leetcode-problemset/leetcode-cn/originData/minimum-absolute-sum-difference.json

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            "title": "Minimum Absolute Sum Difference",
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            "content": "<p>You are given two positive integer arrays <code>nums1</code> and <code>nums2</code>, both of length <code>n</code>.</p>\n\n<p>The <strong>absolute sum difference</strong> of arrays <code>nums1</code> and <code>nums2</code> is defined as the <strong>sum</strong> of <code>|nums1[i] - nums2[i]|</code> for each <code>0 &lt;= i &lt; n</code> (<strong>0-indexed</strong>).</p>\n\n<p>You can replace <strong>at most one</strong> element of <code>nums1</code> with <strong>any</strong> other element in <code>nums1</code> to <strong>minimize</strong> the absolute sum difference.</p>\n\n<p>Return the <em>minimum absolute sum difference <strong>after</strong> replacing at most one<strong> </strong>element in the array <code>nums1</code>.</em> Since the answer may be large, return it <strong>modulo</strong> <code>10<sup>9</sup> + 7</code>.</p>\n\n<p><code>|x|</code> is defined as:</p>\n\n<ul>\n\t<li><code>x</code> if <code>x &gt;= 0</code>, or</li>\n\t<li><code>-x</code> if <code>x &lt; 0</code>.</li>\n</ul>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,7,5], nums2 = [2,3,5]\n<strong>Output:</strong> 3\n<strong>Explanation: </strong>There are two possible optimal solutions:\n- Replace the second element with the first: [1,<u><strong>7</strong></u>,5] =&gt; [1,<u><strong>1</strong></u>,5], or\n- Replace the second element with the third: [1,<u><strong>7</strong></u>,5] =&gt; [1,<u><strong>5</strong></u>,5].\nBoth will yield an absolute sum difference of <code>|1-2| + (|1-3| or |5-3|) + |5-5| = </code>3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [2,4,6,8,10], nums2 = [2,4,6,8,10]\n<strong>Output:</strong> 0\n<strong>Explanation: </strong>nums1 is equal to nums2 so no replacement is needed. This will result in an \nabsolute sum difference of 0.\n</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> nums1 = [1,10,4,4,2,7], nums2 = [9,3,5,1,7,4]\n<strong>Output:</strong> 20\n<strong>Explanation: </strong>Replace the first element with the second: [<u><strong>1</strong></u>,10,4,4,2,7] =&gt; [<u><strong>10</strong></u>,10,4,4,2,7].\nThis yields an absolute sum difference of <code>|10-9| + |10-3| + |4-5| + |4-1| + |2-7| + |7-4| = 20</code>\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>n == nums1.length</code></li>\n\t<li><code>n == nums2.length</code></li>\n\t<li><code>1 &lt;= n &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= nums1[i], nums2[i] &lt;= 10<sup>5</sup></code></li>\n</ul>\n",
            "translatedTitle": "绝对差值和",
            "translatedContent": "<p>给你两个正整数数组 <code>nums1</code> 和 <code>nums2</code> ，数组的长度都是 <code>n</code> 。</p>\n\n<p>数组 <code>nums1</code> 和 <code>nums2</code> 的 <strong>绝对差值和</strong> 定义为所有 <code>|nums1[i] - nums2[i]|</code>（<code>0 <= i < n</code>）的 <strong>总和</strong>（<strong>下标从 0 开始</strong>）。</p>\n\n<p>你可以选用 <code>nums1</code> 中的 <strong>任意一个</strong> 元素来替换 <code>nums1</code> 中的 <strong>至多</strong> 一个元素，以 <strong>最小化</strong> 绝对差值和。</p>\n\n<p>在替换数组 <code>nums1</code> 中最多一个元素 <strong>之后</strong> ，返回最小绝对差值和。因为答案可能很大，所以需要对 <code>10<sup>9</sup> + 7</code> <strong>取余 </strong>后返回。</p>\n\n<p><code>|x|</code> 定义为：</p>\n\n<ul>\n\t<li>如果 <code>x >= 0</code> ，值为 <code>x</code> ，或者</li>\n\t<li>如果 <code>x <= 0</code> ，值为 <code>-x</code></li>\n</ul>\n\n<p> </p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [1,7,5], nums2 = [2,3,5]\n<strong>输出：</strong>3\n<strong>解释：</strong>有两种可能的最优方案：\n- 将第二个元素替换为第一个元素：[1,<strong>7</strong>,5] => [1,<strong>1</strong>,5] ，或者\n- 将第二个元素替换为第三个元素：[1,<strong>7</strong>,5] => [1,<strong>5</strong>,5]\n两种方案的绝对差值和都是 <code>|1-2| + (|1-3| 或者 |5-3|) + |5-5| = </code>3\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [2,4,6,8,10], nums2 = [2,4,6,8,10]\n<strong>输出：</strong>0\n<strong>解释：</strong>nums1 和 nums2 相等，所以不用替换元素。绝对差值和为 0\n</pre>\n\n<p><strong>示例 3</strong><strong>：</strong></p>\n\n<pre>\n<strong>输入：</strong>nums1 = [1,10,4,4,2,7], nums2 = [9,3,5,1,7,4]\n<strong>输出：</strong>20\n<strong>解释：</strong>将第一个元素替换为第二个元素：[<strong>1</strong>,10,4,4,2,7] => [<strong>10</strong>,10,4,4,2,7]\n绝对差值和为 <code>|10-9| + |10-3| + |4-5| + |4-1| + |2-7| + |7-4| = 20</code>\n</pre>\n\n<p> </p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>n == nums1.length</code></li>\n\t<li><code>n == nums2.length</code></li>\n\t<li><code>1 <= n <= 10<sup>5</sup></code></li>\n\t<li><code>1 <= nums1[i], nums2[i] <= 10<sup>5</sup></code></li>\n</ul>\n",
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