leetcode-problemset/leetcode-cn/originData/minimum-domino-rotations-for-equal-row.json

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            "title": "Minimum Domino Rotations For Equal Row",
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            "content": "<p>In a row of dominoes, <code>tops[i]</code> and <code>bottoms[i]</code> represent the top and bottom halves of the <code>i<sup>th</sup></code> domino. (A domino is a tile with two numbers from 1 to 6 - one on each half of the tile.)</p>\n\n<p>We may rotate the <code>i<sup>th</sup></code> domino, so that <code>tops[i]</code> and <code>bottoms[i]</code> swap values.</p>\n\n<p>Return the minimum number of rotations so that all the values in <code>tops</code> are the same, or all the values in <code>bottoms</code> are the same.</p>\n\n<p>If it cannot be done, return <code>-1</code>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/14/domino.png\" style=\"height: 300px; width: 421px;\" />\n<pre>\n<strong>Input:</strong> tops = [2,1,2,4,2,2], bottoms = [5,2,6,2,3,2]\n<strong>Output:</strong> 2\n<strong>Explanation:</strong> \nThe first figure represents the dominoes as given by tops and bottoms: before we do any rotations.\nIf we rotate the second and fourth dominoes, we can make every value in the top row equal to 2, as indicated by the second figure.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> tops = [3,5,1,2,3], bottoms = [3,6,3,3,4]\n<strong>Output:</strong> -1\n<strong>Explanation:</strong> \nIn this case, it is not possible to rotate the dominoes to make one row of values equal.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= tops.length &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>bottoms.length == tops.length</code></li>\n\t<li><code>1 &lt;= tops[i], bottoms[i] &lt;= 6</code></li>\n</ul>\n",
            "translatedTitle": "行相等的最少多米诺旋转",
            "translatedContent": "<p>在一排多米诺骨牌中，<code>tops[i]</code> 和 <code>bottoms[i]</code>&nbsp;分别代表第 <code>i</code> 个多米诺骨牌的上半部分和下半部分。（一个多米诺是两个从 1 到 6 的数字同列平铺形成的&nbsp;—— 该平铺的每一半上都有一个数字。）</p>\n\n<p>我们可以旋转第&nbsp;<code>i</code>&nbsp;张多米诺，使得 <code>tops[i]</code> 和 <code>bottoms[i]</code>&nbsp;的值交换。</p>\n\n<p>返回能使 <code>tops</code> 中所有值或者 <code>bottoms</code> 中所有值都相同的最小旋转次数。</p>\n\n<p>如果无法做到，返回&nbsp;<code>-1</code>.</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/05/14/domino.png\" style=\"height: 300px; width: 421px;\" />\n<pre>\n<strong>输入：</strong>tops = [2,1,2,4,2,2], bottoms = [5,2,6,2,3,2]\n<strong>输出：</strong>2\n<strong>解释：</strong> \n图一表示：在我们旋转之前， tops 和 bottoms 给出的多米诺牌。 \n如果我们旋转第二个和第四个多米诺骨牌，我们可以使上面一行中的每个值都等于 2，如图二所示。 \n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>tops = [3,5,1,2,3], bottoms = [3,6,3,3,4]\n<strong>输出：</strong>-1\n<strong>解释：</strong> 在这种情况下，不可能旋转多米诺牌使一行的值相等。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= tops.length &lt;= 2 * 10<sup>4</sup></code></li>\n\t<li><code>bottoms.length == tops.length</code></li>\n\t<li><code>1 &lt;= tops[i], bottoms[i] &lt;= 6</code></li>\n</ul>\n",
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