leetcode-problemset/leetcode-cn/originData/node-with-highest-edge-score.json

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        "question": {
            "questionId": "2455",
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            "title": "Node With Highest Edge Score",
            "titleSlug": "node-with-highest-edge-score",
            "content": "<p>You are given a directed graph with <code>n</code> nodes labeled from <code>0</code> to <code>n - 1</code>, where each node has <strong>exactly one</strong> outgoing edge.</p>\n\n<p>The graph is represented by a given <strong>0-indexed</strong> integer array <code>edges</code> of length <code>n</code>, where <code>edges[i]</code> indicates that there is a <strong>directed</strong> edge from node <code>i</code> to node <code>edges[i]</code>.</p>\n\n<p>The <strong>edge score</strong> of a node <code>i</code> is defined as the sum of the <strong>labels</strong> of all the nodes that have an edge pointing to <code>i</code>.</p>\n\n<p>Return <em>the node with the highest <strong>edge score</strong></em>. If multiple nodes have the same <strong>edge score</strong>, return the node with the <strong>smallest</strong> index.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img src=\"https://assets.leetcode.com/uploads/2022/06/20/image-20220620195403-1.png\" style=\"width: 450px; height: 260px;\" />\n<pre>\n<strong>Input:</strong> edges = [1,0,0,0,0,7,7,5]\n<strong>Output:</strong> 7\n<strong>Explanation:</strong>\n- The nodes 1, 2, 3 and 4 have an edge pointing to node 0. The edge score of node 0 is 1 + 2 + 3 + 4 = 10.\n- The node 0 has an edge pointing to node 1. The edge score of node 1 is 0.\n- The node 7 has an edge pointing to node 5. The edge score of node 5 is 7.\n- The nodes 5 and 6 have an edge pointing to node 7. The edge score of node 7 is 5 + 6 = 11.\nNode 7 has the highest edge score so return 7.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img src=\"https://assets.leetcode.com/uploads/2022/06/20/image-20220620200212-3.png\" style=\"width: 150px; height: 155px;\" />\n<pre>\n<strong>Input:</strong> edges = [2,0,0,2]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong>\n- The nodes 1 and 2 have an edge pointing to node 0. The edge score of node 0 is 1 + 2 = 3.\n- The nodes 0 and 3 have an edge pointing to node 2. The edge score of node 2 is 0 + 3 = 3.\nNodes 0 and 2 both have an edge score of 3. Since node 0 has a smaller index, we return 0.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == edges.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= edges[i] &lt; n</code></li>\n\t<li><code>edges[i] != i</code></li>\n</ul>\n",
            "translatedTitle": "边积分最高的节点",
            "translatedContent": "<p>给你一个有向图，图中有 <code>n</code> 个节点，节点编号从 <code>0</code> 到 <code>n - 1</code> ，其中每个节点都 <strong>恰有一条</strong> 出边。</p>\n\n<p>图由一个下标从 <strong>0</strong> 开始、长度为 <code>n</code> 的整数数组 <code>edges</code> 表示，其中 <code>edges[i]</code> 表示存在一条从节点 <code>i</code> 到节点 <code>edges[i]</code> 的 <strong>有向</strong> 边。</p>\n\n<p>节点 <code>i</code> 的 <strong>边积分</strong> 定义为：所有存在一条指向节点 <code>i</code> 的边的节点的 <strong>编号</strong> 总和。</p>\n\n<p>返回 <strong>边积分</strong> 最高的节点。如果多个节点的 <strong>边积分</strong> 相同，返回编号 <strong>最小</strong> 的那个。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n<img src=\"https://assets.leetcode.com/uploads/2022/06/20/image-20220620195403-1.png\" style=\"width: 450px; height: 260px;\">\n<pre><strong>输入：</strong>edges = [1,0,0,0,0,7,7,5]\n<strong>输出：</strong>7\n<strong>解释：</strong>\n- 节点 1、2、3 和 4 都有指向节点 0 的边，节点 0 的边积分等于 1 + 2 + 3 + 4 = 10 。\n- 节点 0 有一条指向节点 1 的边，节点 1 的边积分等于 0 。\n- 节点 7 有一条指向节点 5 的边，节点 5 的边积分等于 7 。\n- 节点 5 和 6 都有指向节点 7 的边，节点 7 的边积分等于 5 + 6 = 11 。\n节点 7 的边积分最高，所以返回 7 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n<img src=\"https://assets.leetcode.com/uploads/2022/06/20/image-20220620200212-3.png\" style=\"width: 150px; height: 155px;\">\n<pre><strong>输入：</strong>edges = [2,0,0,2]\n<strong>输出：</strong>0\n<strong>解释：\n</strong>- 节点 1 和 2 都有指向节点 0 的边，节点 0 的边积分等于 1 + 2 = 3 。\n- 节点 0 和 3 都有指向节点 2 的边，节点 2 的边积分等于 0 + 3 = 3 。\n节点 0 和 2 的边积分都是 3 。由于节点 0 的编号更小，返回 0 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == edges.length</code></li>\n\t<li><code>2 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>0 &lt;= edges[i] &lt; n</code></li>\n\t<li><code>edges[i] != i</code></li>\n</ul>\n",
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