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{
"data": {
"question": {
"questionId": "2573",
"questionFrontendId": "2487",
"categoryTitle": "Algorithms",
"boundTopicId": 1990486,
"title": "Remove Nodes From Linked List",
"titleSlug": "remove-nodes-from-linked-list",
"content": "<p>You are given the <code>head</code> of a linked list.</p>\n\n<p>Remove every node which has a node with a greater value anywhere to the right side of it.</p>\n\n<p>Return <em>the </em><code>head</code><em> of the modified linked list.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/10/02/drawio.png\" style=\"width: 631px; height: 51px;\" />\n<pre>\n<strong>Input:</strong> head = [5,2,13,3,8]\n<strong>Output:</strong> [13,8]\n<strong>Explanation:</strong> The nodes that should be removed are 5, 2 and 3.\n- Node 13 is to the right of node 5.\n- Node 13 is to the right of node 2.\n- Node 8 is to the right of node 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> head = [1,1,1,1]\n<strong>Output:</strong> [1,1,1,1]\n<strong>Explanation:</strong> Every node has value 1, so no nodes are removed.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of the nodes in the given list is in the range <code>[1, 10<sup>5</sup>]</code>.</li>\n\t<li><code>1 &lt;= Node.val &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
"translatedTitle": "从链表中移除节点",
"translatedContent": "<p>给你一个链表的头节点 <code>head</code> 。</p>\n\n<p>移除每个右侧有一个更大数值的节点。</p>\n\n<p>返回修改后链表的头节点<em> </em><code>head</code><em> </em>。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<p><img alt=\"\" src=\"https://assets.leetcode.com/uploads/2022/10/02/drawio.png\" style=\"width: 631px; height: 51px;\" /></p>\n\n<pre>\n<strong>输入:</strong>head = [5,2,13,3,8]\n<strong>输出:</strong>[13,8]\n<strong>解释:</strong>需要移除的节点是 5 2 和 3 。\n- 节点 13 在节点 5 右侧。\n- 节点 13 在节点 2 右侧。\n- 节点 8 在节点 3 右侧。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<strong>输入:</strong>head = [1,1,1,1]\n<strong>输出:</strong>[1,1,1,1]\n<strong>解释:</strong>每个节点的值都是 1 ,所以没有需要移除的节点。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>给定列表中的节点数目在范围 <code>[1, 10<sup>5</sup>]</code> 内</li>\n\t<li><code>1 &lt;= Node.val &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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"code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n * int val;\n * ListNode *next;\n * ListNode() : val(0), next(nullptr) {}\n * ListNode(int x) : val(x), next(nullptr) {}\n * ListNode(int x, ListNode *next) : val(x), next(next) {}\n * };\n */\nclass Solution {\npublic:\n ListNode* removeNodes(ListNode* head) {\n \n }\n};",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * int val;\n * ListNode next;\n * ListNode() {}\n * ListNode(int val) { this.val = val; }\n * ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n public ListNode removeNodes(ListNode head) {\n\n }\n}",
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"code": "# Definition for singly-linked list.\n# class ListNode(object):\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution(object):\n def removeNodes(self, head):\n \"\"\"\n :type head: Optional[ListNode]\n :rtype: Optional[ListNode]\n \"\"\"",
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"code": "# Definition for singly-linked list.\n# class ListNode:\n# def __init__(self, val=0, next=None):\n# self.val = val\n# self.next = next\nclass Solution:\n def removeNodes(self, head: Optional[ListNode]) -> Optional[ListNode]:",
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"lang": "JavaScript",
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"code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {ListNode}\n */\nvar removeNodes = function(head) {\n\n};",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n * val: number\n * next: ListNode | null\n * constructor(val?: number, next?: ListNode | null) {\n * this.val = (val===undefined ? 0 : val)\n * this.next = (next===undefined ? null : next)\n * }\n * }\n */\n\nfunction removeNodes(head: ListNode | null): ListNode | null {\n \n};",
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"code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n * public var val: Int\n * public var next: ListNode?\n * public init() { self.val = 0; self.next = nil; }\n * public init(_ val: Int) { self.val = val; self.next = nil; }\n * public init(_ val: Int, _ next: ListNode?) { self.val = val; self.next = next; }\n * }\n */\nclass Solution {\n func removeNodes(_ head: ListNode?) -> ListNode? {\n\n }\n}",
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"lang": "Kotlin",
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"code": "/**\n * Example:\n * var li = ListNode(5)\n * var v = li.`val`\n * Definition for singly-linked list.\n * class ListNode(var `val`: Int) {\n * var next: ListNode? = null\n * }\n */\nclass Solution {\n fun removeNodes(head: ListNode?): ListNode? {\n\n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n * int val;\n * ListNode? next;\n * ListNode([this.val = 0, this.next]);\n * }\n */\nclass Solution {\n ListNode? removeNodes(ListNode? head) {\n \n }\n}",
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"code": "/**\n * Definition for singly-linked list.\n * type ListNode struct {\n * Val int\n * Next *ListNode\n * }\n */\nfunc removeNodes(head *ListNode) *ListNode {\n\n}",
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"code": "# Definition for singly-linked list.\n# class ListNode\n# attr_accessor :val, :next\n# def initialize(val = 0, _next = nil)\n# @val = val\n# @next = _next\n# end\n# end\n# @param {ListNode} head\n# @return {ListNode}\ndef remove_nodes(head)\n\nend",
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"code": "/**\n * Definition for singly-linked list.\n * class ListNode(_x: Int = 0, _next: ListNode = null) {\n * var next: ListNode = _next\n * var x: Int = _x\n * }\n */\nobject Solution {\n def removeNodes(head: ListNode): ListNode = {\n\n }\n}",
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"lang": "Rust",
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"code": "// Definition for singly-linked list.\n// #[derive(PartialEq, Eq, Clone, Debug)]\n// pub struct ListNode {\n// pub val: i32,\n// pub next: Option<Box<ListNode>>\n// }\n//\n// impl ListNode {\n// #[inline]\n// fn new(val: i32) -> Self {\n// ListNode {\n// next: None,\n// val\n// }\n// }\n// }\nimpl Solution {\n pub fn remove_nodes(head: Option<Box<ListNode>>) -> Option<Box<ListNode>> {\n\n }\n}",
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{
"lang": "Racket",
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"code": "; Definition for singly-linked list:\n#|\n\n; val : integer?\n; next : (or/c list-node? #f)\n(struct list-node\n (val next) #:mutable #:transparent)\n\n; constructor\n(define (make-list-node [val 0])\n (list-node val #f))\n\n|#\n\n(define/contract (remove-nodes head)\n (-> (or/c list-node? #f) (or/c list-node? #f))\n )",
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"lang": "Erlang",
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"code": "%% Definition for singly-linked list.\n%%\n%% -record(list_node, {val = 0 :: integer(),\n%% next = null :: 'null' | #list_node{}}).\n\n-spec remove_nodes(Head :: #list_node{} | null) -> #list_node{} | null.\nremove_nodes(Head) ->\n .",
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"lang": "Elixir",
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"code": "# Definition for singly-linked list.\n#\n# defmodule ListNode do\n# @type t :: %__MODULE__{\n# val: integer,\n# next: ListNode.t() | nil\n# }\n# defstruct val: 0, next: nil\n# end\n\ndefmodule Solution do\n @spec remove_nodes(head :: ListNode.t | nil) :: ListNode.t | nil\n def remove_nodes(head) do\n \n end\nend",
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"Iterate on nodes in reversed order.",
"When iterating in reversed order, save the maximum value that was passed before."
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