leetcode-problemset/leetcode-cn/originData/reverse-substrings-between-each-pair-of-parentheses.json

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        "question": {
            "questionId": "1298",
            "questionFrontendId": "1190",
            "categoryTitle": "Algorithms",
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            "title": "Reverse Substrings Between Each Pair of Parentheses",
            "titleSlug": "reverse-substrings-between-each-pair-of-parentheses",
            "content": "<p>You are given a string <code>s</code> that consists of lower case English letters and brackets.</p>\n\n<p>Reverse the strings in each pair of matching parentheses, starting from the innermost one.</p>\n\n<p>Your result should <strong>not</strong> contain any brackets.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;(abcd)&quot;\n<strong>Output:</strong> &quot;dcba&quot;\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;(u(love)i)&quot;\n<strong>Output:</strong> &quot;iloveu&quot;\n<strong>Explanation:</strong> The substring &quot;love&quot; is reversed first, then the whole string is reversed.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;(ed(et(oc))el)&quot;\n<strong>Output:</strong> &quot;leetcode&quot;\n<strong>Explanation:</strong> First, we reverse the substring &quot;oc&quot;, then &quot;etco&quot;, and finally, the whole string.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 2000</code></li>\n\t<li><code>s</code> only contains lower case English characters and parentheses.</li>\n\t<li>It is guaranteed that all parentheses are balanced.</li>\n</ul>\n",
            "translatedTitle": "反转每对括号间的子串",
            "translatedContent": "<p>给出一个字符串&nbsp;<code>s</code>（仅含有小写英文字母和括号）。</p>\n\n<p>请你按照从括号内到外的顺序，逐层反转每对匹配括号中的字符串，并返回最终的结果。</p>\n\n<p>注意，您的结果中 <strong>不应</strong> 包含任何括号。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"(abcd)\"\n<strong>输出：</strong>\"dcba\"\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"(u(love)i)\"\n<strong>输出：</strong>\"iloveu\"\n<strong>解释：</strong>先反转子字符串 \"love\" ，然后反转整个字符串。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"(ed(et(oc))el)\"\n<strong>输出：</strong>\"leetcode\"\n<strong>解释：</strong>先反转子字符串 \"oc\" ，接着反转 \"etco\" ，然后反转整个字符串。</pre>\n\n<p><strong>示例 4：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"a(bcdefghijkl(mno)p)q\"\n<strong>输出：</strong>\"apmnolkjihgfedcbq\"\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 2000</code></li>\n\t<li><code>s</code> 中只有小写英文字母和括号</li>\n\t<li>题目测试用例确保所有括号都是成对出现的</li>\n</ul>\n",
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            "hints": [
                "Find all brackets in the string.",
                "Does the order of the reverse matter ?",
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