mirror of
https://gitee.com/coder-xiaomo/leetcode-problemset
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186 lines
26 KiB
JSON
186 lines
26 KiB
JSON
{
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"questionId": "508",
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"categoryTitle": "Algorithms",
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"boundTopicId": 1655,
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"title": "Most Frequent Subtree Sum",
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"titleSlug": "most-frequent-subtree-sum",
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"content": "<p>Given the <code>root</code> of a binary tree, return the most frequent <strong>subtree sum</strong>. If there is a tie, return all the values with the highest frequency in any order.</p>\n\n<p>The <strong>subtree sum</strong> of a node is defined as the sum of all the node values formed by the subtree rooted at that node (including the node itself).</p>\n\n<p> </p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/24/freq1-tree.jpg\" style=\"width: 207px; height: 183px;\" />\n<pre>\n<strong>Input:</strong> root = [5,2,-3]\n<strong>Output:</strong> [2,-3,4]\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/04/24/freq2-tree.jpg\" style=\"width: 207px; height: 183px;\" />\n<pre>\n<strong>Input:</strong> root = [5,2,-5]\n<strong>Output:</strong> [2]\n</pre>\n\n<p> </p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the tree is in the range <code>[1, 10<sup>4</sup>]</code>.</li>\n\t<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>\n</ul>\n",
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"translatedTitle": "出现次数最多的子树元素和",
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"translatedContent": "<p>给你一个二叉树的根结点 <code>root</code> ，请返回出现次数最多的子树元素和。如果有多个元素出现的次数相同，返回所有出现次数最多的子树元素和（不限顺序）。</p>\n\n<p>一个结点的 <strong>「子树元素和」</strong> 定义为以该结点为根的二叉树上所有结点的元素之和（包括结点本身）。</p>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/04/24/freq1-tree.jpg\" /></p>\n\n<pre>\n<strong>输入:</strong> root = [5,2,-3]\n<strong>输出:</strong> [2,-3,4]\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<p><img src=\"https://assets.leetcode.com/uploads/2021/04/24/freq2-tree.jpg\" /></p>\n\n<pre>\n<strong>输入:</strong> root = [5,2,-5]\n<b>输出:</b> [2]\n</pre>\n\n<p> </p>\n\n<p><strong>提示:</strong></p>\n\n<ul>\n\t<li>节点数在 <code>[1, 10<sup>4</sup>]</code> 范围内</li>\n\t<li><code>-10<sup>5</sup> <= Node.val <= 10<sup>5</sup></code></li>\n</ul>\n",
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"code": "/**\n * Definition for a binary tree node.\n * struct TreeNode {\n * int val;\n * TreeNode *left;\n * TreeNode *right;\n * TreeNode() : val(0), left(nullptr), right(nullptr) {}\n * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}\n * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}\n * };\n */\nclass Solution {\npublic:\n vector<int> findFrequentTreeSum(TreeNode* root) {\n\n }\n};",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public int val;\n * public TreeNode left;\n * public TreeNode right;\n * public TreeNode(int val=0, TreeNode left=null, TreeNode right=null) {\n * this.val = val;\n * this.left = left;\n * this.right = right;\n * }\n * }\n */\npublic class Solution {\n public int[] FindFrequentTreeSum(TreeNode root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode {\n * public $val = null;\n * public $left = null;\n * public $right = null;\n * function __construct($val = 0, $left = null, $right = null) {\n * $this->val = $val;\n * $this->left = $left;\n * $this->right = $right;\n * }\n * }\n */\nclass Solution {\n\n /**\n * @param TreeNode $root\n * @return Integer[]\n */\n function findFrequentTreeSum($root) {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * public class TreeNode {\n * public var val: Int\n * public var left: TreeNode?\n * public var right: TreeNode?\n * public init() { self.val = 0; self.left = nil; self.right = nil; }\n * public init(_ val: Int) { self.val = val; self.left = nil; self.right = nil; }\n * public init(_ val: Int, _ left: TreeNode?, _ right: TreeNode?) {\n * self.val = val\n * self.left = left\n * self.right = right\n * }\n * }\n */\nclass Solution {\n func findFrequentTreeSum(_ root: TreeNode?) -> [Int] {\n\n }\n}",
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"code": "/**\n * Definition for a binary tree node.\n * type TreeNode struct {\n * Val int\n * Left *TreeNode\n * Right *TreeNode\n * }\n */\nfunc findFrequentTreeSum(root *TreeNode) []int {\n\n}",
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"code": "# Definition for a binary tree node.\n# class TreeNode\n# attr_accessor :val, :left, :right\n# def initialize(val = 0, left = nil, right = nil)\n# @val = val\n# @left = left\n# @right = right\n# end\n# end\n# @param {TreeNode} root\n# @return {Integer[]}\ndef find_frequent_tree_sum(root)\n\nend",
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"code": "/**\n * Definition for a binary tree node.\n * class TreeNode(_value: Int = 0, _left: TreeNode = null, _right: TreeNode = null) {\n * var value: Int = _value\n * var left: TreeNode = _left\n * var right: TreeNode = _right\n * }\n */\nobject Solution {\n def findFrequentTreeSum(root: TreeNode): Array[Int] = {\n\n }\n}",
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