leetcode-problemset/leetcode-cn/originData/minimize-the-maximum-of-two-arrays.json

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            "title": "Minimize the Maximum of Two Arrays",
            "titleSlug": "minimize-the-maximum-of-two-arrays",
            "content": "<p>We have two arrays <code>arr1</code> and <code>arr2</code> which are initially empty. You need to add positive integers to them such that they satisfy all the following conditions:</p>\n\n<ul>\n\t<li><code>arr1</code> contains <code>uniqueCnt1</code> <strong>distinct</strong> positive integers, each of which is <strong>not divisible</strong> by <code>divisor1</code>.</li>\n\t<li><code>arr2</code> contains <code>uniqueCnt2</code> <strong>distinct</strong> positive integers, each of which is <strong>not divisible</strong> by <code>divisor2</code>.</li>\n\t<li><strong>No</strong> integer is present in both <code>arr1</code> and <code>arr2</code>.</li>\n</ul>\n\n<p>Given <code>divisor1</code>, <code>divisor2</code>, <code>uniqueCnt1</code>, and <code>uniqueCnt2</code>, return <em>the <strong>minimum possible maximum</strong> integer that can be present in either array</em>.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n\n<pre>\n<strong>Input:</strong> divisor1 = 2, divisor2 = 7, uniqueCnt1 = 1, uniqueCnt2 = 3\n<strong>Output:</strong> 4\n<strong>Explanation:</strong> \nWe can distribute the first 4 natural numbers into arr1 and arr2.\narr1 = [1] and arr2 = [2,3,4].\nWe can see that both arrays satisfy all the conditions.\nSince the maximum value is 4, we return it.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n\n<pre>\n<strong>Input:</strong> divisor1 = 3, divisor2 = 5, uniqueCnt1 = 2, uniqueCnt2 = 1\n<strong>Output:</strong> 3\n<strong>Explanation:</strong> \nHere arr1 = [1,2], and arr2 = [3] satisfy all conditions.\nSince the maximum value is 3, we return it.</pre>\n\n<p><strong class=\"example\">Example 3:</strong></p>\n\n<pre>\n<strong>Input:</strong> divisor1 = 2, divisor2 = 4, uniqueCnt1 = 8, uniqueCnt2 = 2\n<strong>Output:</strong> 15\n<strong>Explanation:</strong> \nHere, the final possible arrays can be arr1 = [1,3,5,7,9,11,13,15], and arr2 = [2,6].\nIt can be shown that it is not possible to obtain a lower maximum satisfying all conditions. \n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= divisor1, divisor2 &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= uniqueCnt1, uniqueCnt2 &lt; 10<sup>9</sup></code></li>\n\t<li><code>2 &lt;= uniqueCnt1 + uniqueCnt2 &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
            "translatedTitle": "最小化两个数组中的最大值",
            "translatedContent": "<p>给你两个数组&nbsp;<code>arr1</code> 和&nbsp;<code>arr2</code>&nbsp;，它们一开始都是空的。你需要往它们中添加正整数，使它们满足以下条件：</p>\n\n<ul>\n\t<li><code>arr1</code>&nbsp;包含&nbsp;<code>uniqueCnt1</code>&nbsp;个<strong>&nbsp;互不相同</strong>&nbsp;的正整数，每个整数都&nbsp;<strong>不能 </strong>被&nbsp;<code>divisor1</code>&nbsp;<strong>整除</strong>&nbsp;。</li>\n\t<li><code>arr2</code>&nbsp;包含&nbsp;<code>uniqueCnt2</code>&nbsp;个<strong>&nbsp;互不相同</strong>&nbsp;的正整数，每个整数都&nbsp;<strong>不能</strong>&nbsp;被&nbsp;<code>divisor2</code>&nbsp;<strong>整除</strong>&nbsp;。</li>\n\t<li><code>arr1</code> 和&nbsp;<code>arr2</code>&nbsp;中的元素&nbsp;<strong>互不相同</strong>&nbsp;。</li>\n</ul>\n\n<p>给你&nbsp;<code>divisor1</code>&nbsp;，<code>divisor2</code>&nbsp;，<code>uniqueCnt1</code>&nbsp;和&nbsp;<code>uniqueCnt2</code>&nbsp;，请你返回两个数组中&nbsp;<strong>最大元素</strong>&nbsp;的&nbsp;<strong>最小值</strong>&nbsp;。</p>\n\n<p>&nbsp;</p>\n\n<p><strong>示例 1：</strong></p>\n\n<pre>\n<b>输入：</b>divisor1 = 2, divisor2 = 7, uniqueCnt1 = 1, uniqueCnt2 = 3\n<b>输出：</b>4\n<b>解释：</b>\n我们可以把前 4 个自然数划分到 arr1 和 arr2 中。\narr1 = [1] 和 arr2 = [2,3,4] 。\n可以看出两个数组都满足条件。\n最大值是 4 ，所以返回 4 。\n</pre>\n\n<p><strong>示例 2：</strong></p>\n\n<pre>\n<b>输入：</b>divisor1 = 3, divisor2 = 5, uniqueCnt1 = 2, uniqueCnt2 = 1\n<b>输出：</b>3\n<b>解释：</b>\narr1 = [1,2] 和 arr2 = [3] 满足所有条件。\n最大值是 3 ，所以返回 3 。</pre>\n\n<p><strong>示例 3：</strong></p>\n\n<pre>\n<b>输入：</b>divisor1 = 2, divisor2 = 4, uniqueCnt1 = 8, uniqueCnt2 = 2\n<b>输出：</b>15\n<b>解释：</b>\n最终数组为 arr1 = [1,3,5,7,9,11,13,15] 和 arr2 = [2,6] 。\n上述方案是满足所有条件的最优解。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li><code>2 &lt;= divisor1, divisor2 &lt;= 10<sup>5</sup></code></li>\n\t<li><code>1 &lt;= uniqueCnt1, uniqueCnt2 &lt; 10<sup>9</sup></code></li>\n\t<li><code>2 &lt;= uniqueCnt1 + uniqueCnt2 &lt;= 10<sup>9</sup></code></li>\n</ul>\n",
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