leetcode-problemset/leetcode-cn/originData/number-of-times-binary-string-is-prefix-aligned.json

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            "title": "Number of Times Binary String Is Prefix-Aligned",
            "titleSlug": "number-of-times-binary-string-is-prefix-aligned",
            "content": "<p>You have a <strong>1-indexed</strong> binary string of length <code>n</code> where all the bits are <code>0</code> initially. We will flip all the bits of this binary string (i.e., change them from <code>0</code> to <code>1</code>) one by one. You are given a <strong>1-indexed</strong> integer array <code>flips</code> where <code>flips[i]</code> indicates that the bit at index <code>i</code> will be flipped in the <code>i<sup>th</sup></code> step.</p>\n\n<p>A binary string is <strong>prefix-aligned</strong> if, after the <code>i<sup>th</sup></code> step, all the bits in the <strong>inclusive</strong> range <code>[1, i]</code> are ones and all the other bits are zeros.</p>\n\n<p>Return <em>the number of times the binary string is <strong>prefix-aligned</strong> during the flipping process</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> flips = [3,2,4,1,5]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> The binary string is initially &quot;00000&quot;.\nAfter applying step 1: The string becomes &quot;00100&quot;, which is not prefix-aligned.\nAfter applying step 2: The string becomes &quot;01100&quot;, which is not prefix-aligned.\nAfter applying step 3: The string becomes &quot;01110&quot;, which is not prefix-aligned.\nAfter applying step 4: The string becomes &quot;11110&quot;, which is prefix-aligned.\nAfter applying step 5: The string becomes &quot;11111&quot;, which is prefix-aligned.\nWe can see that the string was prefix-aligned 2 times, so we return 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> flips = [4,1,2,3]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> The binary string is initially &quot;0000&quot;.\nAfter applying step 1: The string becomes &quot;0001&quot;, which is not prefix-aligned.\nAfter applying step 2: The string becomes &quot;1001&quot;, which is not prefix-aligned.\nAfter applying step 3: The string becomes &quot;1101&quot;, which is not prefix-aligned.\nAfter applying step 4: The string becomes &quot;1111&quot;, which is prefix-aligned.\nWe can see that the string was prefix-aligned 1 time, so we return 1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == flips.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>flips</code> is a permutation of the integers in the range <code>[1, n]</code>.</li>\n</ul>\n",
            "translatedTitle": "二进制字符串前缀一致的次数",
            "translatedContent": "<p>给你一个长度为 <code>n</code> 、下标从 <strong>1</strong> 开始的二进制字符串，所有位最开始都是 <code>0</code> 。我们会按步翻转该二进制字符串的所有位（即，将 <code>0</code> 变为 <code>1</code>）。</p>\n\n<p>给你一个下标从 <strong>1</strong> 开始的整数数组 <code>flips</code> ，其中 <code>flips[i]</code> 表示对应下标 <code>i</code> 的位将会在第 <code>i</code> 步翻转。</p>\n\n<p>二进制字符串 <strong>前缀一致</strong> 需满足：在第 <code>i</code> 步之后，在 <strong>闭</strong> 区间&nbsp;<code>[1, i]</code> 内的所有位都是 1 ，而其他位都是 0 。</p>\n\n<p>返回二进制字符串在翻转过程中 <strong>前缀一致</strong> 的次数。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>flips = [3,2,4,1,5]\n<strong>输出：</strong>2\n<strong>解释：</strong>二进制字符串最开始是 \"00000\" 。\n执行第 1 步：字符串变为 \"00100\" ，不属于前缀一致的情况。\n执行第 2 步：字符串变为 \"01100\" ，不属于前缀一致的情况。\n执行第 3 步：字符串变为 \"01110\" ，不属于前缀一致的情况。\n执行第 4 步：字符串变为 \"11110\" ，属于前缀一致的情况。\n执行第 5 步：字符串变为 \"11111\" ，属于前缀一致的情况。\n在翻转过程中，前缀一致的次数为 2 ，所以返回 2 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>flips = [4,1,2,3]\n<strong>输出：</strong>1\n<strong>解释：</strong>二进制字符串最开始是 \"0000\" 。\n执行第 1 步：字符串变为 \"0001\" ，不属于前缀一致的情况。\n执行第 2 步：字符串变为 \"1001\" ，不属于前缀一致的情况。\n执行第 3 步：字符串变为 \"1101\" ，不属于前缀一致的情况。\n执行第 4 步：字符串变为 \"1111\" ，属于前缀一致的情况。\n在翻转过程中，前缀一致的次数为 1 ，所以返回 1 。</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == flips.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 5 * 10<sup>4</sup></code></li>\n\t<li><code>flips</code> 是范围 <code>[1, n]</code> 中所有整数构成的一个排列</li>\n</ul>\n",
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