leetcode-problemset/leetcode-cn/originData/partition-array-such-that-maximum-difference-is-k.json

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        "question": {
            "questionId": "2387",
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            "categoryTitle": "Algorithms",
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            "title": "Partition Array Such That Maximum Difference Is K",
            "titleSlug": "partition-array-such-that-maximum-difference-is-k",
            "content": "<p>You are given an integer array <code>nums</code> and an integer <code>k</code>. You may partition <code>nums</code> into one or more <strong>subsequences</strong> such that each element in <code>nums</code> appears in <strong>exactly</strong> one of the subsequences.</p>\n\n<p>Return <em>the <strong>minimum </strong>number of subsequences needed such that the difference between the maximum and minimum values in each subsequence is <strong>at most</strong> </em><code>k</code><em>.</em></p>\n\n<p>A <strong>subsequence</strong> is a sequence that can be derived from another sequence by deleting some or no elements without changing the order of the remaining elements.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,6,1,2,5], k = 2\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nWe can partition nums into the two subsequences [3,1,2] and [6,5].\nThe difference between the maximum and minimum value in the first subsequence is 3 - 1 = 2.\nThe difference between the maximum and minimum value in the second subsequence is 6 - 5 = 1.\nSince two subsequences were created, we return 2. It can be shown that 2 is the minimum number of subsequences needed.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,2,3], k = 1\n<strong>Output:</strong> 2\n<strong>Explanation:</strong>\nWe can partition nums into the two subsequences [1,2] and [3].\nThe difference between the maximum and minimum value in the first subsequence is 2 - 1 = 1.\nThe difference between the maximum and minimum value in the second subsequence is 3 - 3 = 0.\nSince two subsequences were created, we return 2. Note that another optimal solution is to partition nums into the two subsequences [1] and [2,3].\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,2,4,5], k = 0\n<strong>Output:</strong> 3\n<strong>Explanation:</strong>\nWe can partition nums into the three subsequences [2,2], [4], and [5].\nThe difference between the maximum and minimum value in the first subsequences is 2 - 2 = 0.\nThe difference between the maximum and minimum value in the second subsequences is 4 - 4 = 0.\nThe difference between the maximum and minimum value in the third subsequences is 5 - 5 = 0.\nSince three subsequences were created, we return 3. It can be shown that 3 is the minimum number of subsequences needed.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "划分数组使最大差为 K",
            "translatedContent": "<p>给你一个整数数组 <code>nums</code> 和一个整数 <code>k</code> 。你可以将 <code>nums</code> 划分成一个或多个 <strong>子序列</strong> ，使 <code>nums</code> 中的每个元素都 <strong>恰好</strong> 出现在一个子序列中。</p>\n\n<p>在满足每个子序列中最大值和最小值之间的差值最多为 <code>k</code> 的前提下，返回需要划分的 <strong>最少</strong> 子序列数目。</p>\n\n<p><strong>子序列</strong> 本质是一个序列，可以通过删除另一个序列中的某些元素（或者不删除）但不改变剩下元素的顺序得到。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [3,6,1,2,5], k = 2\n<strong>输出：</strong>2\n<strong>解释：</strong>\n可以将 nums 划分为两个子序列 [3,1,2] 和 [6,5] 。\n第一个子序列中最大值和最小值的差值是 3 - 1 = 2 。\n第二个子序列中最大值和最小值的差值是 6 - 5 = 1 。\n由于创建了两个子序列，返回 2 。可以证明需要划分的最少子序列数目就是 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [1,2,3], k = 1\n<strong>输出：</strong>2\n<strong>解释：</strong>\n可以将 nums 划分为两个子序列 [1,2] 和 [3] 。\n第一个子序列中最大值和最小值的差值是 2 - 1 = 1 。\n第二个子序列中最大值和最小值的差值是 3 - 3 = 0 。\n由于创建了两个子序列，返回 2 。注意，另一种最优解法是将 nums 划分成子序列 [1] 和 [2,3] 。\n</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums = [2,2,4,5], k = 0\n<strong>输出：</strong>3\n<strong>解释：</strong>\n可以将 nums 划分为三个子序列 [2,2]、[4] 和 [5] 。\n第一个子序列中最大值和最小值的差值是 2 - 2 = 0 。\n第二个子序列中最大值和最小值的差值是 4 - 4 = 0 。\n第三个子序列中最大值和最小值的差值是 5 - 5 = 0 。\n由于创建了三个子序列，返回 3 。可以证明需要划分的最少子序列数目就是 3 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= nums[i] &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= k &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
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                "Which values in each subsequence matter? The only values that matter are the maximum and minimum values.",
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