leetcode-problemset/leetcode-cn/originData/removing-stars-from-a-string.json

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        "question": {
            "questionId": "2470",
            "questionFrontendId": "2390",
            "categoryTitle": "Algorithms",
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            "title": "Removing Stars From a String",
            "titleSlug": "removing-stars-from-a-string",
            "content": "<p>You are given a string <code>s</code>, which contains stars <code>*</code>.</p>\n\n<p>In one operation, you can:</p>\n\n<ul>\n\t<li>Choose a star in <code>s</code>.</li>\n\t<li>Remove the closest <strong>non-star</strong> character to its <strong>left</strong>, as well as remove the star itself.</li>\n</ul>\n\n<p>Return <em>the string after <strong>all</strong> stars have been removed</em>.</p>\n\n<p><strong>Note:</strong></p>\n\n<ul>\n\t<li>The input will be generated such that the operation is always possible.</li>\n\t<li>It can be shown that the resulting string will always be unique.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;leet**cod*e&quot;\n<strong>Output:</strong> &quot;lecoe&quot;\n<strong>Explanation:</strong> Performing the removals from left to right:\n- The closest character to the 1<sup>st</sup> star is &#39;t&#39; in &quot;lee<strong><u>t</u></strong>**cod*e&quot;. s becomes &quot;lee*cod*e&quot;.\n- The closest character to the 2<sup>nd</sup> star is &#39;e&#39; in &quot;le<strong><u>e</u></strong>*cod*e&quot;. s becomes &quot;lecod*e&quot;.\n- The closest character to the 3<sup>rd</sup> star is &#39;d&#39; in &quot;leco<strong><u>d</u></strong>*e&quot;. s becomes &quot;lecoe&quot;.\nThere are no more stars, so we return &quot;lecoe&quot;.</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> s = &quot;erase*****&quot;\n<strong>Output:</strong> &quot;&quot;\n<strong>Explanation:</strong> The entire string is removed, so we return an empty string.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> consists of lowercase English letters and stars <code>*</code>.</li>\n\t<li>The operation above can be performed on <code>s</code>.</li>\n</ul>\n",
            "translatedTitle": "从字符串中移除星号",
            "translatedContent": "<p>给你一个包含若干星号 <code>*</code> 的字符串 <code>s</code> 。</p>\n\n<p>在一步操作中，你可以：</p>\n\n<ul>\n\t<li>选中 <code>s</code> 中的一个星号。</li>\n\t<li>移除星号 <strong>左侧</strong> 最近的那个 <strong>非星号</strong> 字符，并移除该星号自身。</li>\n</ul>\n\n<p>返回移除 <strong>所有</strong> 星号之后的字符串<strong>。</strong></p>\n\n<p><strong>注意：</strong></p>\n\n<ul>\n\t<li>生成的输入保证总是可以执行题面中描述的操作。</li>\n\t<li>可以证明结果字符串是唯一的。</li>\n</ul>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"leet**cod*e\"\n<strong>输出：</strong>\"lecoe\"\n<strong>解释：</strong>从左到右执行移除操作：\n- 距离第 1 个星号最近的字符是 \"lee<em><strong>t</strong></em>**cod*e\" 中的 't' ，s 变为 \"lee*cod*e\" 。\n- 距离第 2 个星号最近的字符是 \"le<em><strong>e</strong></em>*cod*e\" 中的 'e' ，s 变为 \"lecod*e\" 。\n- 距离第 3 个星号最近的字符是 \"leco<em><strong>d</strong></em>*e\" 中的 'd' ，s 变为 \"lecoe\" 。\n不存在其他星号，返回 \"lecoe\" 。</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>s = \"erase*****\"\n<strong>输出：</strong>\"\"\n<strong>解释：</strong>整个字符串都会被移除，所以返回空字符串。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= s.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>s</code> 由小写英文字母和星号 <code>*</code> 组成</li>\n\t<li><code>s</code> 可以执行上述操作</li>\n</ul>\n",
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            "hints": [
                "What data structure could we use to efficiently perform these removals?",
                "Use a stack to store the characters. Pop one character off the stack at each star. Otherwise, we push the character onto the stack."
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