leetcode-problemset/leetcode-cn/originData/minimum-operations-to-maximize-last-elements-in-arrays.json

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            "title": "Minimum Operations to Maximize Last Elements in Arrays",
            "titleSlug": "minimum-operations-to-maximize-last-elements-in-arrays",
            "content": "<p>You are given two <strong>0-indexed</strong> integer arrays, <code>nums1</code> and <code>nums2</code>, both having length <code>n</code>.</p>\n\n<p>You are allowed to perform a series of <strong>operations</strong> (<strong>possibly none</strong>).</p>\n\n<p>In an operation, you select an index <code>i</code> in the range <code>[0, n - 1]</code> and <strong>swap</strong> the values of <code>nums1[i]</code> and <code>nums2[i]</code>.</p>\n\n<p>Your task is to find the <strong>minimum</strong> number of operations required to satisfy the following conditions:</p>\n\n<ul>\n\t<li><code>nums1[n - 1]</code> is equal to the <strong>maximum value</strong> among all elements of <code>nums1</code>, i.e., <code>nums1[n - 1] = max(nums1[0], nums1[1], ..., nums1[n - 1])</code>.</li>\n\t<li><code>nums2[n - 1]</code> is equal to the <strong>maximum</strong> <strong>value</strong> among all elements of <code>nums2</code>, i.e., <code>nums2[n - 1] = max(nums2[0], nums2[1], ..., nums2[n - 1])</code>.</li>\n</ul>\n\n<p>Return <em>an integer denoting the <strong>minimum</strong> number of operations needed to meet <strong>both</strong> conditions</em>, <em>or </em><code>-1</code><em> if it is <strong>impossible</strong> to satisfy both conditions.</em></p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,2,7], nums2 = [4,5,3]\n<strong>Output:</strong> 1\n<strong>Explanation:</strong> In this example, an operation can be performed using index i = 2.\nWhen nums1[2] and nums2[2] are swapped, nums1 becomes [1,2,3] and nums2 becomes [4,5,7].\nBoth conditions are now satisfied.\nIt can be shown that the minimum number of operations needed to be performed is 1.\nSo, the answer is 1.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [2,3,4,5,9], nums2 = [8,8,4,4,4]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> In this example, the following operations can be performed:\nFirst operation using index i = 4.\nWhen nums1[4] and nums2[4] are swapped, nums1 becomes [2,3,4,5,4], and nums2 becomes [8,8,4,4,9].\nAnother operation using index i = 3.\nWhen nums1[3] and nums2[3] are swapped, nums1 becomes [2,3,4,4,4], and nums2 becomes [8,8,4,5,9].\nBoth conditions are now satisfied.\nIt can be shown that the minimum number of operations needed to be performed is 2.\nSo, the answer is 2.   \n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,5,4], nums2 = [2,5,3]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> In this example, it is not possible to satisfy both conditions. \nSo, the answer is -1.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums1.length == nums2.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums1[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= nums2[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "最大化数组末位元素的最少操作次数",
