leetcode-problemset/leetcode-cn/originData/minimum-right-shifts-to-sort-the-array.json

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            "title": "Minimum Right Shifts to Sort the Array",
            "titleSlug": "minimum-right-shifts-to-sort-the-array",
            "content": "<p>You are given a <strong>0-indexed</strong> array <code>nums</code> of length <code>n</code> containing <strong>distinct</strong> positive integers. Return <em>the <strong>minimum</strong> number of <strong>right shifts</strong> required to sort </em><code>nums</code><em> and </em><code>-1</code><em> if this is not possible.</em></p>\n\n<p>A <strong>right shift</strong> is defined as shifting the element at index <code>i</code> to index <code>(i + 1) % n</code>, for all indices.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [3,4,5,1,2]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> \nAfter the first right shift, nums = [2,3,4,5,1].\nAfter the second right shift, nums = [1,2,3,4,5].\nNow nums is sorted; therefore the answer is 2.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [1,3,5]\n<strong>Output:</strong> 0\n<strong>Explanation:</strong> nums is already sorted therefore, the answer is 0.</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums = [2,1,4]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> It&#39;s impossible to sort the array using right shifts.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 100</code></li>\n\t<li><code>nums</code> contains distinct integers.</li>\n</ul>\n",
            "translatedTitle": "使数组成为递增数组的最少右移次数",
            "translatedContent": "<p>给你一个长度为 <code>n</code>&nbsp;下标从 <strong>0</strong>&nbsp;开始的数组&nbsp;<code>nums</code>&nbsp;，数组中的元素为&nbsp;<strong>互不相同</strong>&nbsp;的正整数。请你返回让 <code>nums</code>&nbsp;成为递增数组的 <strong>最少右移</strong>&nbsp;次数，如果无法得到递增数组，返回 <code>-1</code>&nbsp;。</p>\n\n<p>一次 <strong>右移</strong>&nbsp;指的是同时对所有下标进行操作，将下标为 <code>i</code>&nbsp;的元素移动到下标&nbsp;<code>(i + 1) % n</code>&nbsp;处。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [3,4,5,1,2]\n<b>输出：</b>2\n<b>解释：</b>\n第一次右移后，nums = [2,3,4,5,1] 。\n第二次右移后，nums = [1,2,3,4,5] 。\n现在 nums 是递增数组了，所以答案为 2 。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [1,3,5]\n<b>输出：</b>0\n<b>解释：</b>nums 已经是递增数组了，所以答案为 0 。</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>nums = [2,1,4]\n<b>输出：</b>-1\n<b>解释：</b>无法将数组变为递增数组。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= nums.length &lt;= 100</code></li>\n\t<li><code>1 &lt;= nums[i] &lt;= 100</code></li>\n\t<li><code>nums</code>&nbsp;中的整数互不相同。</li>\n</ul>\n",
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