leetcode-problemset/leetcode-cn/originData/power-set-lcci.json

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        "question": {
            "questionId": "100198",
            "questionFrontendId": "面试题 08.04",
            "categoryTitle": "LCCI",
            "boundTopicId": 49280,
            "title": "Power Set LCCI",
            "titleSlug": "power-set-lcci",
            "content": "<p>Write a method to return all subsets of a set. The elements in a set are&nbsp;pairwise distinct.</p>\r\n\r\n<p>Note: The result set should not contain duplicated subsets.</p>\r\n\r\n<p><strong>Example:</strong></p>\r\n\r\n<pre>\r\n<strong> Input</strong>:  nums = [1,2,3]\r\n<strong> Output</strong>: \r\n[\r\n  [3],\r\n&nbsp; [1],\r\n&nbsp; [2],\r\n&nbsp; [1,2,3],\r\n&nbsp; [1,3],\r\n&nbsp; [2,3],\r\n&nbsp; [1,2],\r\n&nbsp; []\r\n]\r\n</pre>\r\n",
            "translatedTitle": "幂集",
            "translatedContent": "<p>幂集。编写一种方法，返回某集合的所有子集。集合中<strong>不包含重复的元素</strong>。</p>\n\n<p>说明：解集不能包含重复的子集。</p>\n\n<p><strong>示例:</strong></p>\n\n<pre><strong> 输入</strong>： nums = [1,2,3]\n<strong> 输出</strong>：\n[\n  [3],\n&nbsp; [1],\n&nbsp; [2],\n&nbsp; [1,2,3],\n&nbsp; [1,3],\n&nbsp; [2,3],\n&nbsp; [1,2],\n&nbsp; []\n]\n</pre>\n",
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                {
                    "name": "Bit Manipulation",
                    "slug": "bit-manipulation",
                    "translatedName": "位运算",
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                    "lang": "C++",
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                    "code": "class Solution {\npublic:\n    vector<vector<int>> subsets(vector<int>& nums) {\n\n    }\n};",
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                    "code": "class Solution {\n    public List<List<Integer>> subsets(int[] nums) {\n\n    }\n}",
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                    "code": "class Solution(object):\n    def subsets(self, nums):\n        \"\"\"\n        :type nums: List[int]\n        :rtype: List[List[int]]\n        \"\"\"",
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                    "code": "/**\n * @param {number[]} nums\n * @return {number[][]}\n */\nvar subsets = function(nums) {\n\n};",
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                    "code": "class Solution {\n\n    /**\n     * @param Integer[] $nums\n     * @return Integer[][]\n     */\n    function subsets($nums) {\n\n    }\n}",
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                    "code": "class Solution {\n    func subsets(_ nums: [Int]) -> [[Int]] {\n\n    }\n}",
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                    "code": "class Solution {\n    fun subsets(nums: IntArray): List<List<Int>> {\n\n    }\n}",
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                    "code": "class Solution {\n  List<List<int>> subsets(List<int> nums) {\n\n  }\n}",
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                    "lang": "Go",
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                    "code": "func subsets(nums []int) [][]int {\n\n}",
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                    "lang": "Ruby",
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                    "code": "# @param {Integer[]} nums\n# @return {Integer[][]}\ndef subsets(nums)\n\nend",
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                    "code": "object Solution {\n    def subsets(nums: Array[Int]): List[List[Int]] = {\n\n    }\n}",
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                    "lang": "Rust",
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                    "code": "impl Solution {\n    pub fn subsets(nums: Vec<i32>) -> Vec<Vec<i32>> {\n\n    }\n}",
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                    "lang": "Elixir",
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                    "code": "defmodule Solution do\n  @spec subsets(nums :: [integer]) :: [[integer]]\n  def subsets(nums) do\n\n  end\nend",
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            "hints": [
                "如何从子集{a, b}中构建{a, b, c}的所有子集？",
                "任何属于{a, b}的子集都是{a, b, c}的子集。哪个集合是{a, b, c}的子集却不是{a, b}的子集。",
                "包含c的子集是{a, b, c}，而非{a, b}。你能使用子集{a, b}构建这些子集吗？",
                "通过把c加到所有{a, b}的子集里，你可以构建剩余的子集。",
                "你也可以将每个子集映射成二进制数。第i位可以表示元素是否在集合中的“布尔”标志。"
            ],
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