            "translatedContent": "<p>给你两个下标从 <strong>0</strong> 开始的整数数组 <code>nums1</code> 和 <code>nums2</code> ，这两个数组的长度都是 <code>n</code> 。</p>\n\n<p>你可以执行一系列<strong> 操作（可能不执行）</strong>。</p>\n\n<p>在每次操作中，你可以选择一个在范围 <code>[0, n - 1]</code> 内的下标 <code>i</code> ，并交换 <code>nums1[i]</code> 和 <code>nums2[i]</code> 的值。</p>\n\n<p>你的任务是找到满足以下条件所需的 <strong>最小</strong> 操作次数：</p>\n\n<ul>\n\t<li><code>nums1[n - 1]</code> 等于 <code>nums1</code> 中所有元素的 <strong>最大值</strong> ，即 <code>nums1[n - 1] = max(nums1[0], nums1[1], ..., nums1[n - 1])</code> 。</li>\n\t<li><code>nums2[n - 1]</code> 等于 <code>nums2</code> 中所有元素的 <strong>最大值</strong> ，即 <code>nums2[n - 1] = max(nums2[0], nums2[1], ..., nums2[n - 1])</code> 。</li>\n</ul>\n\n<p>以整数形式，表示并返回满足上述 <strong>全部</strong> 条件所需的 <strong>最小</strong> 操作次数，如果无法同时满足两个条件，则返回 <code>-1</code> 。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [1,2,7]，nums2 = [4,5,3]\n<strong>输出：</strong>1\n<strong>解释：</strong>在这个示例中，可以选择下标 i = 2 执行一次操作。\n交换 nums1[2] 和 nums2[2] 的值，nums1 变为 [1,2,3] ，nums2 变为 [4,5,7] 。\n同时满足两个条件。\n可以证明，需要执行的最小操作次数为 1 。\n因此，答案是 1 。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [2,3,4,5,9]，nums2 = [8,8,4,4,4]\n<strong>输出：</strong>2\n<strong>解释：</strong>在这个示例中，可以执行以下操作：\n首先，选择下标 i = 4 执行操作。\n交换 nums1[4] 和 nums2[4] 的值，nums1 变为 [2,3,4,5,4] ，nums2 变为 [8,8,4,4,9] 。\n然后，选择下标 i = 3 执行操作。\n交换 nums1[3] 和 nums2[3] 的值，nums1 变为 [2,3,4,4,4] ，nums2 变为 [8,8,4,5,9] 。\n同时满足两个条件。 \n可以证明，需要执行的最小操作次数为 2 。 \n因此，答案是 2 。\n</pre>\n\n<p><strong class=\"example\">示例 3：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [1,5,4]，nums2 = [2,5,3]\n<strong>输出：</strong>-1\n<strong>解释：</strong>在这个示例中，无法同时满足两个条件。\n因此，答案是 -1 。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>1 &lt;= n == nums1.length == nums2.length &lt;= 1000</code></li>\n\t<li><code>1 &lt;= nums1[i] &lt;= 10<sup>9</sup></code></li>\n\t<li><code>1 &lt;= nums2[i] &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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                "Consider how to calculate the minimum number of operations when <code>nums1[n - 1]</code> and <code>nums2[n - 1]</code> are fixed (they are not swapped).",
                "For each index <code>i</code>, there are only <code>3</code> possibilities: <ul>\r\n<li><code>nums1[i] <= nums1[n - 1] && nums2[i] <= nums2[n - 1]</code>. We don't need to swap them.</li>\r\n<li><code>nums1[i] <= nums2[n - 1] && nums2[i] <= nums1[n - 1]</code>. We have to swap them.</li>\r\n<li>Otherwise, there is no solution.</li>\r\n</ul>",
                "There are <code>2</code> cases to determine the minimum number of operations: <ul>\r\n<li>The first case is the number of indices that need to be swapped when <code>nums1[n - 1]</code> and <code>nums2[n - 1]</code> are fixed.</li>\r\n<li>The second case is <code>1 +</code> the number of indices that need to be swapped when <code>nums1[n - 1]</code> and <code>nums2[n - 1]</code> are swapped.</li>\r\n</ul>",
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href=\\\"https:\\/\\/github.com\\/emirpasic\\/gods\\/tree\\/v1.18.1\\\" target=\\\"_blank\\\">https:\\/\\/godoc.org\\/github.com\\/emirpasic\\/gods@v1.18.1<\\/a> \\u7b2c\\u4e09\\u65b9\\u5e93\\u3002<\\/p>\"],\"python3\":[\"Python3\",\"<p>\\u7248\\u672c\\uff1a<code>Python 3.10<\\/code><\\/p>\\r\\n\\r\\n<p>\\u4e3a\\u4e86\\u65b9\\u4fbf\\u8d77\\u89c1\\uff0c\\u5927\\u90e8\\u5206\\u5e38\\u7528\\u5e93\\u5df2\\u7ecf\\u88ab\\u81ea\\u52a8 \\u5bfc\\u5165\\uff0c\\u5982<a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/array.html\\\" target=\\\"_blank\\\">array<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/bisect.html\\\" target=\\\"_blank\\\">bisect<\\/a>, <a href=\\\"https:\\/\\/docs.python.org\\/3\\/library\\/collections.html\\\" target=\\\"_blank\\\">collections<\\/a>\\u3002 \\u5982\\u679c\\u60a8\\u9700\\u8981\\u4f7f\\u7528\\u5176\\u4ed6\\u5e93\\u51fd\\u6570\\uff0c\\u8bf7\\u81ea\\u884c\\u5bfc\\u5165\\u3002<\\/p>\\r\\n\\r\\n<p>\\u5982\\u9700\\u4f7f\\u7528 Map\\/TreeMap 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