leetcode-problemset/leetcode-cn/originData/middle-of-the-linked-list.json

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            "questionId": "908",
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            "categoryTitle": "Algorithms",
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            "title": "Middle of the Linked List",
            "titleSlug": "middle-of-the-linked-list",
            "content": "<p>Given the <code>head</code> of a singly linked list, return <em>the middle node of the linked list</em>.</p>\n\n<p>If there are two middle nodes, return <strong>the second middle</strong> node.</p>\n\n<p>&nbsp;</p>\n<p><strong class=\"example\">Example 1:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/23/lc-midlist1.jpg\" style=\"width: 544px; height: 65px;\" />\n<pre>\n<strong>Input:</strong> head = [1,2,3,4,5]\n<strong>Output:</strong> [3,4,5]\n<strong>Explanation:</strong> The middle node of the list is node 3.\n</pre>\n\n<p><strong class=\"example\">Example 2:</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/23/lc-midlist2.jpg\" style=\"width: 664px; height: 65px;\" />\n<pre>\n<strong>Input:</strong> head = [1,2,3,4,5,6]\n<strong>Output:</strong> [4,5,6]\n<strong>Explanation:</strong> Since the list has two middle nodes with values 3 and 4, we return the second one.\n</pre>\n\n<p>&nbsp;</p>\n<p><strong>Constraints:</strong></p>\n\n<ul>\n\t<li>The number of nodes in the list is in the range <code>[1, 100]</code>.</li>\n\t<li><code>1 &lt;= Node.val &lt;= 100</code></li>\n</ul>\n",
            "translatedTitle": "链表的中间结点",
            "translatedContent": "<p>给你单链表的头结点 <code>head</code> ，请你找出并返回链表的中间结点。</p>\n\n<p>如果有两个中间结点，则返回第二个中间结点。</p>\n\n<p>&nbsp;</p>\n\n<p><strong class=\"example\">示例 1：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/23/lc-midlist1.jpg\" style=\"width: 544px; height: 65px;\" />\n<pre>\n<strong>输入：</strong>head = [1,2,3,4,5]\n<strong>输出：</strong>[3,4,5]\n<strong>解释：</strong>链表只有一个中间结点，值为 3 。\n</pre>\n\n<p><strong class=\"example\">示例 2：</strong></p>\n<img alt=\"\" src=\"https://assets.leetcode.com/uploads/2021/07/23/lc-midlist2.jpg\" style=\"width: 664px; height: 65px;\" />\n<pre>\n<strong>输入：</strong>head = [1,2,3,4,5,6]\n<strong>输出：</strong>[4,5,6]\n<strong>解释：</strong>该链表有两个中间结点，值分别为 3 和 4 ，返回第二个结点。\n</pre>\n\n<p>&nbsp;</p>\n\n<p><strong>提示：</strong></p>\n\n<ul>\n\t<li>链表的结点数范围是 <code>[1, 100]</code></li>\n\t<li><code>1 &lt;= Node.val &lt;= 100</code></li>\n</ul>\n",
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                    "name": "Linked List",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     int val;\n *     ListNode next;\n *     ListNode() {}\n *     ListNode(int val) { this.val = val; }\n *     ListNode(int val, ListNode next) { this.val = val; this.next = next; }\n * }\n */\nclass Solution {\n    public ListNode middleNode(ListNode head) {\n\n    }\n}",
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                    "code": "# Definition for singly-linked list.\n# class ListNode(object):\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution(object):\n    def middleNode(self, head):\n        \"\"\"\n        :type head: ListNode\n        :rtype: ListNode\n        \"\"\"\n        ",
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                    "code": "# Definition for singly-linked list.\n# class ListNode:\n#     def __init__(self, val=0, next=None):\n#         self.val = val\n#         self.next = next\nclass Solution:\n    def middleNode(self, head: Optional[ListNode]) -> Optional[ListNode]:",
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                    "code": "/**\n * Definition for singly-linked list.\n * struct ListNode {\n *     int val;\n *     struct ListNode *next;\n * };\n */\nstruct ListNode* middleNode(struct ListNode* head) {\n    \n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * public class ListNode {\n *     public int val;\n *     public ListNode next;\n *     public ListNode(int val=0, ListNode next=null) {\n *         this.val = val;\n *         this.next = next;\n *     }\n * }\n */\npublic class Solution {\n    public ListNode MiddleNode(ListNode head) {\n\n    }\n}",
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                    "code": "/**\n * Definition for singly-linked list.\n * function ListNode(val, next) {\n *     this.val = (val===undefined ? 0 : val)\n *     this.next = (next===undefined ? null : next)\n * }\n */\n/**\n * @param {ListNode} head\n * @return {ListNode}\n */\nvar middleNode = function(head) {\n\n};",
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                    "code": "/**\n * Definition for singly-linked list.\n * class ListNode {\n *     val: number\n *     next: ListNode | null\n *     constructor(val?: number, next?: ListNode | null) {\n *         this.val = (val===undefined ? 0 : val)\n *         this.next = (next===undefined ? null : next)\n *     }\n * }\n */\n\nfunction middleNode(head: ListNode | null): ListNode | null {\n    \n};",
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