNode:\n# def __init__(self, val=0, left=None, right=None):\n# self.val = val\n# self.left = left\n# self.right = right\nclass Solution:\n def searchBST(self, root: Optional[TreeNode], val: int) -> Optional[TreeNode]:",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * struct TreeNode *left;\n * struct TreeNode *right;\n * };\n */\nstruct TreeNode* searchBST(struct TreeNode* root, int val) {\n \n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public TreeNode SearchBST(TreeNode root, int val) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * function TreeNode(val, left, right) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n */\n/**\n * @param {TreeNode} root\n * @param {number} val\n * @return {TreeNode}\n */\nvar searchBST = function(root, val) {\n\n};",
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"lang": "TypeScript",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * val: number\n * left: TreeNode | null\n * right: TreeNode | null\n * constructor(val?: number, left?: TreeNode | null, right?: TreeNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.left = (left===undefined ? null : left)\n * this.right = (right===undefined ? null : right)\n * }\n * }\n */\n\nfunction searchBST(root: TreeNode | null, val: number): TreeNode | null {\n \n};",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @param Integer $val\n * @return TreeNode\n */\n function searchBST($root, $val) {\n\n }\n}",
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"__typename": "CodeSnippetNode"
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"lang": "Swift",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func searchBST(_ root: TreeNode?, _ val: Int) -> TreeNode? {\n\n }\n}",
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"code": "/**\n * Example:\n * var ti = TreeNode(5)\n * var v = ti.`val`\n * Definition for a binary tree node.\n * class TreeNode(var `val`: Int) {\n * var left: TreeNode? = null\n * var right: TreeNode? = null\n * }\n */\nclass Solution {\n fun searchBST(root: TreeNode?, `val`: Int): TreeNode? {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * int val;\n * TreeNode? left;\n * TreeNode? right;\n * TreeNode([this.val = 0, this.left, this.right]);\n * }\n */\nclass Solution {\n TreeNode? searchBST(TreeNode? root, int val) {\n \n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc searchBST(root *TreeNode, val int) *TreeNode {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @param {Integer} val\n# @return {TreeNode}\ndef search_bst(root, val)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def searchBST(root: TreeNode, `val`: Int): TreeNode = {\n\n }\n}",
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"code": "// Definition for a binary tree node.\n// #[derive(Debug, PartialEq, Eq)]\n// pub struct TreeNode {\n// pub val: i32,\n// pub left: Option<Rc<RefCell<TreeNode>>>,\n// pub right: Option<Rc<RefCell<TreeNode>>>,\n// }\n//\n// impl TreeNode {\n// #[inline]\n// pub fn new(val: i32) -> Self {\n// TreeNode {\n// val,\n// left: None,\n// right: None\n// }\n// }\n// }\nuse std::rc::Rc;\nuse std::cell::RefCell;\nimpl Solution {\n pub fn search_bst(root: Option<Rc<RefCell<TreeNode>>>, val: i32) -> Option<Rc<RefCell<TreeNode>>> {\n\n }\n}",
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"code": "%% Definition for a binary tree node.\n%%\n%% -record(tree_node, {val = 0 :: integer(),\n%% left = null :: 'null' | #tree_node{},\n%% right = null :: 'null' | #tree_node{}}).\n\n-spec search_bst(Root :: #tree_node{} | null, Val :: integer()) -> #tree_node{} | null.\nsearch_bst(Root, Val) ->\n .",
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"code": "# Definition for a binary tree node.\n#\n# defmodule TreeNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# left: TreeNode.t() | nil,\n# right: TreeNode.t() | nil\n# }\n# defstruct val: 0, left: nil, right: nil\n# end\n\ndefmodule Solution do\n @spec search_bst(root :: TreeNode.t | nil, val :: integer) :: TreeNode.t | nil\n def search_bst(root, val) do\n \n end\nend",
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