mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
synced 2025-01-10 18:48:13 +08:00
161 lines
21 KiB
JSON
161 lines
21 KiB
JSON
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"questionId": "1000563",
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"questionFrontendId": "LCP 75",
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"categoryTitle": "Algorithms",
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"boundTopicId": 2239382,
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"title": "传送卷轴",
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"titleSlug": "rdmXM7",
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"content": "English description is not available for the problem. Please switch to Chinese.",
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"translatedTitle": "传送卷轴",
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"translatedContent": "随着不断的深入,小扣来到了守护者之森寻找的魔法水晶。首先,他必须先通过守护者的考验。\n\n考验的区域是一个正方形的迷宫,`maze[i][j]` 表示在迷宫 `i` 行 `j` 列的地形:\n- 若为 `.` ,表示可以到达的空地;\n- 若为 `#` ,表示不可到达的墙壁;\n- 若为 `S` ,表示小扣的初始位置;\n- 若为 `T` ,表示魔法水晶的位置。\n\n小扣每次可以向 上、下、左、右 相邻的位置移动一格。而守护者拥有一份「传送魔法卷轴」,使用规则如下:\n- 魔法需要在小扣位于 **空地** 时才能释放,发动后卷轴消失;;\n- 发动后,小扣会被传送到水平或者竖直的镜像位置,且目标位置不得为墙壁(如下图所示);\n![image.png](https://pic.leetcode.cn/1681789509-wTekFu-image.png){:width=400px}\n\n在使用卷轴后,小扣将被「附加负面效果」,因此小扣需要尽可能缩短传送后到达魔法水晶的距离。而守护者的目标是阻止小扣到达魔法水晶的位置;如果无法阻止,则尽可能 **增加** 小扣传送后到达魔法水晶的距离。\n假设小扣和守护者都按最优策略行事,返回小扣需要在 「附加负面效果」的情况下 **最少** 移动多少次才能到达魔法水晶。如果无法到达,返回 `-1`。\n\n**注意:**\n- 守护者可以不使用卷轴;\n- 传送后的镜像位置可能与原位置相同。\n\n**示例 1:**\n>输入:`maze = [\".....\",\"##S..\",\"...#.\",\"T.#..\",\"###..\"]`\n>\n>输出:`7`\n>\n>解释:如下图所示:\n>守护者释放魔法的两个最佳的位置为 [2,0] 或 [3,1]:\n>若小扣经过 [2,0],守护者在该位置释放魔法,\n>小扣被传送至 [2,4] 处且加上负面效果,此时小扣还需要移动 7 次才能到达魔法水晶;\n>若小扣经过 [3,1],守护者在该位置释放魔法,\n>小扣被传送至 [3,3] 处且加上负面效果,此时小扣还需要移动 9 次才能到达魔法水晶;\n>因此小扣负面效果下最少需要移动 7 次才能到达魔法水晶。\n![image.png](https://pic.leetcode.cn/1681714676-gksEMT-image.png){:width=300px}\n\n\n**示例 2:**\n>输入:`maze = [\".#..\",\"..##\",\".#S.\",\".#.T\"]`\n>\n>输出:`-1`\n>\n>解释:如下图所示。\n>若小扣向下移动至 [3,2],守护者使其传送至 [0,2],小扣将无法到达魔法水晶;\n>若小扣向右移动至 [2,3],守护者使其传送至 [2,0],小扣将无法到达魔法水晶;\n![image.png](https://pic.leetcode.cn/1681714693-LsxKAh-image.png){:width=300px}\n\n\n**示例 3:**\n>输入:`maze = [\"S###.\",\"..###\",\"#..##\",\"##..#\",\"###.T\"]`\n>\n>输出:`5`\n>\n>解释:如下图所示:\n>守护者需要小扣在空地才能释放,因此初始无法将其从 [0,0] 传送至 [0,4];\n>当小扣移动至 [2,1] 时,释放卷轴将其传送至水平方向的镜像位置 [2,1](为原位置)\n>而后小扣需要移动 5 次到达魔法水晶\n![image.png](https://pic.leetcode.cn/1681800985-KrSdru-image.png){:width=300px}\n\n**提示:**\n- `4 <= maze.length == maze[i].length <= 200`\n- `maze[i][j]` 仅包含 `\".\"`、`\"#\"`、`\"S\"`、`\"T\"`",
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