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"question": {
"questionId": "2547",
"questionFrontendId": "2451",
"categoryTitle": "Algorithms",
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"title": "Odd String Difference",
"titleSlug": "odd-string-difference",
"content": "<p>You are given an array of equal-length strings <code>words</code>. Assume that the length of each string is <code>n</code>.</p>\n\n<p>Each string <code>words[i]</code> can be converted into a <strong>difference integer array</strong> <code>difference[i]</code> of length <code>n - 1</code> where <code>difference[i][j] = words[i][j+1] - words[i][j]</code> where <code>0 &lt;= j &lt;= n - 2</code>. Note that the difference between two letters is the difference between their <strong>positions</strong> in the alphabet i.e.&nbsp;the position of <code>&#39;a&#39;</code> is <code>0</code>, <code>&#39;b&#39;</code> is <code>1</code>, and <code>&#39;z&#39;</code> is <code>25</code>.</p>\n\n<ul>\n\t<li>For example, for the string <code>&quot;acb&quot;</code>, the difference integer array is <code>[2 - 0, 1 - 2] = [2, -1]</code>.</li>\n</ul>\n\n<p>All the strings in words have the same difference integer array, <strong>except one</strong>. You should find that string.</p>\n\n<p>Return<em> the string in </em><code>words</code><em> that has different <strong>difference integer array</strong>.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;adc&quot;,&quot;wzy&quot;,&quot;abc&quot;]\n<strong>Output:</strong> &quot;abc&quot;\n<strong>Explanation:</strong> \n- The difference integer array of &quot;adc&quot; is [3 - 0, 2 - 3] = [3, -1].\n- The difference integer array of &quot;wzy&quot; is [25 - 22, 24 - 25]= [3, -1].\n- The difference integer array of &quot;abc&quot; is [1 - 0, 2 - 1] = [1, 1]. \nThe odd array out is [1, 1], so we return the corresponding string, &quot;abc&quot;.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> words = [&quot;aaa&quot;,&quot;bob&quot;,&quot;ccc&quot;,&quot;ddd&quot;]\n<strong>Output:</strong> &quot;bob&quot;\n<strong>Explanation:</strong> All the integer arrays are [0, 0] except for &quot;bob&quot;, which corresponds to [13, -13].\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= words.length &lt;= 100</code></li>\n\t<li><code>n == words[i].length</code></li>\n\t<li><code>2 &lt;= n &lt;= 20</code></li>\n\t<li><code>words[i]</code> consists of lowercase English letters.</li>\n</ul>\n",
"translatedTitle": "差值数组不同的字符串",
"translatedContent": "<p>给你一个字符串数组 <code>words</code>&nbsp;,每一个字符串长度都相同,令所有字符串的长度都为 <code>n</code>&nbsp;。</p>\n\n<p>每个字符串&nbsp;<code>words[i]</code>&nbsp;可以被转化为一个长度为&nbsp;<code>n - 1</code>&nbsp;的&nbsp;<strong>差值整数数组</strong>&nbsp;<code>difference[i]</code>&nbsp;,其中对于&nbsp;<code>0 &lt;= j &lt;= n - 2</code>&nbsp;有&nbsp;<code>difference[i][j] = words[i][j+1] - words[i][j]</code>&nbsp;。注意两个字母的差值定义为它们在字母表中&nbsp;<strong>位置</strong>&nbsp;之差,也就是说&nbsp;<code>'a'</code>&nbsp;的位置是&nbsp;<code>0</code>&nbsp;<code>'b'</code>&nbsp;的位置是&nbsp;<code>1</code>&nbsp;<code>'z'</code>&nbsp;的位置是&nbsp;<code>25</code>&nbsp;。</p>\n\n<ul>\n\t<li>比方说,字符串&nbsp;<code>\"acb\"</code>&nbsp;的差值整数数组是&nbsp;<code>[2 - 0, 1 - 2] = [2, -1]</code>&nbsp;。</li>\n</ul>\n\n<p><code>words</code>&nbsp;中所有字符串 <strong>除了一个字符串以外</strong>&nbsp;,其他字符串的差值整数数组都相同。你需要找到那个不同的字符串。</p>\n\n<p>请你返回<em>&nbsp;</em><code>words</code>中&nbsp;<strong>差值整数数组</strong>&nbsp;不同的字符串。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1</strong></p>\n\n<pre>\n<b>输入:</b>words = [\"adc\",\"wzy\",\"abc\"]\n<b>输出:</b>\"abc\"\n<b>解释:</b>\n- \"adc\" 的差值整数数组是 [3 - 0, 2 - 3] = [3, -1] 。\n- \"wzy\" 的差值整数数组是 [25 - 22, 24 - 25]= [3, -1] 。\n- \"abc\" 的差值整数数组是 [1 - 0, 2 - 1] = [1, 1] 。\n不同的数组是 [1, 1],所以返回对应的字符串,\"abc\"。\n</pre>\n\n<p><strong>示例 2</strong></p>\n\n<pre>\n<b>输入:</b>words = [\"aaa\",\"bob\",\"ccc\",\"ddd\"]\n<b>输出:</b>\"bob\"\n<b>解释:</b>除了 \"bob\" 的差值整数数组是 [13, -13] 以外,其他字符串的差值整数数组都是 [0, 0] 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li><code>3 &lt;= words.length &lt;= 100</code></li>\n\t<li><code>n == words[i].length</code></li>\n\t<li><code>2 &lt;= n &lt;= 20</code></li>\n\t<li><code>words[i]</code>&nbsp;只含有小写英文字母。</li>\n</ul>\n",
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